Solutions Manual — Physics, 12th Edition (Cutnell, Johnson, Young & Stadler, 2021), Chapters 1-32 | All Chapters Covered

SOLUTIONS MANUAL
Physics
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John D. Cutnell, Kenneth W. Johnson, David Young, and Shane Stadler
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12th Edition
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, TABLE OF CONTENTS
Solutions Manual: Physics, 12th Edition
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By John D. Cutnell, Kenneth W. Johnson, David Young, and Shane Stadler

Chapter 1 Introduction and Mathematical Concepts
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Chapter 2 Kinematics in One Dimension
Chapter 3 Kinematics in Two Dimensions
Chapter 4 Forces and Newton’s Laws of Motion
Chapter 5 Dynamics of Uniform Circular Motion
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Chapter 6 Work and Energy
Chapter 7 Impulse and Momentum
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Chapter 8 Rotational Kinematics
Chapter 9 Rotational Dynamics
Chapter 10 Simple Harmonic Motion and Elasticity
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Chapter 11 Fluids
Chapter 12 Temperature and Heat
Chapter 13 The Transfer of Heat
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Chapter 14 The Ideal Gas Law and Kinetic Theory
Chapter 15 Thermodynamics
Chapter 16 Waves and Sound
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Chapter 17 The Principle of Linear Superposition and Interference Phenomena
Chapter 18 Electric Forces and Electric Fields
Chapter 19 Electric Potential Energy and the Electric Potential
Chapter 20 Electric Circuits
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Chapter 21 Magnetic Forces and Magnetic Fields
Chapter 22 Electromagnetic Induction
Chapter 23 Alternating Current Circuits
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Chapter 24 Electromagnetic Waves
Chapter 25 The Reflection of Light: Mirrors
Chapter 26 The Refraction of Light: Lenses and Optical Instruments
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Chapter 27 Interference and the Wave Nature of Light




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, Chapter 28 Special Relativity
Chapter 29 Particles and Waves
Chapter 30 The Nature of the Atom
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Chapter 31 Nuclear Physics and Radioactivity
Chapter 32 Ionizing Radiation, Nuclear Energy, and Elementary Particles
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, CHAPTER 1 INTRODUCTION AND
MATHEMATICAL CONCEPTS
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ANSWERS TO FOCUS ON CONCEPTS QUESTIONS
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1. (d) The resultant vector R is drawn from the tail of the first vector to the head of the
last vector.

2. (c) Note from the drawing that the magnitude R of the resultant vector R is equal to
the shortest distance between the tail of A and the head of B. Thus, R is less than the
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magnitude (length) of A plus the magnitude of B.

3. (b) In this drawing the vector –C is reversed relative to C, while vectors A and B are
not reversed.
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4. (c) In this drawing the vectors –B and –C are reversed relative to B and C, while vector
A is not reversed.
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5. (c) When the two vector components Ax and Ay are added by the tail-to-head method,
the sum equals the vector A. Therefore, these vector components are the correct ones.

6. (b) The displacement vector A points in the –y direction. Therefore, it has no scalar
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component along the x axis (Ax = 0 m) and its scalar component along the y axis is
negative.

7. (e) The scalar components are given by Ax = (450 m) sin 35.0 = 258 m and
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Ay = (450 m) cos 35.0 = 369 m.

8. (d)
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9. Rx = 0 m, Ry = 6.8 m

10. R = 7.9 m,    degrees
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11. (a) The triangle in the drawing is a right triangle. The lengths A and B of the two sides
are known, so the Pythagorean theorem can be used to determine the length R of the
hypotenuse.

 4.0 km 
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12. (b) The angle is found by using the inverse tangent function,   tan1  53 .
 3.0 km 
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