RASMUSSEN PATHOPHYSIOLOGY EXAM 1 2026/2027 | 100%
Correct Answers with Complete Solutions | Nursing
Prerequisite | Pass Guaranteed - A+ Graded
Topic 1: Cellular Adaptation and Injury (10 Questions)
Q1: A 75-year-old client with right-sided hemiplegia following a stroke has noticed that
their right arm appears noticeably smaller than the left. The nurse recognizes this as an
example of which cellular adaptation?
A. Hypertrophy due to compensatory mechanisms
B. Hyperplasia from neural stimulation loss
C. Atrophy from disuse and denervation [CORRECT]
D. Metaplasia caused by ischemic tissue changes
Correct Answer: C
Rationale: This scenario demonstrates disuse atrophy, a decrease in cell size due to
reduced workload. Following a stroke, denervation (loss of neural stimulation) and
immobility lead to reduced protein synthesis and increased protein degradation in
skeletal muscle. The affected limb receives inadequate mechanical stimulation and
trophic signals, causing muscle fibers to shrink.
● A is incorrect: Hypertrophy involves increased cell size, which occurs in the
unaffected (compensating) left side if it takes on additional work, not the
affected side.
● B is incorrect: Hyperplasia involves increased cell number; mature skeletal
muscle cells are terminally differentiated and cannot undergo hyperplasia.
● D is incorrect: Metaplasia is the reversible replacement of one differentiated cell
type with another (e.g., columnar to squamous epithelium), not applicable to
muscle tissue changes post-stroke.
,Q2: A postmenopausal woman is diagnosed with endometrial hyperplasia. The
pathophysiology of this condition involves which mechanism?
A. Decreased estrogen stimulation causing cellular shrinkage
B. Excessive estrogen stimulation promoting cellular proliferation [CORRECT]
C. Chronic inflammation inducing metaplastic changes
D. Ischemic injury triggering compensatory cellular enlargement
Correct Answer: B
Rationale: Endometrial hyperplasia represents hormonal hyperplasia—an increase in the
number of endometrial glandular cells due to excessive estrogen stimulation
unopposed by progesterone. Estrogen binds to nuclear receptors, promoting DNA
synthesis and mitotic activity. Without progesterone-induced differentiation and
shedding, continued proliferation creates a thickened, disordered endometrium with
increased cancer risk.
● A is incorrect: Estrogen deficiency causes atrophic changes (thin endometrium),
not hyperplasia.
● C is incorrect: While chronic inflammation can cause metaplasia, endometrial
hyperplasia is fundamentally a hormonal proliferation disorder.
● D is incorrect: Ischemia causes cellular injury or atrophy, not hyperplasia;
compensatory enlargement describes hypertrophy, not increased cell numbers.
Q3: A client with a 40-pack-year smoking history develops metaplasia in the bronchial
epithelium. Which pathophysiological process has occurred?
A. Irreversible transformation of normal cells to malignant cells
B. Reversible replacement of pseudostratified columnar epithelium with stratified
squamous epithelium [CORRECT]
C. Abnormal variation in cell size and shape with nuclear atypia
D. Adaptive enlargement of individual ciliated columnar cells
Correct Answer: B
,Rationale: Metaplasia is a reversible adaptive response where one mature differentiated
cell type replaces another better suited to withstand adverse conditions. In smokers,
chronic irritation causes pseudostratified ciliated columnar epithelium to transform into
stratified squamous epithelium (squamous metaplasia), which is more resistant to
chemical irritation but lacks mucociliary clearance. This change is reversible if irritant
exposure ceases.
● A is incorrect: Metaplasia is reversible and distinct from dysplasia or malignancy,
though persistent metaplasia can be a precursor lesion.
● C is incorrect: This describes dysplasia—disordered, premalignant cellular
development with nuclear atypia and loss of polarity.
● D is incorrect: Cellular enlargement describes hypertrophy; metaplasia involves
lineage switching to a different cell type, not size changes.
