Solution manual for applied strength of materials,
7th edition by robert l. Mott | all chapters 1-14|
latest edition 2026
,Table of contents
1. 1. Basic concepts in strength of materials
2. Exploration
3. 1–1 objective of this book: to ensure safety
4. 1–2 objectives of this chapter
5. 1–3 basic unit systems
6. 1–4 mass, force, and weight
7. 1–5 concept of stress
8. 1–6 direct normal stress
9. 1–7 stress elements for direct normal stresses
10. 1–8 concept of strain
11. 1–9 direct shear stress
12. 1–10 stress elements for shear stresses
13. 1–11 commercially available standard shapes
14. 1–12 preferred sizes and screw threads
15. 1–13 review of the fundamentals of statics
16. 2. Design properties of materials
17. Exploration
18. 2–1 objectives of this chapter
19. 2–2 design properties of materials
20. 2–3 steel
21. 2–4 cast iron
22. 2–5 aluminum
23. 2–6 copper, brass, and bronze
24. 2–7 zinc-, magnesium-, titanium-, and nickel-based alloys
25. 2–8 nonmetals in engineering design
26. 2–9 wood
27. 2–10 concrete
28. 2–11 plastics
29. 2–12 composites
30. 2–13 materials selection
31. 3. Direct stress, deformation, and design
32. Exploration
33. 3–1 objectives of this chapter
34. 3–2 applied normal stress
35. 3–3 design normal stress
36. 3–4 determination of design factor
,37. 3–5 methods of computing design stress
38. 3–6 elastic deformation in tension and compression members
39. 3–7 stress concentration factors for direct axial stresses
40. 3–8 applied bearing stress
41. 3–9 design bearing stress
42. 4. Design for direct shear, torsional shear, and torsional deformation
43. Exploration
44. 4–1 objectives of this chapter
45. 4–2 design shear stress
46. 4–3 transmitting power through rotating shafts
47. 4–4 applied torsional shear stress in members with circular cross sections
48. 4–5 development of the torsional shear stress formula
49. 4–6 polar moment of inertia for solid circular bars
50. 4–7 torsional shear stress and polar moment of inertia for hollow circular bars
51. 4–8 design of circular members under torsion
52. 4–9 comparison of solid and hollow circular members
53. 4–10 stress concentrations in torsionally loaded members
54. 4–11 twisting: elastic torsional deformation
55. 4–12 torsion in noncircular sections
56. References
57. Internet sites
58. Problems
59. 5. Shearing forces and bending moments in beams
60. 6. Centroids and moments of inertia of areas
61. 7. Stress due to bending
62. 8. Shearing stresses in beams
63. 9. Deflection of beams
64. 10. Combined stresses
65. 11. Columns
66. 12. Pressure vessels
67. 13. Connections
68. 14. Thermal effects and elements of more than one material
, Chapter 1 basic concepts in strength of materials
1.1 to 1.11 answers in text.
1.12 𝑊 = 𝑚 ∙ 𝑔 = 1400 kg ∙ 9.81 m/s2 = 13 734 (kg ∙ m)/s2 = 14 × 103 n
𝑾 = 𝟏3. 𝟕 𝐤𝐍
1.13 total weight = 𝑚 𝑔 = 3500 kg ∙ 9.81 m/s2 = 34.34 kn each
front wheel: 𝐹𝐹 = (1 ) (0.40)(34.34 kn ) = 6.87 𝐤𝐍
2
each rear wheel: 𝐹𝑅 = (1 ) (0.60)(34.34 kn ) = 𝟏0.32 𝐤𝐍
2
1.14 loading = total force / area
Total force = 𝑚 𝑔 = 5900 kg ∙ 9.81 m/s2 = 57.9 kn
area = (4.5 m )(3.5 m ) = 15.8 m 2
Loading = 57.9 kn ⁄15.8 m 2 = 3.66 kn ⁄m 2 = 𝟑.66 𝐤𝐏𝐚
1.15 force = 𝑚 𝑔 = 35 kg ∙ 9.81 m/s2 = 343 n
K = spring scale =4800 n⁄m = 𝐹/δ𝐿
δ𝐿 = 𝐹 = 343 n = 0.0715 m = 71.5 × 10−3 m = 71. 𝟓 𝐦𝐦
𝐾 4800 n/m
1.16 𝑚=
𝑤
=
3250 lb lb∙s2 = 101 𝐬𝐥𝐮𝐠𝐬
𝑔 32.2 (ft/s2 )
= 101 ft
1.17 𝑚=
𝑤
=
11 600 lb lb∙s2 = 𝟑60 𝐬𝐥𝐮𝐠𝐬
𝑔 32.2 (ft/s2 )
= 360 ft
1.19 𝑝 = 1700 psi ∙ 6.895 (kpa⁄psi) = 11 722 𝐤𝐏𝐚
1.20 𝜎 = 24 300 psi ∙ 6.895 (kpa⁄psi) = 167 549 kpa = 𝟏68 𝐌𝐏𝐚
