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, TABLE OF CONTENTS
Solutions Manual: Categorical and Nonparametric Data Analysis:
Choosing the Best Statistical Technique, 1st Edition
Author: E. Michael Nussbaum
ST
Chapter 1. Levels of Measurement, Probability, and the Binomial Formula
UV
Chapter 2. Estimation and Hypothesis Testing
Chapter 3. Random Variables and Probability Distributions
Chapter 4. Contingency Tables: The Chi-Square Test and Associated Effect Sizes
IA
Chapter 5. Contingency Tables: Special Situations
Chapter 6. Basic Nonparametric Tests for Ordinal Data
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Chapter 7. Nonparametric Tests for Multiple or Related Samples
Chapter 8. Advanced Rank Tests (For Interactions and Robust ANOVA)
Chapter 9. Linear Regression and Generalized Linear Models
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Chapter 10. Binary Logistic Regression
Chapter 11. Multinomial Logistic, Ordinal, and Poisson Regression
Chapter 12. Log-Linear Analysis
PR
Chapter 13. General Estimating Equations
Chapter 14. Estimation Procedures
Chapter 15. Choosing the Best Statistical Technique
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ED
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, Answers to Even Numbered Problems
Chapter 1 - Levels of Measurement, Probability, and the Binomial Formula
2. (a) ordinal. (b) metric (ratio). (c) nominal. (d) ordinal (ordered categories).
ST
1
∗1 2
4. (a) 6 6 . (b) 16.7 16.7 −16.7 30.6 .
16.7
6
UV
3
6. 25 1.6
4!
8. 4
1
=
1 ! 4−1 !
4.
4!
10. 4
2
=
2 ! 4−2 !
6
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4! 2
12. ∗.752∗1−.75 .21 .
2 ! 4−2 !
14. =BINOM.DIST(2,4,0.75,1) 26.2%.
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16.
45.0%
40.0%
35.0%
AP
30.0%
Probability
25.0%
20.0%
PR
15.0%
10.0%
5.0%
0.0%
OV
0 1 2 3 4
Hits
44.5− 60 .5
18. z 3.74 , p = .009%.
√ 60 .5 1−.5
ED
©Instructor Web Resource Material Created by E. Michael Nussbaum to accompany Nussbaum:
Categorical and Nonparametric Data Analysis, 2015, Routledge/Taylor & Francis.
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, Answers to Even Numbered Problems
Chapter 2 - Estimation and Hypothesis Testing
ST
2. Reject null hypothesis of π .80 (z = -4.125, p < .001, SPSS reports the one-sided
asymptotic value). 9.5
4. X = 9.5 with continuity correction. P .3654 . For one-tailed test, H : = .6525; H :
UV
0 a
26
< .6525. SE
√ .3654∗1−.3654
.094 . z
.3654−.6525
.094
−3.04 . Prob(z
IA
26
≤ - 3.04) = .001 So one-tailed p = .001. Because the normal distribution is symmetrical,
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double the one-tailed value, yielding p = .002 (two-tailed).
6. T = 7, n = 9 (with tie omitted), H0: Prob(+) = .50; Ha: Prob(+) ≠ .50. p = .09 (one-tailed), p =
.18 (two-tailed). (In EXCEL, =1-BINOM.DIST(6, 9, .50, 1) .09. We fail to reject the null
AP
hypothesis of no trend.
8. T = 6, n = 6, H0: Prob(+) = .50; Ha: Prob(+) ≠ .50. p = .016 (one-tailed), p = .03 (two-tailed).
(In EXCEL, =1-BINOM.DIST(5, 6, .50, 1) .016.) The association is significant.
PR
©Instructor Web Resource Material Created by E. Michael Nussbaum to accompany Nussbaum:
Categorical and Nonparametric Data Analysis, 2015, Routledge/Taylor & Francis.
OV
ED
??
