allCM2500/CM2501forKirby Hebert / Module7:BeamDesign|ColumnsandBuckling / FinalExam-Part2
vt vt vt vt vt vt vt v t v t v t vt vt vt vt vt vt vt v t v t vt vt vt vt
Information
Determinethemagnitudeanddirectionofallsupportreactionsforthepin-jointedstructureshown below.
vt vt vt vt vt vt vt vt vt vt vt vt vt vt
w = 600 lb/ft.
vt vt vt
Question 1 v t
Correct v t v t 1.00pointsoutof1.00
vt vt vt vt
Ay=
Selectone: vt
a. 1350lbs.↑ vt vt
b. 5400lbs.→ vt vt
c. 5400lbs.↓ vt vt
d. 1800lbs.↑ vt vt
, Question 2 v t
Correct v t v t 1.00pointsoutof1.00
vt vt vt vt
Ax=
Selectone:vt
a. 7200lbs.→ vt vt
b. 5400lbs.→ vt vt
c. 7200lbs.← vt vt
d. 5400lbs.← vt vt
Question 3 v t
Correct v t v t 1.00pointsoutof1.00
vt vt vt vt
Dy=
Selectone:vt
a. 4050lbs.↑ vt vt
b. 5400lbs.↑ vt vt
c. 5400lbs.↓ vt vt
d. 1800lbs.↑ vt vt
Question 4 v t
Incorrect v t 0.00pointsoutof1.00
vt vt vt vt
Dx=
Selectone:vt
a. 7200lbs.→ vt vt
b. 5400lbs.→ vt vt
c. 7200lbs.← vt vt
d. 5400lbs.← vt vt
vt vt vt vt vt vt vt v t v t v t vt vt vt vt vt vt vt v t v t vt vt vt vt
Information
Determinethemagnitudeanddirectionofallsupportreactionsforthepin-jointedstructureshown below.
vt vt vt vt vt vt vt vt vt vt vt vt vt vt
w = 600 lb/ft.
vt vt vt
Question 1 v t
Correct v t v t 1.00pointsoutof1.00
vt vt vt vt
Ay=
Selectone: vt
a. 1350lbs.↑ vt vt
b. 5400lbs.→ vt vt
c. 5400lbs.↓ vt vt
d. 1800lbs.↑ vt vt
, Question 2 v t
Correct v t v t 1.00pointsoutof1.00
vt vt vt vt
Ax=
Selectone:vt
a. 7200lbs.→ vt vt
b. 5400lbs.→ vt vt
c. 7200lbs.← vt vt
d. 5400lbs.← vt vt
Question 3 v t
Correct v t v t 1.00pointsoutof1.00
vt vt vt vt
Dy=
Selectone:vt
a. 4050lbs.↑ vt vt
b. 5400lbs.↑ vt vt
c. 5400lbs.↓ vt vt
d. 1800lbs.↑ vt vt
Question 4 v t
Incorrect v t 0.00pointsoutof1.00
vt vt vt vt
Dx=
Selectone:vt
a. 7200lbs.→ vt vt
b. 5400lbs.→ vt vt
c. 7200lbs.← vt vt
d. 5400lbs.← vt vt