Q4: During a biopsy, a pathologist notes cells demonstrating variation in size and shape,
nuclear hyperchromatism, and loss of normal tissue architecture. These findings are
characteristic of:
A. Reversible cellular adaptation to chronic irritation
B. Disordered, non-neoplastic cellular proliferation indicating pre-malignant change
[CORRECT]
C. Programmed cell death with maintenance of membrane integrity
D. Coordinated cellular enlargement in response to increased demand
Correct Answer: B
Rationale: These findings describe dysplasia—disordered epithelial cell growth with loss
of normal maturation, nuclear pleomorphism, hyperchromatism, and architectural
distortion. Dysplasia represents a pre-neoplastic change that may progress to
carcinoma in situ or invasive cancer if causative factors persist. It is graded (mild,
moderate, severe) based on the extent of epithelial involvement.
, ● A is incorrect: Reversible adaptation describes metaplasia; dysplasia is
potentially premalignant and considered more serious.
● C is incorrect: Programmed cell death with membrane integrity describes
apoptosis, characterized by cell shrinkage and chromatin condensation without
inflammation.
● D is incorrect: Coordinated enlargement describes hypertrophy, which maintains
normal cellular architecture and function.
Q5: A client experiences cardiac hypertrophy following chronic hypertension. Which
cellular mechanism primarily drives this adaptation?
A. Increased cell number through stimulated mitosis
B. Increased cell size due to enhanced protein synthesis and sarcomere addition
[CORRECT]
C. Replacement of damaged cardiomyocytes with fibroblast proliferation
D. Accumulation of intracellular lipid droplets causing cellular expansion
Correct Answer: B
Rationale: Cardiac hypertrophy is work-induced hypertrophy—an increase in
cardiomyocyte size (not number) due to chronic pressure overload. Increased wall
stress triggers mechanotransduction pathways, activating transcription factors that
upregulate contractile protein synthesis and add sarcomeres in parallel. This increases
wall thickness to normalize wall stress (Laplace's law: wall stress = pressure × radius / 2
× thickness).
● A is incorrect: Adult cardiomyocytes are terminally differentiated and rarely
divide; cardiac enlargement is hypertrophy, not hyperplasia.
● C is incorrect: Fibroblast proliferation with collagen deposition describes
pathological fibrosis/scarring, not adaptive hypertrophy.
● D is incorrect: Lipid accumulation describes fatty change (steatosis), a form of
reversible injury, not adaptive hypertrophy.
Correct Answers with Complete Solutions | Nursing
Prerequisite | Pass Guaranteed - A+ Graded
Topic 1: Cellular Adaptation and Injury (10 Questions)
Q1: A 75-year-old client with right-sided hemiplegia following a stroke has noticed that
their right arm appears noticeably smaller than the left. The nurse recognizes this as an
example of which cellular adaptation?
A. Hypertrophy due to compensatory mechanisms
B. Hyperplasia from neural stimulation loss
C. Atrophy from disuse and denervation [CORRECT]
D. Metaplasia caused by ischemic tissue changes
Correct Answer: C
Rationale: This scenario demonstrates disuse atrophy, a decrease in cell size due to
reduced workload. Following a stroke, denervation (loss of neural stimulation) and
immobility lead to reduced protein synthesis and increased protein degradation in
skeletal muscle. The affected limb receives inadequate mechanical stimulation and
trophic signals, causing muscle fibers to shrink.
● A is incorrect: Hypertrophy involves increased cell size, which occurs in the
unaffected (compensating) left side if it takes on additional work, not the
affected side.
● B is incorrect: Hyperplasia involves increased cell number; mature skeletal
muscle cells are terminally differentiated and cannot undergo hyperplasia.
● D is incorrect: Metaplasia is the reversible replacement of one differentiated cell
type with another (e.g., columnar to squamous epithelium), not applicable to
muscle tissue changes post-stroke.
,Q2: A postmenopausal woman is diagnosed with endometrial hyperplasia. The
pathophysiology of this condition involves which mechanism?
A. Decreased estrogen stimulation causing cellular shrinkage
B. Excessive estrogen stimulation promoting cellular proliferation [CORRECT]
C. Chronic inflammation inducing metaplastic changes
D. Ischemic injury triggering compensatory cellular enlargement
Correct Answer: B
Rationale: Endometrial hyperplasia represents hormonal hyperplasia—an increase in the
number of endometrial glandular cells due to excessive estrogen stimulation
unopposed by progesterone. Estrogen binds to nuclear receptors, promoting DNA
synthesis and mitotic activity. Without progesterone-induced differentiation and
shedding, continued proliferation creates a thickened, disordered endometrium with
increased cancer risk.
