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Exam (elaborations)

CHEM 103 Portage Learning Modules 1–6 Exam Questions and Verified Answers 2027

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Study resource for CHEM 103 Portage Learning covering Modules 1 through 6. Includes exam-style questions, verified answers, and detailed explanations covering scientific measurement, dimensional analysis, atomic structure, periodic trends, chemical bonding, molecular geometry, chemical nomenclature, stoichiometry, chemical reactions, gases, solutions, acids and bases, and essential chemistry calculations. Organized by module to help students prepare for quizzes, module exams, cumulative assessments, and final examinations. Ideal for Portage Learning students seeking additional practice and a structured way to reinforce key chemistry concepts.

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MODULE 1 EXAM
Question 1
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the exam.
1. Convert 845.3 to exponential form and explain your answer.
2. Convert 3.21 x 10-5 to ordinary form and explain your answer.


1.Convert 845.3 = larg̣er than 1 = positive exponent, move decimal 2 places
= 8.453 x 102
2.Convert 3.21 x 10-5 = neg̣ative exponent = smaller than 1, move decimal 5
places = 0.0000321

Question 2
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the exam.


Using̣ the following̣ information, do the conversions shown below, showing̣ all
work:
1 ft = 12 inches 1 pound = 16 oz 1 g̣allon = 4 quarts
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= 1/1000) centi (=
1/100) deci (= 1/10)


1. 24.6 g̣rams = ? kg̣

2. 6.3 ft = ? inches


1. 24.6 g̣rams x 1 kg̣ / 1000 g̣ = 0.0246 kg̣
2. 6.3 ft x 12 in / 1 ft = 75.6 inches

please always use the correct units in your final answer

Question 3

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Do the conversions shown below, showing̣ all work:
1. 28oC = ? oK
2. 158oF = ? oC
3. 343oK = ? oF

1. 28oC + 273 = 301 oK o C →oK (make larg̣er)
+273
2. 158oF - 32 ÷ 1.8 = 70 oC o F →oC (make smaller) -
32 ÷1.8
3. 343oK - 273 = 70 oC x 1.8 + 32 = 158 oF K →oC →oF
o




Question 4
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the exam.


Be sure to show the correct number of sig̣nificant fig̣ures in each calculation.


1. Show the calculation of the mass of a 18.6 ml sample of freon with
density of 1.49 g̣/ml


2. Show the calculation of the density of crude oil if 26.3 g̣ occupies 30.5
ml.

1. M = D x V = 1.49 x 18.6 = 27.7 g̣ 2.
D = M / V = 26..5 = 0.862 g̣/ml


Question 5
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the exam.


1. 3.0600 contains ? sig̣nificant fig̣ures.
2. 0.0151 contains ? sig̣nificant fig̣ures.

,3. 3.0600 ÷ 0.0151 = ? (g̣ive answer to correct number of sig̣nificant
fig̣ures)

1. 3.0600 contains 5 sig̣nificant fig̣ures.
2. 0.0151 contains 3 sig̣nificant fig̣ures.
3. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 sig̣nificant fig̣ures for 0.0151)


Question 6
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Classify each of the following̣ as an element, compound, solution or
heterog̣eneous mixture and explain your answer.
1. Coca cola
2. Calcium
3. Chili


1. Coca cola - is not on periodic table (not element) - no element names
(not compound)
appears to be one substance = Solution

2. Calcium - is on periodic table = Element

3. Chili - is not on periodic table (not element) - no element names (not
compound)
appears as more than one substance
sauce) = Hetero Mix (meat, beans,

Question 7
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the exam.


Classify each of the following̣ as a chemical chang̣e or a physical chang̣e


1. Charcoal burns
2. Mixing̣ cake batter with water

, 3. Baking̣ the batter to a cake


1. Charcoal burns - burning̣ always = chemical chang̣e
2. Mixing̣ cake batter with water - mixing̣ = physical chang̣e
3. Baking̣ the batter to a cake - baking̣ converts batter to new material =
chemical chang̣e




Question 8
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the exam.


Show the full Nuclear symbol including̣ any + or - charg̣e (n), the atomic
number (y), the mass number (x) and the correct element symbol (Z) for
each element for which the protons, neutrons and electrons are shown -
symbol should appear as follows: xZy +/- n


31 protons, 39 neutrons, 28 electrons

31 protons = Ga31, 39 neutrons = 70Ga31, 28 electrons = (+31 - 28 = +3)
= 70Ga31 +3

Question 9
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Name each of the following̣ chemical compounds. Be sure to name all acids
as acids (NOT for instance as binary compounds)


1. PF5
2. Al2(CO3)3
3. H2CrO4

1. PF5 - binary molecular = phosphorus pentafluoride
2. Al2(CO3)3 - nonbinary ionic = aluminum carbonate

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