,
, GROUP PERFORMANCE PROFILE N120 ASSESSMENT 2 FALL 2026 SECT
6F-SJ | QUESTIONS AND ANSWERS | 100% CORRECT - WCU.
SECTION 1: OVERALL CLASS PERFORMANCE
Question 1
What is the total number of students who completed N120 Assessment 2 for the Fall 2026 semester,
Section 6F-SJ?
A) 28 students
B) 32 students
C) 35 students
D) 38 students
Answer: B) 32 students
Rationale: The group performance profile for N120 Assessment 2 Fall 2026 Section 6F-SJ indicates
that 32 students completed the assessment. This number represents the total enrolled students who
took the examination within the specified testing window. The class size is typical for a foundational
nursing course at this institution.
Question 2
What is the mean (average) score for the class on Assessment 2?
A) 76.8 percent
B) 79.4 percent
C) 81.2 percent
D) 83.5 percent
Answer: B) 79.4 percent
, Rationale: The mean score for the class on Assessment 2 is 79.4 percent. This indicates that, on
average, students performed near the passing threshold (typically 75-80 percent depending on
program requirements). The mean is calculated by summing all individual scores and dividing by the
total number of students (32). This score suggests that many students are at risk for failing the course
if their performance does not improve on subsequent assessments.
Question 3
What is the median score for the class on Assessment 2?
A) 78.5 percent
B) 79.0 percent
C) 80.0 percent
D) 81.0 percent
Answer: B) 79.0 percent
Rationale: The median score is 79.0 percent, which is slightly lower than the mean (79.4 percent).
This indicates that the score distribution is slightly negatively skewed, meaning there are a few very
low scores pulling the mean down. The median represents the middle score when all scores are
arranged in ascending order (the 16th score out of 32). When the median is lower than the mean, it
suggests the presence of some high scores but more low scores.
Question 4
What is the standard deviation for the class on Assessment 2?
A) 6.8 percent
B) 7.5 percent
C) 8.2 percent
D) 9.1 percent
, GROUP PERFORMANCE PROFILE N120 ASSESSMENT 2 FALL 2026 SECT
6F-SJ | QUESTIONS AND ANSWERS | 100% CORRECT - WCU.
SECTION 1: OVERALL CLASS PERFORMANCE
Question 1
What is the total number of students who completed N120 Assessment 2 for the Fall 2026 semester,
Section 6F-SJ?
A) 28 students
B) 32 students
C) 35 students
D) 38 students
Answer: B) 32 students
Rationale: The group performance profile for N120 Assessment 2 Fall 2026 Section 6F-SJ indicates
that 32 students completed the assessment. This number represents the total enrolled students who
took the examination within the specified testing window. The class size is typical for a foundational
nursing course at this institution.
Question 2
What is the mean (average) score for the class on Assessment 2?
A) 76.8 percent
B) 79.4 percent
C) 81.2 percent
D) 83.5 percent
Answer: B) 79.4 percent
, Rationale: The mean score for the class on Assessment 2 is 79.4 percent. This indicates that, on
average, students performed near the passing threshold (typically 75-80 percent depending on
program requirements). The mean is calculated by summing all individual scores and dividing by the
total number of students (32). This score suggests that many students are at risk for failing the course
if their performance does not improve on subsequent assessments.
Question 3
What is the median score for the class on Assessment 2?
A) 78.5 percent
B) 79.0 percent
C) 80.0 percent
D) 81.0 percent
Answer: B) 79.0 percent
Rationale: The median score is 79.0 percent, which is slightly lower than the mean (79.4 percent).
This indicates that the score distribution is slightly negatively skewed, meaning there are a few very
low scores pulling the mean down. The median represents the middle score when all scores are
arranged in ascending order (the 16th score out of 32). When the median is lower than the mean, it
suggests the presence of some high scores but more low scores.
Question 4
What is the standard deviation for the class on Assessment 2?
A) 6.8 percent
B) 7.5 percent
C) 8.2 percent
D) 9.1 percent