SOLUTIONS MANUAL
FOR FUNDAMENTALS OF ENGINEERING
ECONOMICS, 4TH EDITION, BY CHAN S. PARK (
ALL CHAPTERS COVERED) LATEST 2026
1
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contents
Chapter 1 Engineering Economic Decisions
Chapter 2 Time Value Of Money
Chapter 3 Understanding Money Management
Chapter 4 Equivalence Calculations Under Inflation
Chapter 5 Present-Worth Analysis
Chapter 6 Annual Equivalence Analysis
Chapter 7 Rate-Of-Return Analysis
Chapter 8 Accounting For Depreciation And Income Taxes
Chapter 9 Project Cash Flow Analysis
Chapter 10 Handling Project Uncertainty
Chapter 11 Replacement Decisions
Chapter 12 Benefit-Cost Analysis
Chapter 13 Understanding Financial Statements
,chapter 1 engineering economic decisions
there are no end-of-chapter questions in this introductory chapter. however, the following questions
could be added as a part of instruction:
1. ask students to review the contents of the wall street journal for the past 3 months.
then, identify and categorize the types of investment decisions appeared in the journal
according to the types of strategic economics decisions discussed in the text.
2. work in small groups and brainstorm ideas about how a common appliance, device or
tool could be redesigned to improve it in some way. identify the steps involved and the
economic factors, which you would need to consider prior to making a decision to
manufacture the redesigned product. a detailed design and actual cost estimates are not
required. some items, which could be considered
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for this redesign exercise, are: a shopping cart, telephone, can opener, screwdriver, etc.
3. many oil price forecasts in the early 2000 indicated that the price of oil in the year 2007
would not exceed $50 per barrel. what is the price of today? why are these prices so
difficult to predict? imagine what the consequences would be if you used these optimistic
estimates in your economic analysis in your early project undertaking. what would be
some practical ways to consider this type of variation in economic analysis?
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, chapter 2: time value of money
2.1) i ipn (0.09)($3,000)(5) $1,350
2.2)
• simple interest:
f p in)
$4, 000 $2, 0.08n)
n 12.5 years (or 13 years)
• compound interest:
$4, 000 $2, 0.07)n
2 1.07n
log 2 n log 1.07
n 10.24 years (or 11 years)
2.3)
• simple interest:
i ipn (0.07)($10, 000)(20)
$14, 000
• compound interest:
i p (1 i)n 1 $10,000 (1.07)20 1
$28,696.84
2.4)
• compound interest:
f $1, 0.06)5
$1, 338.23
• simple interest:
f $1, 0.07(5))
350
the simple interest option is better.
instructor solutions manual to accompany fundamentals of engineering economics, second edition, by chan s. park.