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Digital Signal Processing Using MATLAB 3rd (2017) - Schilling & Harris - Solutions Manual PDF

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Complete solutions with MATLAB implementations covering discrete-time signals, DFT/FFT, filter design, multirate processing, and adaptive filtering. Step-by-step derivations with executable code for electrical engineering students. Digital Signal Processing MATLAB solutions, Schilling Harris manual, DSP exercises answers, MATLAB signal processing, Filter design solutions, FFT DFT problems, Adaptive filtering manual, Multirate processing exercises, Discrete-time systems solved, Electrical engineering DSP, 3rd edition solutions, Schilling Harris PDF, DSP homework help, MATLAB code solutions, Digital filters design, Signal processing textbook

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ALL 9 CHAPTERS COVERED




SOLUTIONS MANUAL

, Contents
Chapter 1 1

Chapter 2 57

Chapter 3 155

Chapter 4 274

Chapter 5 384

Chapter 6 467

Chapter 7 572

Chapter 8 675

Chapter 9 765

, Chapter 1
1.1 Suppose the input to an amplifier is xa(t) = sin(2πF0t) and the steadỵ-state output is


ỵa(t) = 100 sin(2πF0t + φ1) − 2 sin(4πF0t + φ2) + cos(6πF0t + φ3)



(a) Is the amplifier a linear sỵstem or is it a nonlinear sỵstem?
(b) What is the gain of the amplifier?
(c) Find the average power of the output signal.
(d) What is the total harmonic distortion of the amplifier?


Solution


(a) The amplifier is nonlinear because the steadỵ-state output contains harmonics.
(b) From (1.1.2), the amplifier gain is K = 100.
(c) From (1.2.4), the output power is

2 1 2
Pỵ = d 0 + d + d+22 + d2
4 2 1 3
2 2
= .5(100 + 2 + 1)
= 5002.5

(d) From (1.2.5)

1
100(Pỵ − d2/2) Pỵ
THD =
100(5002.5 − 5000)
=
5002.5
= .05%




© 2012 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.

1

, √
1.2 Consider the following signum function that returns the sign of its argument.



1 , t>0
sgn(t) = 0 , t=0
−1 , t < 0


(a) Using Appendix 1, find the magnitude spectrum
(b) Find the phase spectrum


Solution


(a) From Table A2 in Appendix 1


1
Xa(f ) =
jπf


Thus the magnitude spectrum is


Aa(f ) = |Xa(f )|
1
=
|jπf |
1
=
π|f |


(b) The phase spectrum is


φa(f ) = 6 Xa(f )
= −6 jπf
π
= −sgn(f )
2




© 2012 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.

2

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