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O Chem 331 Exam 4 Final Exam Questions and All Correct Answers.

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How to make C-C bond for synthesis problems - Answer start with alkyne deprotonate (add strong base, usually NaNH2) add alkyl halide How to make cis alkene from alkyne - Answer H2 and Lindlars catalyst How to make trans alkene from alkyne - Answer Na metal in liquid NH3 alkene hydrogenation - Answer - h2 and metal (pd/pt) -break pi bond, add H to each carbon -syn addition alkene hydrohalogenation-- just HX - Answer - HX (HCl, HBr) - break pi bond, put H on less substituted carbon (C) - carbocation forms at more substituted C -be careful of hydride shift and carbocation rearrangement -halogen (X) adds to most substituted C alkene hydrohalogenation-- HX in ROOR - Answer - anti markov - break pi bond, add X to less substituted C - add H to more sub. C alkene Halogenation - Answer - X2 in non reactive solvent (CH2Cl, etc) - break pi bond, put X on both Cs that were in bond - anti: add X to different faces alkene halohydrin - Answer -X2 in reactive solvent (H2O) -add X to less sub. C - cut off one H from solvent and add the rest to more sub. C side Alkene Acid catalyzed hydration - Answer -H2O; React in aqueous sulfuric acid, make alcohol

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O Chem 331 Exam 4 Final Exam
Questions and All Correct Answers.
How to make C-C bond for synthesis problems - Answer start with alkyne

deprotonate (add strong base, usually NaNH2)

add alkyl halide



How to make cis alkene from alkyne - Answer H2 and Lindlars catalyst



How to make trans alkene from alkyne - Answer Na metal in liquid NH3



alkene hydrogenation - Answer - h2 and metal (pd/pt)

-break pi bond, add H to each carbon

-syn addition



alkene hydrohalogenation-- just HX - Answer - HX (HCl, HBr)

- break pi bond, put H on less substituted carbon (C)

- carbocation forms at more substituted C

-be careful of hydride shift and carbocation rearrangement

-halogen (X) adds to most substituted C



alkene hydrohalogenation-- HX in ROOR - Answer - anti markov

- break pi bond, add X to less substituted C

- add H to more sub. C



alkene Halogenation - Answer - X2 in non reactive solvent (CH2Cl, etc)

- break pi bond, put X on both Cs that were in bond

- anti: add X to different faces



alkene halohydrin - Answer -X2 in reactive solvent (H2O)

-add X to less sub. C

- cut off one H from solvent and add the rest to more sub. C side



Alkene Acid catalyzed hydration - Answer -H2O; React in aqueous sulfuric acid, make alcohol

-break pi bond, add H to less sub. C

, -carbocation intermediate forms on more sub C, rearrange if needed

- OH added to C that had final carbocation placement



alkene oxymercuration - Answer -Hg(OAC)2, H20 in NaBH4

- markovnikov but no carbocation intermediate

- break pi bond add H to less sub C

-add OH to more sub C

-if showing chirality, add H and OH to different faces



alkene alkoxymercuration - Answer - Hg(OAc)2, ROH in NaBH4

-break pi bond, add H to less sub C

- add O-R to more sub. C

- if showing chirality, add H and OR to different faces



alkene Hydroboration - Answer - BH3, THF and NaOH/H2O2/H2O

- break pi, add H to more sub C

- add OH to less sub C

- syn addition



alkene epoxidation - Answer - Extra O in reactant (mPCBA, RCO3H)

-break pi bond in the middle, add an O in between both C to make 3 member ring

-if reacting with H3O+ too, add OH to both C in the bond (anti addition)



Alkene Dihydroxylation - Answer - strong oxidizing agent, weak conditions (KMnO4,
cold/dilute)

- or OsO4

- break pi bond, add OH to each C, syn



alkene oxidative cleavage- KMnO4, hot conditions - Answer - spilt pi bond down middle, add
O to both sides of the break

- other side of break becomes carboxylic acid



alkene ozonolysis- reductive conditions - Answer - O3, DMS [ (CH3)2S ]

- cleave pi bond, add O to less sub. C

- add H to more sub. C

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