SUMMER 2026
PREDICTED PAPER
AQA A-level
MATHEMATICS
7357/3
Paper 3
Mark scheme
,1 Given that
J g(x) dx = 5
deduce the value of
(g(x) + 1) dx
이
Circle your answer.
5 13 6 -3
Given that
Split the integral raquired so we can use the given
[R(x) dx= 5 result.
[(gha) i) d [ g(x)
gta) dx+[1 0x
deduce thevalue of
(g(x)+1) dx
Circle your answe
5+ [2]
5+(8-0)
exams
13 -3
xa
=13
ve
save my
(1 mark)
2 Given that
5 cos a - 12 sin a = R cos(0 + а)
find the value of R.
Circle your answer.
, 17 13 5 12
Given that
5 cos a-12 sin a= R cos(0+a)
This is a harmonic identity. "R²=2²+62"
R52+(-12)
find the value of R.
Circle your answer
R=169
17 13 12
[1] R=√169=13
myexams
save my
(1 mark)
3 Determine which one of these graphs represents a function whose inverse function
exists.
Tick (✓) one box.
x
A B
, KN
Determine which one of these graphs represents a function whose in tion exists.
For a function to have an inverse it needs
Tick ( one box. to be one-to-one.
Draw horizontal and /or vertical lines on
each graph to see if any intersect the
graph more than once.
Graph A: many-to-one
Graph B (infinitely) many-to-one ("all-to-one"!)
save myexams
Graph C one-to-many
Graph D one-to-one
C D
[1]
(1 mark)
PREDICTED PAPER
AQA A-level
MATHEMATICS
7357/3
Paper 3
Mark scheme
,1 Given that
J g(x) dx = 5
deduce the value of
(g(x) + 1) dx
이
Circle your answer.
5 13 6 -3
Given that
Split the integral raquired so we can use the given
[R(x) dx= 5 result.
[(gha) i) d [ g(x)
gta) dx+[1 0x
deduce thevalue of
(g(x)+1) dx
Circle your answe
5+ [2]
5+(8-0)
exams
13 -3
xa
=13
ve
save my
(1 mark)
2 Given that
5 cos a - 12 sin a = R cos(0 + а)
find the value of R.
Circle your answer.
, 17 13 5 12
Given that
5 cos a-12 sin a= R cos(0+a)
This is a harmonic identity. "R²=2²+62"
R52+(-12)
find the value of R.
Circle your answer
R=169
17 13 12
[1] R=√169=13
myexams
save my
(1 mark)
3 Determine which one of these graphs represents a function whose inverse function
exists.
Tick (✓) one box.
x
A B
, KN
Determine which one of these graphs represents a function whose in tion exists.
For a function to have an inverse it needs
Tick ( one box. to be one-to-one.
Draw horizontal and /or vertical lines on
each graph to see if any intersect the
graph more than once.
Graph A: many-to-one
Graph B (infinitely) many-to-one ("all-to-one"!)
save myexams
Graph C one-to-many
Graph D one-to-one
C D
[1]
(1 mark)
