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CHEM 104/ CHEM104 General Chemistry II Module 2 Exam (Latest 2026/2027 Update) | Complete Exam Questions with Verified Answers and Detailed Rationales | Portage Learning

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INSTANT PDF DOWNLOAD – This comprehensive study guide covers the Module 2 Exam for CHEM 104 General Chemistry II at Portage Learning (Latest 2026/2027 Update), featuring verified practice questions with correct answers and detailed rationales. Based on typical general chemistry curricula, this resource covers acid-base chemistry (identifying acids/bases/salts, Brønsted-Lowry theory, weak acids), equilibrium reactions and Le Chatelier’s principle, buffer solutions and the Henderson-Hasselbalch equation, titration calculations, and solubility product constants (Ksp). Includes practice problems with step-by-step solutions. Key Topics & Practice Q&A Question 1: Identify each of the compounds below as ACID, BASE or SALT on the basis of their formula and explain your answer. (1) Cr(OH)₃ (2) HAsO₄ (3) CoCO₃ Answer: (1) BASE – contains Cr metal + OH polyatomic group; (2) ACID – contains H + polyatomic group (AsO₄); (3) SALT – contains Co metal + polyatomic group (CO₃). Question 2: For the Brønsted-Lowry acid-base reaction shown below, list the stronger acid, stronger base, weaker acid, and weaker base: NH₄⁺ + H₂PO₄⁻ ⇌ NH₃ + H₃PO₄ Answer: Stronger acid: H₃PO₄ ; Stronger base: NH₃ ; Weaker acid: NH₄⁺ ; Weaker base: H₂PO₄⁻. Question 3: Show the calculation of the [H⁺], pH, and % ionization for 0.645 M acetic acid (HC₂H₃O₂). Ka = 1.8 × 10⁻⁵ Answer: H⁺ = x = 3.41 × 10⁻³ M ; pH = -log(3.41×10⁻³) = 2.47 ; % ionization = (3.41×10⁻³ / 0.645) × 100 = 0.53%. Question 4: Show the calculation of the pH of a buffer prepared by mixing 0.100 M NH₄Cl and 0.0750 M NH₃. Ka = 1.8 × 10⁻⁵ Answer: pKa = -log(1.8×10⁻⁵) = 4.74. pH = pKa + log([base]/[acid]) = 4.74 + log(0.0750/0.100) = 4.74 + (-0.125) = 4.62. Question 5: Show the calculation of the molar solubility (mol/L) of BaF₂, Ksp of BaF₂ = 1.0 × 10⁻⁶. Answer: Ksp = [Ba²⁺][F⁻]² = (s)(2s)² = 4s³. s = (1.0×10⁻⁶ / 4)^(1/3) = 6.3 × 10⁻³ mol/L. Question 6: Predict whether a solution of LiF is acidic, basic, or neutral. Answer: Basic. F⁻ hydrolyzes to form a weak acid (HF) and OH⁻, resulting in a basic solution. CHEM 104 Exam 2 Study Materials Portage Acid Base Salt Identification Bronsted Lowry pH Calculation Weak Acid Ka Percent Ionization Acetic Acid Henderson Hasselbalch Buffer pH Ksp Molar Solubility Calculation General Chemistry II Module 2 Le Chatelier Equilibrium Shift Titration Equivalence Point Portage Learning CHEM 104 2026 A+ Grade Chemistry Study Guide

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2 MAXE · 401 MEHC
★ ★
University of Wisconsin–Madison
W Department of Chemistry
EST. 1848
NUMEN LUMEN · THE WISCONSIN IDEA




Chem 104 Exam #2 Study Materials
G E N E RA L C H E M I ST RY I I — M O L E CU L A R G E O M E T RY, O R GA N I C C H E M I ST RY &
T H E R M O DY N A M I CS

INSTITUTION University of Wisconsin–Madison PROGRAM Bachelor of Science — General
Chemistry II
COURSE CODE Chem 104 COURSE TITLE General Chemistry II
ACADEMIC YEAR EXAM TITLE Chem 104 Exam #2 Study Materials
TOTAL QUESTIONS 48 Questions FORMAT Multiple Choice — Select the
Single Best Answer


STUDY GUIDE INSTRUCTIONS
▸ This study guide covers molecular geometry, intermolecular forces, organic functional groups, fatty
acids, isomers, and thermodynamics for Chem 104 Exam 2.
▸ Each question tests one discrete concept, definition, or classification from the course material.
▸ Select the single best answer for each question. Correct answers and detailed rationales are provided.
▸ Pay careful attention to VSEPR theory nomenclature (electron geometry vs. molecular geometry), IUPAC
functional group naming, and thermodynamic sign conventions.
▸ All content reflects the standard General Chemistry II curriculum at UW–Madison.

, CHEM 104 — VSEPR, ORGANIC FUNCTIONAL GROUPS &
Questions 1 – 48
THERMODYNAMICS

1. A student is identifying an organic functional group that contains a carbonyl group (C=O)
bonded to a hydroxyl group (–OH), represented as –COOH. This functional group is
characteristic of organic acids. What is its name?
A. Ester
B. Aldehyde
C. Carboxyl acid (carboxylic acid)
D. Ketone
CORRECT ANSWER C — Carboxyl acid (carboxylic acid)
RATIONALE A carboxyl (carboxylic acid) group consists of a carbonyl (C=O) bonded to a
hydroxyl (–OH), written as –COOH. It is the functional group of organic acids like
acetic acid. An ester (Option A) has –COOR where R is an alkyl group. An aldehyde
(Option B) has –CHO with H attached to the carbonyl carbon. A ketone (Option D)
has C=O with two alkyl groups. Carboxylic acids are acidic because the –OH
proton is readily donated, stabilized by resonance with the carbonyl oxygen.

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