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MAT3705 Assignment 2 solutions 2026

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MAT3705 Assignment 2 solutions 2026 0-7-9-3-2-2-6-4-2-7 UNISA Learning Units 2,3 and 4 Due Date: 04 June 2026 iQ Level Work Verified score you 90%-100%

Institution
University Of South Africa (Unisa)
Course
Complex Analysis (MAT3705)

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MAT3705 Assignment 2 Solutions 2026
UNISA
Learning Units 2,3 and 4
Due Date: 04 June 2026




iQ Level Work Verified score you 90%-100%

, MAT3705 Assignment 2 (2026) — Full Solutions

Question 1

Given
𝑖𝑧
𝑓(𝑧) =
∣ 𝑧 ∣2


Let

𝑧 = 𝑥 + 𝑖𝑦


Then

∣ 𝑧 ∣2 = 𝑥 2 + 𝑦 2


and

𝑖𝑧 = 𝑖(𝑥 + 𝑖𝑦) = 𝑖𝑥 + 𝑖 2 𝑦 = 𝑖𝑥 − 𝑦


Therefore
−𝑦 + 𝑖𝑥
𝑓(𝑧) =
𝑥2 + 𝑦2


Hence
−𝑦
𝑢(𝑥, 𝑦) =
𝑥2 + 𝑦2


and
𝑥
𝑣(𝑥, 𝑦) =
𝑥2 + 𝑦2


So the correct option for Question 1(a) is:

iii




Partial derivatives
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