www.PlusBay.Plus
,www.PlusBay.Plus
,Chapter 1: Arithmetic Needed for Dosage
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MULTIPLE CHOICE ty
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink
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15 oz. What portion of the water remained?
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a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A t y
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity
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(25 oz): 10 oz remain. To determine the portion of the water that remains, create a fraction by
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dividing 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25.
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To reduce fractions, find the largest number that can be divided evenly into the numerator and
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the denominator
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(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of
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2/5.
ty
Format: Multiple Choice ty ty
Chapter: 1
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Client Needs: Physiological Integrity: Basic Care and Comfort
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Cognitive Level: Apply
ty ty ty
Difficulty: Moderate ty
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
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Integrated Process: Teaching/Learning
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Objective: 1, 2 ty ty
2. A patient/client was prescribed 240 W
ty mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only
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100 mL. What portion of the Ensure remained?
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a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B t y
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available
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quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create
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a fraction by dividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140
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divided by 240 = 7/12. To reduce fractions, find the largest number that can be divided evenly
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into the numerator and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The
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fraction 140/240 can be reduced to its lowest terms of 7/12.
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Format: Multiple Choice ty ty
Chapter: 1
ty ty
Client Needs: Physiological Integrity: Basic Care and Comfort
ty ty ty ty ty ty ty
Cognitive Level: Apply
ty ty ty
Difficulty: Moderate ty
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
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Integrated Process: Teaching/Learning
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Objective: 1, 2 ty ty
1 |P a g ety ty ty ty ty
www.PlusBay.Plus
, 3. A patient/client consumed
ty oz. of coffee, 2/3 oz. of ice cream, and oz. of beef broth.
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What is the total number of ounces consumed that should be documented for the patient/client?
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a. 3 3/4 ty
b. 4 5/12 ty
c. 4 2/3 ty
d. 4 4/9 ty
ANS: B t y
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by
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multiplying the whole number by the denominator and then adding that total to the numerator. For
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the coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
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= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators,
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find the least common denominator (LCD). For 2, 3, and 4, the LCD =
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12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and
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then multiply that result by the numerator of the fraction. The new fractions to be added are
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27/12 (coffee), 8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the
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numerators are added together and the fraction is reduced to the lowest terms.
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Format: Multiple Choice ty ty
Chapter: 1
ty ty
Client Needs: Physiological Integrity: Basic Care and Comfort
ty ty ty ty ty ty ty
Cognitive Level: Analyze
ty ty ty
Difficulty: Difficult ty
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
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Integrated Process: Communication and Documentation
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Objective: 1, 2
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4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
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the nurse document as
ty ty ty
WWW.TBSM.WS
consumed?
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a. 360
b. 420
c. 510
d. 600
ANS: B t y
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number
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of milliliters consumed, multiply 180 7/3 (
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an improper fraction by multiplying the whole number by the denominator and then adding that
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total to
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the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 =
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420).
ty
Format: Multiple Choice ty ty
Chapter: 1
ty ty
Client Needs: Physiological Integrity: Basic Care and Comfort
ty ty ty ty ty ty ty
Cognitive Level: Analyze
ty ty ty
Difficulty: Difficult ty
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
ty ty ty ty ty ty ty ty
Integrated Process: Communication and Documentation
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Objective: 1, 2
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5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms
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were gained since admission?
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a. 0.78
b. 0.88
2 |P a g e
ty ty ty ty ty
www.PlusBay.Plus
,www.PlusBay.Plus
,Chapter 1: Arithmetic Needed for Dosage
ty ty ty ty ty
MULTIPLE CHOICE ty
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink
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15 oz. What portion of the water remained?
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a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A t y
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity
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(25 oz): 10 oz remain. To determine the portion of the water that remains, create a fraction by
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dividing 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25.
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
To reduce fractions, find the largest number that can be divided evenly into the numerator and
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
the denominator
ty ty
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of
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2/5.
ty
Format: Multiple Choice ty ty
Chapter: 1
ty ty
Client Needs: Physiological Integrity: Basic Care and Comfort
ty ty ty ty ty ty ty
Cognitive Level: Apply
ty ty ty
Difficulty: Moderate ty
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
ty ty ty ty ty ty ty ty
Integrated Process: Teaching/Learning
ty ty ty
Objective: 1, 2 ty ty
2. A patient/client was prescribed 240 W
ty mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only
ty ty ty ty ty ty ty ty ty ty
100 mL. What portion of the Ensure remained?
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a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B t y
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available
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quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
a fraction by dividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140
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divided by 240 = 7/12. To reduce fractions, find the largest number that can be divided evenly
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
into the numerator and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The
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fraction 140/240 can be reduced to its lowest terms of 7/12.
ty ty ty ty ty ty ty ty ty ty ty
Format: Multiple Choice ty ty
Chapter: 1
ty ty
Client Needs: Physiological Integrity: Basic Care and Comfort
ty ty ty ty ty ty ty
Cognitive Level: Apply
ty ty ty
Difficulty: Moderate ty
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
ty ty ty ty ty ty ty ty
Integrated Process: Teaching/Learning
ty ty ty
Objective: 1, 2 ty ty
1 |P a g ety ty ty ty ty
www.PlusBay.Plus
, 3. A patient/client consumed
ty oz. of coffee, 2/3 oz. of ice cream, and oz. of beef broth.
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What is the total number of ounces consumed that should be documented for the patient/client?
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a. 3 3/4 ty
b. 4 5/12 ty
c. 4 2/3 ty
d. 4 4/9 ty
ANS: B t y
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
multiplying the whole number by the denominator and then adding that total to the numerator. For
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the coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
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= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators,
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find the least common denominator (LCD). For 2, 3, and 4, the LCD =
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12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and
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then multiply that result by the numerator of the fraction. The new fractions to be added are
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
27/12 (coffee), 8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the
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numerators are added together and the fraction is reduced to the lowest terms.
ty ty ty ty ty ty ty ty ty ty ty ty ty
Format: Multiple Choice ty ty
Chapter: 1
ty ty
Client Needs: Physiological Integrity: Basic Care and Comfort
ty ty ty ty ty ty ty
Cognitive Level: Analyze
ty ty ty
Difficulty: Difficult ty
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
ty ty ty ty ty ty ty ty
Integrated Process: Communication and Documentation
ty ty ty ty ty
Objective: 1, 2
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4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
the nurse document as
ty ty ty
WWW.TBSM.WS
consumed?
ty
a. 360
b. 420
c. 510
d. 600
ANS: B t y
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
of milliliters consumed, multiply 180 7/3 (
ty ty ). When a mixed number is present, change it to
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
an improper fraction by multiplying the whole number by the denominator and then adding that
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
total to
ty ty
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 =
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420).
ty
Format: Multiple Choice ty ty
Chapter: 1
ty ty
Client Needs: Physiological Integrity: Basic Care and Comfort
ty ty ty ty ty ty ty
Cognitive Level: Analyze
ty ty ty
Difficulty: Difficult ty
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
ty ty ty ty ty ty ty ty
Integrated Process: Communication and Documentation
ty ty ty ty ty
Objective: 1, 2
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5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms
ty ty ty ty ty ty ty ty ty ty ty ty ty ty
were gained since admission?
ty ty ty ty
a. 0.78
b. 0.88
2 |P a g e
ty ty ty ty ty
www.PlusBay.Plus