ED
OV
PR
AP
?_
IA
UV
ST
, TABLE OF CONTENTS
Solutions Manual: Categorical and Nonparametric Data Analysis:
Choosing the Best Statistical Technique, 1st Edition
Author: E. Michael Nussbaum
ST
Chapter 1. Levels of Measurement, Probability, and the Binomial Formula
UV
Chapter 2. Estimation and Hypothesis Testing
Chapter 3. Random Variables and Probability Distributions
Chapter 4. Contingency Tables: The Chi-Square Test and Associated Effect Sizes
IA
Chapter 5. Contingency Tables: Special Situations
Chapter 6. Basic Nonparametric Tests for Ordinal Data
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Chapter 7. Nonparametric Tests for Multiple or Related Samples
Chapter 8. Advanced Rank Tests (For Interactions and Robust ANOVA)
Chapter 9. Linear Regression and Generalized Linear Models
AP
Chapter 10. Binary Logistic Regression
Chapter 11. Multinomial Logistic, Ordinal, and Poisson Regression
Chapter 12. Log-Linear Analysis
PR
Chapter 13. General Estimating Equations
Chapter 14. Estimation Procedures
Chapter 15. Choosing the Best Statistical Technique
OV
ED
? ?
, Answers to Even Numbered Problems
Chapter 1 - Levels of Measurement, Probability, and the Binomial Formula
2. (a) ordinal. (b) metric (ratio). (c) nominal. (d) ordinal (ordered categories).
ST
1
∗1 2
4. (a) 6 6 . (b) 16.7 16.7 −16.7 30.6 .
16.7
6
UV
3
6. 25 1.6
4!
8. 4
1
=
1 ! 4−1 !
4.
4!
10. 4
2
=
2 ! 4−2 !
6
IA
4! 2
12. ∗.752∗1−.75 .21 .
2 ! 4−2 !
14. =BINOM.DIST(2,4,0.75,1) 26.2%.
?_
16.
45.0%
40.0%
35.0%
AP
30.0%
Probability
25.0%
20.0%
PR
15.0%
10.0%
5.0%
0.0%
OV
0 1 2 3 4
Hits
44.5− 60 .5
18. z 3.74 , p = .009%.
√ 60 .5 1−.5
ED
©Instructor Web Resource Material Created by E. Michael Nussbaum to accompany Nussbaum:
Categorical and Nonparametric Data Analysis, 2015, Routledge/Taylor & Francis.
??
, Answers to Even Numbered Problems
Chapter 2 - Estimation and Hypothesis Testing
ST
2. Reject null hypothesis of π .80 (z = -4.125, p < .001, SPSS reports the one-sided
asymptotic value). 9.5
4. X = 9.5 with continuity correction. P .3654 . For one-tailed test, H : = .6525; H :
UV
0 a
26
< .6525. SE
√ .3654∗1−.3654
.094 . z
.3654−.6525
.094
−3.04 . Prob(z
IA
26
≤ - 3.04) = .001 So one-tailed p = .001. Because the normal distribution is symmetrical,
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double the one-tailed value, yielding p = .002 (two-tailed).
6. T = 7, n = 9 (with tie omitted), H0: Prob(+) = .50; Ha: Prob(+) ≠ .50. p = .09 (one-tailed), p =
.18 (two-tailed). (In EXCEL, =1-BINOM.DIST(6, 9, .50, 1) .09. We fail to reject the null
AP
hypothesis of no trend.
8. T = 6, n = 6, H0: Prob(+) = .50; Ha: Prob(+) ≠ .50. p = .016 (one-tailed), p = .03 (two-tailed).
(In EXCEL, =1-BINOM.DIST(5, 6, .50, 1) .016.) The association is significant.
PR
©Instructor Web Resource Material Created by E. Michael Nussbaum to accompany Nussbaum:
Categorical and Nonparametric Data Analysis, 2015, Routledge/Taylor & Francis.
OV
ED
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