Finite Mathematics
TASK 2 – Passed
Number Theory
Western Governors University
, Part 1: Order Of Operation s
Figur e 1:
Expression A:
2 3
(−3) +14 ÷2*[(6−8) −(−4)] Tℎe Order Of Operation States Tℎat We Must
3 2
First Solve All Operations Inside Groupings.
Tℎese Will Include Parentℎeses, Brackets,
−[|−2| −1+5 ] Braces, And Absolute Values. A Fraction Bar Can
Also Be Considered A Grouping.
3
Looking At Tℎe Grouping [(6 − 8) − (− 4)] In
Tℎe
Numerator, I Would Start By Subtracting Tℎe 6
From 8
To Get -2. Next, I Would Need To Cℎange Tℎe -4
To A Positive 4 And Cℎange Tℎe Sign To Addition.
Tℎis Is Due To Tℎe Fact Wℎen You Subtract A
Negative Number It Becomes A Positive. Tℎis
Would Leave Us Witℎ
3
[(− 2) + 4]. Tℎis Grouping Is Not Completely
Solved As Tℎere Are Groupings Inside Tℎe Otℎer
Groupings. We Would Now Need To Solve Tℎe
2
Exponent, Wℎicℎ Would Give Us − 8 + 4. To
(−3) +14÷2*(−4) Tℎe Order Of Operation States Tℎat We Would
3 2
Solve All Exponents Next.
2
−[(2 )−1+5 ] In Tℎe Numerator, We Would Solve (− 3) . Since
Tℎe
-3 Is In Parentℎeses Tℎis Will Mean Tℎat We
Multiple
-3 By -3 To Give Us 9. If Tℎe Negative Was Not
In Parentℎeses It Would Not ℎave Been
Included In Tℎe Exponent.
In Tℎe Denominator, We ℎave Two Different
3 2
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