7th edition by robert l. Mott | all chapters 1-14|
latest edition 2026
,Table of contents
1. 1. Basic concepts in strength of materials
2. Exploration
3. 1–1 objective of this book: to ensure safety
4. 1–2 objectives of this chapter
5. 1–3 basic unit systems
6. 1–4 mass, force, and weight
7. 1–5 concept of stress
8. 1–6 direct normal stress
9. 1–7 stress elements for direct normal stresses
10. 1–8 concept of strain
11. 1–9 direct shear stress
12. 1–10 stress elements for shear stresses
13. 1–11 commercially available standard shapes
14. 1–12 preferred sizes and screw threads
15. 1–13 review of the fundamentals of statics
16. 2. Design properties of materials
17. Exploration
18. 2–1 objectives of this chapter
19. 2–2 design properties of materials
20. 2–3 steel
21. 2–4 cast iron
22. 2–5 aluminum
23. 2–6 copper, brass, and bronze
24. 2–7 zinc-, magnesium-, titanium-, and nickel-based alloys
25. 2–8 nonmetals in engineering design
26. 2–9 wood
27. 2–10 concrete
28. 2–11 plastics
29. 2–12 composites
30. 2–13 materials selection
31. 3. Direct stress, deformation, and design
32. Exploration
33. 3–1 objectives of this chapter
34. 3–2 applied normal stress
35. 3–3 design normal stress
36. 3–4 determination of design factor
,37. 3–5 methods of computing design stress
38. 3–6 elastic deformation in tension and compression members
39. 3–7 stress concentration factors for direct axial stresses
40. 3–8 applied bearing stress
41. 3–9 design bearing stress
42. 4. Design for direct shear, torsional shear, and torsional deformation
43. Exploration
44. 4–1 objectives of this chapter
45. 4–2 design shear stress
46. 4–3 transmitting power through rotating shafts
47. 4–4 applied torsional shear stress in members with circular cross sections
48. 4–5 development of the torsional shear stress formula
49. 4–6 polar moment of inertia for solid circular bars
50. 4–7 torsional shear stress and polar moment of inertia for hollow circular bars
51. 4–8 design of circular members under torsion
52. 4–9 comparison of solid and hollow circular members
53. 4–10 stress concentrations in torsionally loaded members
54. 4–11 twisting: elastic torsional deformation
55. 4–12 torsion in noncircular sections
56. References
57. Internet sites
58. Problems
59. 5. Shearing forces and bending moments in beams
60. 6. Centroids and moments of inertia of areas
61. 7. Stress due to bending
62. 8. Shearing stresses in beams
63. 9. Deflection of beams
64. 10. Combined stresses
65. 11. Columns
66. 12. Pressure vessels
67. 13. Connections
68. 14. Thermal effects and elements of more than one material
, Chapter 1 basic concepts in strength of materials
1.1 to 1.11 answers in text.
1.12 𝑊 = 𝑚 ∙ 𝑔 = 1400 kg ∙ 9.81 m/s2 = 13 734 (kg ∙ m)/s2 = 14 × 103 n
𝑾 = 𝟏3. 𝟕 𝐤𝐍
1.13 total weight = 𝑚 𝑔 = 3500 kg ∙ 9.81 m/s2 = 34.34 kn each
front wheel: 𝐹𝐹 = (1 ) (0.40)(34.34 kn ) = 6.87 𝐤𝐍
2
each rear wheel: 𝐹𝑅 = (1 ) (0.60)(34.34 kn ) = 𝟏0.32 𝐤𝐍
2
1.14 loading = total force / area
Total force = 𝑚 𝑔 = 5900 kg ∙ 9.81 m/s2 = 57.9 kn
area = (4.5 m )(3.5 m ) = 15.8 m 2
Loading = 57.9 kn ⁄15.8 m 2 = 3.66 kn ⁄m 2 = 𝟑.66 𝐤𝐏𝐚
1.15 force = 𝑚 𝑔 = 35 kg ∙ 9.81 m/s2 = 343 n
K = spring scale =4800 n⁄m = 𝐹/δ𝐿
δ𝐿 = 𝐹 = 343 n = 0.0715 m = 71.5 × 10−3 m = 71. 𝟓 𝐦𝐦
𝐾 4800 n/m
1.16 𝑚=
𝑤
=
3250 lb lb∙s2 = 101 𝐬𝐥𝐮𝐠𝐬
𝑔 32.2 (ft/s2 )
= 101 ft
1.17 𝑚=
𝑤
=
11 600 lb lb∙s2 = 𝟑60 𝐬𝐥𝐮𝐠𝐬
𝑔 32.2 (ft/s2 )
= 360 ft
1.19 𝑝 = 1700 psi ∙ 6.895 (kpa⁄psi) = 11 722 𝐤𝐏𝐚
1.20 𝜎 = 24 300 psi ∙ 6.895 (kpa⁄psi) = 167 549 kpa = 𝟏68 𝐌𝐏𝐚
