Portage Learning Chemistry CHEM 103 Unit 5
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1. As33 (nonmetal = gain electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3
gain 3 ’ As-3
Ge32 (metal = lose electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2
lose 4 ’ Ge+4: What will be the charge of the ion formed from each of these atoms? Explain your answer.
As33, Ge32
2. 1) Cl-O bond electronegativity difference = 3.5 - 3.0 = 0.5
(1.6 - 0.5 bond is Polar)
H-O bond electronegativity difference = 3.5 - 2.1 = 1.4
(1.6 - 0.5 bond is Polar)
2) Ca N bond electronegativity difference = 3.0 - 2.5 = 0.5
(1.6 - 0.5 bond is Polar)
H-C bond electronegativity difference = 2.5 - 2.1 = 0.4
(< 0.5 bond is Nonpolar): Using the electronegativity values from the equation bank, show the determina-
tion of the polarity of each different type of bond in the following molecules:
3. Your Answer:
NH3
N = 5, H = 3, 8 total
H
..
H:N:H
..
SO2
S = 6, O = 12, total = 18
.. .. ..
: O : S :: O
.. ..
CH3OH
C = 4, H = 4, O = 6, total = 14
H
1/5
, Portage Learning Chemistry CHEM 103 Unit 5
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.. ..
H:C:O:H
.. ..
H
HNO2
H = 1, N = 5, O = 12, total = 18
.. .. ..
H:O:N::O:
..
N2
N = 10
: N ::: N :
CH2O
C = 4, H = 2, O = 6, total = 12
.. ..
H : C :: O : H: Write Lewis dot structures for the following molecules:
NH3
SO2
CH3OH
HNO2
N2
CH2O
4. 1.) PH3 4 Groups of electrons around P = Tetrahedral Electron Geometry
Tetrahedral Electron Geometry = sp3 Hybridization of P
3 atoms around central Tetrahedral atom = Triangular pyramid shape
P-H bond (2.1-2.1) is nonpolar = all nonpolar bonds = Nonpolar molecular
polarity
2.) HCN 2 Groups of electrons around C = Linear Electron Geometry
Linear Electron Geometry = sp Hybridization of C
2 atoms around central Linear atom = Linear shape
2/5
Study online at https://quizlet.com/_d8619w
1. As33 (nonmetal = gain electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3
gain 3 ’ As-3
Ge32 (metal = lose electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2
lose 4 ’ Ge+4: What will be the charge of the ion formed from each of these atoms? Explain your answer.
As33, Ge32
2. 1) Cl-O bond electronegativity difference = 3.5 - 3.0 = 0.5
(1.6 - 0.5 bond is Polar)
H-O bond electronegativity difference = 3.5 - 2.1 = 1.4
(1.6 - 0.5 bond is Polar)
2) Ca N bond electronegativity difference = 3.0 - 2.5 = 0.5
(1.6 - 0.5 bond is Polar)
H-C bond electronegativity difference = 2.5 - 2.1 = 0.4
(< 0.5 bond is Nonpolar): Using the electronegativity values from the equation bank, show the determina-
tion of the polarity of each different type of bond in the following molecules:
3. Your Answer:
NH3
N = 5, H = 3, 8 total
H
..
H:N:H
..
SO2
S = 6, O = 12, total = 18
.. .. ..
: O : S :: O
.. ..
CH3OH
C = 4, H = 4, O = 6, total = 14
H
1/5
, Portage Learning Chemistry CHEM 103 Unit 5
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.. ..
H:C:O:H
.. ..
H
HNO2
H = 1, N = 5, O = 12, total = 18
.. .. ..
H:O:N::O:
..
N2
N = 10
: N ::: N :
CH2O
C = 4, H = 2, O = 6, total = 12
.. ..
H : C :: O : H: Write Lewis dot structures for the following molecules:
NH3
SO2
CH3OH
HNO2
N2
CH2O
4. 1.) PH3 4 Groups of electrons around P = Tetrahedral Electron Geometry
Tetrahedral Electron Geometry = sp3 Hybridization of P
3 atoms around central Tetrahedral atom = Triangular pyramid shape
P-H bond (2.1-2.1) is nonpolar = all nonpolar bonds = Nonpolar molecular
polarity
2.) HCN 2 Groups of electrons around C = Linear Electron Geometry
Linear Electron Geometry = sp Hybridization of C
2 atoms around central Linear atom = Linear shape
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