g g g
SOLUTION MANUAL
g
, Cg g Og g Ng g Tg g Eg g Ng g Tg g S
Preface i
Solutionsg tog Problemsg Chapterg 2 1
Solutionsg tog Problemsg Chapterg 3 17
Solutionsg tog Problemsg Chapterg 4 29
Solutionsg tog Problemsg Chapterg 5 49
Solutionsg tog Problemsg Chapterg 6 81
Solutionsg tog Problemsg Chapterg 7 107
Solutionsg tog Problemsg Chapterg 8 121
Solutionsg tog Problemsg Chapterg 9 133
Solutionsg tog Problemsg Chapterg 10 153
Solutionsg tog Problemsg Chapterg 11 165
Solutionsg tog Problemsg Chapterg 12 177
, Sg g Og g Lg g Ug g Tg g Ig g Og g Ng g S Tg g O Pg g Rg g Og g Bg g Lg g Eg g Mg g S
Cg g Hg g Ag g Pg g Tg g Eg g R 2
1. Fromgproblemgstatement,gwegwantgtogfindg bP / T g . g g g
vg
g Usinggthegproduct-rule,
FGPIJ FGvIJ FGPIJ
g g g
H T K H T K H v K
g g
g
v
gg g
g g
g
g
P
g
g g
T
Byg definition,
F I
1g g vg
gP G J
v H T K
g g g
P
and
1g gv FI
T gg g
vg gPg H KJ
G T
Then,
F P I
g g g
g Pgg 1.8gg10
5
GH T K J 5.32gg10
6
g33.8gbargDC-1
g g
v
T
Integratingg theg aboveg equationg andg assumingg Pg andg Tg constantg overg theg temperatureg range
,gwegobtain
g
Pgg PggT
T
ForgTg=g1C,gwegget
Pgg33.8gbar
1
, 2 Solutionsg Manual
2. Giveng theg equationg ofg state, FV I g
PG bJ RT
Hn K gg
g
g
g
weg find:
FGS IJ FGPIJ nR g
gg g
g
g g
g g
H V K H T K V nb
g g
T
g g
V g g
FGS IJ FGV IJ nR
g
g
gg g
g
g gg
H P K H T K P
g g
T
g g
P
FGU IJ TFGPIJ P 0
g
g
g g g g
g
g g gg
H V K H T K
g g
T
g g
V
F U I F U I F V I
H PGK J HGV KJH GP K J 0
g g g
g gg g g g gg
g g g g g g g
T T T
FGH IJ TFGV IJV nb
g
g
g g g
g
g g g
H P K
g g HT K T
g g
Forg ang isothermalg change,
z
Sgg
V2g
Vg1
FGP IJ
HT K
g
g
g
g
V
V gnb
dVggnRglng 2g
V1ggnb
g P1
gnRglng
P2
Ug
z
LF U I GF VJI O dP 0
P2g
NMGH V JK HP K QP
P1g
g
g
g T
g
gg
g g
Tg g
g g
H g
zL F V I O
P2g
NMT GHT JK VPQdP nbbP P g
P 1g
g
g g
g
Pg g
g g gg 2g g 1
G H TS nbbP P g nRT ln G
gg gg gg
F P IJ g g g g g
g
g 1g
HP K 2 1
g 2g
F PI
A U TS nRT ln G
g 1g
gg
HP K
g g g g g
g g
J 2