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Solutions Manual for Engineering Mechanics: Statics (14th Edition, 2019) by Hibbeler

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This solutions manual provides detailed, step-by-step answers to all end-of-chapter problems found in Engineering Mechanics: Statics, 14th Edition by R.C. Hibbeler. It covers topics such as equilibrium of particles and rigid bodies, structural analysis, distributed forces, friction, and moments of inertia. The manual is designed to help students deeply understand the logic behind each solution, reinforce conceptual learning, and effectively prepare for exams. Ideal for engineering students using Hibbeler’s textbook in coursework, assignments, or self-study. hibbeler statics solutions, engineering mechanics statics, 14th edition statics, hibbeler statics 14e, statics textbook answers, statics problem solving, mechanical engineering statics, hibbeler solution manual, engineering statics exercises, free body diagram practice, statics chapter solutions, moments and forces, structural analysis statics, equilibrium of rigid bodies, physics statics solutions, statics exam prep, hibbeler solved problems, mechanics study guide

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, 1–1.

Round off the following numbers to three significant
figures: (a) 58 342 m, (b) 68.534 s, (c) 2553 N, and
(d) 7555 kg.


SOLUTION
a) 58.3 km b) 68.5 s c) 2.55 kN d) 7.56 Mg


Ans.

*1–4.

Represent each of the following combinations of units in
the correct SI form using an ap p ropriate prefix: (a) m>ms,
#
(b) mkm, (c) ks>mg, and (d) km mN.




SOLUTION
11023 m
m ≤ = km>s Ans.
a) m>ms = ¢ ≤ = ¢ s
1102 -3

s -611023 m = 1102-3 m =
b) mkm = 1102 Ans.
mm
11023 s 11029 s
1102-6 kg kg




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1–5.
c) ks>mg =
= = Gs>kg

d) km # mN = 10 3
m 10 -6
N = 10 -3
m # N = mm # N

Ans.

R epresent each of the following quantities in the correct
SI form using an appropriate prefix: (a) 0.000 431 kg,
(b) 35.3(103) N, and (c) 0.005 32 km.




SOLUTION
a) 0.000 431 kg = 0.000 431 A 103 B g = 0.431 g Ans.

b) 35.3 A 103 B N = 35.3 kN Ans.

c) 0.005 32 km = 0.005 32 A 103 B m = 5.32 m Ans.




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1–9.

A rocket has a mass of 250(103) slugs on earth. Specify
(a) its mass in SI units and (b) its weight in SI units. If the
rocket is on the moon, where the acceleration due to gravity
is gm = 5.30 ft> s2, determine to three significant figures
(c) its weight in SI units and (d) its mass in SI units.




SOLUTION
Using Table 1–2 and applying Eq. 1–3, we have
14.59 kg
a) 250 A 103 B slugs = C 250 A 103 B slugs D a b
1 slugs

= 3.6475 A 106 B kg

= 3.65 Gg Ans.

b) We = mg = C 3.6475 A 106 B kg D A 9.81 m>s2
B

= 35.792 A 106 B kg # m>s2
Ans.
= 35.8 MN

c) Wm = mgm = C 250 A 103 B slugs D A 5.30
ft>s2 B

4.448 N
= C 1.325 A 106 B lb D a b Ans.
1 lb

= 5.894 A 106 B N = 5.89 MN
Or
gm 5.30 ft>s2




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Connected book
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Russell C. Hibbeler Engineering Mechanics
Publisher: 2015 ISBN: 9780133918922 Edition: Unknown

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