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, MAC 231 I Name: .1 bh rn s
Module 3 Test
Sections (3.5 - 3.8)
Multiple Choice (5 points each)
Determine which one of the following defines y implicitly rather than explicitly.
tAl ! = 3stnx
tB] ! = xlnx
tCl x=e!
tDl !=ex*xlnx
7, Determine an expression for
dv
dx
if siny-x.
tAl csc/ + 4
4x Ll-t,.ql
\J)
= f. i.J
tBl
tcl
cos/
sin y
+ (,'y)(#-) = t
ID] sec/ n
=>
a- *L(
lEl CSCX ds. 1r:54
= *13
U3. Determine an expression for 4!- if : *t' -t^Y:'l
dx
lAl dY- 2o-Y'
+ 4[rf+:l _ #U7
dx 2xy-sec2 y
l-z
tBl dY
- Y sec2 =+L, J**(.r*I -&4(*)=
dx y'+Zxy
tcl &=
dx
y'
sec' y
+ #(t.y-'.te) -3'
-2xy
tDl
d!
dx
= 2*r- sec' y
+ 9:,=-9'a
7x t"cJ
y
tEl dy _2n+secz
dx 2x
'*Y
=gncJ-L\
This study source was downloaded by 100000904123021 from CourseHero.com on 02-26-2026 22:40:58 GMT -06:00
https://www.coursehero.com/file/105955179/Module-3-Test-solutions-1pdf/
Scholarfriends
https://scholarfriends.com
Downloaded by: | https://scholarfriends.com/singlePaper/618996/mac-2311-calculus-with-analytic-geometry-i-module-3-
test-solutions
Distribution of this document is illegal.
, MAC 231 I Name: .1 bh rn s
Module 3 Test
Sections (3.5 - 3.8)
Multiple Choice (5 points each)
Determine which one of the following defines y implicitly rather than explicitly.
tAl ! = 3stnx
tB] ! = xlnx
tCl x=e!
tDl !=ex*xlnx
7, Determine an expression for
dv
dx
if siny-x.
tAl csc/ + 4
4x Ll-t,.ql
\J)
= f. i.J
tBl
tcl
cos/
sin y
+ (,'y)(#-) = t
ID] sec/ n
=>
a- *L(
lEl CSCX ds. 1r:54
= *13
U3. Determine an expression for 4!- if : *t' -t^Y:'l
dx
lAl dY- 2o-Y'
+ 4[rf+:l _ #U7
dx 2xy-sec2 y
l-z
tBl dY
- Y sec2 =+L, J**(.r*I -&4(*)=
dx y'+Zxy
tcl &=
dx
y'
sec' y
+ #(t.y-'.te) -3'
-2xy
tDl
d!
dx
= 2*r- sec' y
+ 9:,=-9'a
7x t"cJ
y
tEl dy _2n+secz
dx 2x
'*Y
=gncJ-L\
This study source was downloaded by 100000904123021 from CourseHero.com on 02-26-2026 22:40:58 GMT -06:00
https://www.coursehero.com/file/105955179/Module-3-Test-solutions-1pdf/