● A is incorrect: Estrogen deficiency causes atrophic changes (thin endometrium),
not hyperplasia.
● C is incorrect: While chronic inflammation can cause metaplasia, endometrial
hyperplasia is fundamentally a hormonal proliferation disorder.
● D is incorrect: Ischemia causes cellular injury or atrophy, not hyperplasia;
compensatory enlargement describes hypertrophy, not increased cell numbers.
Q3: A client with a 40-pack-year smoking history develops metaplasia in the bronchial
epithelium. Which pathophysiological process has occurred?
A. Irreversible transformation of normal cells to malignant cells
B. Reversible replacement of pseudostratified columnar epithelium with stratified
squamous epithelium [CORRECT]
C. Abnormal variation in cell size and shape with nuclear atypia
D. Adaptive enlargement of individual ciliated columnar cells
Correct Answer: B
,Rationale: Metaplasia is a reversible adaptive response where one mature differentiated
cell type replaces another better suited to withstand adverse conditions. In smokers,
chronic irritation causes pseudostratified ciliated columnar epithelium to transform into
stratified squamous epithelium (squamous metaplasia), which is more resistant to
chemical irritation but lacks mucociliary clearance. This change is reversible if irritant
exposure ceases.
● A is incorrect: Metaplasia is reversible and distinct from dysplasia or malignancy,
though persistent metaplasia can be a precursor lesion.
● C is incorrect: This describes dysplasia—disordered, premalignant cellular
development with nuclear atypia and loss of polarity.
● D is incorrect: Cellular enlargement describes hypertrophy; metaplasia involves
lineage switching to a different cell type, not size changes.
Q4: During a biopsy, a pathologist notes cells demonstrating variation in size and shape,
nuclear hyperchromatism, and loss of normal tissue architecture. These findings are
characteristic of:
A. Reversible cellular adaptation to chronic irritation
B. Disordered, non-neoplastic cellular proliferation indicating pre-malignant change
[CORRECT]
C. Programmed cell death with maintenance of membrane integrity
D. Coordinated cellular enlargement in response to increased demand
Correct Answer: B
Rationale: These findings describe dysplasia—disordered epithelial cell growth with loss
of normal maturation, nuclear pleomorphism, hyperchromatism, and architectural
distortion. Dysplasia represents a pre-neoplastic change that may progress to
carcinoma in situ or invasive cancer if causative factors persist. It is graded (mild,
moderate, severe) based on the extent of epithelial involvement.
, ● A is incorrect: Reversible adaptation describes metaplasia; dysplasia is
potentially premalignant and considered more serious.
● C is incorrect: Programmed cell death with membrane integrity describes
apoptosis, characterized by cell shrinkage and chromatin condensation without
inflammation.
● D is incorrect: Coordinated enlargement describes hypertrophy, which maintains
normal cellular architecture and function.
Q5: A client experiences cardiac hypertrophy following chronic hypertension. Which
cellular mechanism primarily drives this adaptation?
A. Increased cell number through stimulated mitosis
B. Increased cell size due to enhanced protein synthesis and sarcomere addition
[CORRECT]
C. Replacement of damaged cardiomyocytes with fibroblast proliferation
D. Accumulation of intracellular lipid droplets causing cellular expansion
Correct Answer: B
Rationale: Cardiac hypertrophy is work-induced hypertrophy—an increase in
cardiomyocyte size (not number) due to chronic pressure overload. Increased wall
stress triggers mechanotransduction pathways, activating transcription factors that
upregulate contractile protein synthesis and add sarcomeres in parallel. This increases
wall thickness to normalize wall stress (Laplace's law: wall stress = pressure × radius / 2
× thickness).
● A is incorrect: Adult cardiomyocytes are terminally differentiated and rarely
divide; cardiac enlargement is hypertrophy, not hyperplasia.
● C is incorrect: Fibroblast proliferation with collagen deposition describes
pathological fibrosis/scarring, not adaptive hypertrophy.
● D is incorrect: Lipid accumulation describes fatty change (steatosis), a form of
reversible injury, not adaptive hypertrophy.
