Questions & Answers | Complete Aptitude Study Guide
Prepare for the FCTC Mechanical Reasoning Test with this comprehensive practice test featuring
verified questions, correct answers, and detailed explanations. This study guide covers essential
topics including mechanical principles, force and motion, gears, pulleys, levers, tools, fluid
mechanics, basic physics, spatial reasoning, and problem-solving skills commonly assessed on
firefighter candidate aptitude examinations. Designed to reinforce critical mechanical concepts
and improve test-taking confidence, the material helps candidates develop the knowledge needed
to excel on the exam. Ideal for firefighter applicants seeking a reliable resource to prepare for
and successfully pass the FCTC Mechanical Reasoning Test.
Question 1
A lever has a fulcrum placed 2 feet from the load and 6 feet from the effort force. What
is the mechanical advantage of this lever?
A) 2
B) 3
C) 4
D) 6
Rationale: Mechanical Advantage (MA) = Distance from effort to fulcrum ÷ Distance from
load to fulcrum. MA = 6 ÷ 2 = 3. This means the lever multiplies the effort force by 3
times.
Question 2
In a Class 1 lever, where is the fulcrum located?
A) Between the effort and the load
B) At the end, with the load in the middle
C) At the end, with the effort in the middle
D) On the same side as the load
Rationale: A Class 1 lever has the fulcrum located between the effort and the load.
Examples include a seesaw, crowbar, and scissors. The mechanical advantage depends on
the distances from the fulcrum to the effort and load.
,Question 3
A fixed pulley changes the direction of force but provides no mechanical advantage.
What is the mechanical advantage of a single fixed pulley?
A) 0
B) 1
C) 2
D) 4
Rationale: A single fixed pulley has a mechanical advantage of 1. It only changes the
direction of the applied force (e.g., pulling down to lift a load up) without multiplying the
force. The effort force equals the load force.
Question 4
If gear A has 20 teeth and gear B has 60 teeth, and gear A turns at 120 RPM, what is the
speed of gear B?
A) 30 RPM
B) 40 RPM
C) 60 RPM
D) 120 RPM
Rationale: Gear ratio = Teeth of driven gear ÷ Teeth of driving gear = 60 ÷ 20 = 3. Speed
of driven gear = Speed of driving gear ÷ Gear ratio = 120 ÷ 3 = 40 RPM. When gear size
increases, speed decreases.
Question 5
What does a movable pulley provide in a rope system?
A) Mechanical advantage of 2
B) Mechanical advantage of 1
,C) Only changes direction
D) No mechanical advantage
Rationale: A single movable pulley provides a mechanical advantage of 2. The load is
supported by two rope segments, so the effort force required is half the load weight.
However, the rope must be pulled twice as far.
Question 6
A 150-pound force is applied to a 2-square-inch piston. What is the pressure exerted?
A) 50 PSI
B) 75 PSI
C) 100 PSI
D) 150 PSI
Rationale: Pressure = Force ÷ Area = 150 lbs ÷ 2 in² = 75 PSI (pounds per square inch).
This is a fundamental hydraulic principle (Pascal's law).
Question 7
If gear X turns clockwise, which direction does gear Y turn in a simple two-gear system?
A) Counterclockwise
B) Clockwise
C) Same direction
D) Cannot be determined
Rationale: In a simple two-gear system where the gears are meshed together, adjacent
gears always turn in opposite directions. If gear X turns clockwise, gear Y turns
counterclockwise.
Question 8
, A Class 2 lever has the load between the fulcrum and the effort. What is the mechanical
advantage compared to a Class 1 lever?
A) It is always less than 1
B) It is always greater than 1
C) It is always equal to 1
D) It depends on the load
Rationale: In a Class 2 lever, the effort arm is always longer than the load arm, so the
mechanical advantage is always greater than 1. Examples include a wheelbarrow and a
nutcracker.
Question 9
In a hydraulic system, if a 10-pound force is applied to a 1-square-inch piston, and the
output piston has an area of 5 square inches, what is the output force?
A) 10 pounds
B) 50 pounds
C) 100 pounds
D) 500 pounds
Rationale: Hydraulic systems multiply force based on the ratio of piston areas. Pressure =
Force₁ ÷ Area₁ = 10 ÷ 1 = 10 PSI. Output Force = Pressure × Area₂ = 10 × 5 = 50 pounds.
Question 10
What happens to the speed of a belt-driven pulley system when the driven pulley is
larger than the driving pulley?
A) The driven pulley turns slower
B) The driven pulley turns faster
C) The speed remains the same
D) The belt slips