Solution Manual - Introduction to Chemical Engineering Thermaodynmics 9th Edition - Smith - All 16 Chapter Included

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,solution-manual-introduction-to-chemical-engineering-
thermodynamics-7th-edition Chapter 1 - Section A - Mathcad
Solutions
1.4 The equation that relates deg F to deg C is: t(F) = 1.8 t(C) + 32. Solve this
equation by setting t(F) = t(C).

Guess solution: t = 0


2
P = 3000bar A = 12.566 mm

mass = 384.4 kg
2
P = 3000atm

mass = 1000.7 lbm
1.7 Pabs = gh + Patm

gm m
 = 13.535 g = 9.832 h = 56.38cm
3 2
cm s


gm ft
1.8  = 13.535 g = 32.243 h = 25.62in
3 2
cm s
gm m
1.10 Assume the following:  = 13.5 g = 9.8
3 2
cm s
P
P = h =
g h = 302.3 m Ans.
400b
ar


1.11 The force on a spring is described by: F = Ks x where Ks is the spring
constant. First calculate K based on the earth measurement then gMars
based on spring measurement on Mars.
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, On Earth:
m
F = massg = Kx g = 9.81 mass = 0.40kg
2
s
N F
F = massg Ks = 363.333
m x
On Mars: F = 3.924 N
x = 0.40cm Ks =
FMars Mars
g = mass FMars = Kx
−3
FMars = 4  10 mK
mK
gMars = 0.01 Ans.
kg


d
1.12 Given: P = −g
dz




Separating variables and integrating:




After integrating: ln =



and rearranging:

gm
Psea = 1atm M = 29
mol
3
cm atm
R = 82.06 T = (10 + 273.15)K zDenver = 1mi
molK
Mg m
zDenver = 0.194 g = 9.8
RT 2
s

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