RADIO FREQUENCY
INTERGRATED CIRCUITS
SYSTEMS SOLUTION
MANUAL BY HOOMAN
DARABI LATEST UPDATE.
, Radio Frequency Integrated
Circuits and Systems
Solution Manual
Hooman Darabi
Solutions to Problem Sets
The selected solutions to all 12 chapters problem sets are presented in this manual. The
problem sets depict examples of practical applications of the concepts described in the book,
more detailed analysis of some of the ideas, or in some cases present a new concept.
Note that selected problems have been given answers already in the book.
,1 Chapter One
1. Using spherical coordinates, find the capacitance formed by two concentric spherical
conducting shells of radius a, and b. What is the capacitance of a metallic marble with a
diameter of 1cm in free space? Hint: let 𝑏 → ∞, thus, 𝐶 = 4𝜋 0𝑎 = 0.55𝑝𝐹.
Solution: Suppose the inner sphere has a surface charge density of +𝜌𝑆. The outer surface
charge density is negative, and proportionally smaller (by (𝑎/𝑏)2) to keep the total charge
the same.
-
+
+ S
- + a + -
b
+
-
From Gauss’s law:
ф𝐷 ⋅ 𝑑𝑆 = 𝑄𝑄 = +𝜌𝑆4𝜋𝑎2
Thus, inside the
sphere
, Assuming a potential of 𝑉0 between the inner we have:
𝑏 𝜖 𝑟2 𝜖 𝑎 𝑏
Thus:
1
In the case of a metallic marble, 𝑏 → ∞, and hence: 𝐶 = 4𝜋 0 𝑎. Letting 0 = ×
36𝜋
10−9, and 𝑎 = 0.5𝑐𝑚, it yields .
2. Consider the parallel plate capacitor containing two different dielectrics. Find the total
capacitance as a function of the parameters shown in the figure.
Area: A
1
2
ck
INTERGRATED CIRCUITS
SYSTEMS SOLUTION
MANUAL BY HOOMAN
DARABI LATEST UPDATE.
, Radio Frequency Integrated
Circuits and Systems
Solution Manual
Hooman Darabi
Solutions to Problem Sets
The selected solutions to all 12 chapters problem sets are presented in this manual. The
problem sets depict examples of practical applications of the concepts described in the book,
more detailed analysis of some of the ideas, or in some cases present a new concept.
Note that selected problems have been given answers already in the book.
,1 Chapter One
1. Using spherical coordinates, find the capacitance formed by two concentric spherical
conducting shells of radius a, and b. What is the capacitance of a metallic marble with a
diameter of 1cm in free space? Hint: let 𝑏 → ∞, thus, 𝐶 = 4𝜋 0𝑎 = 0.55𝑝𝐹.
Solution: Suppose the inner sphere has a surface charge density of +𝜌𝑆. The outer surface
charge density is negative, and proportionally smaller (by (𝑎/𝑏)2) to keep the total charge
the same.
-
+
+ S
- + a + -
b
+
-
From Gauss’s law:
ф𝐷 ⋅ 𝑑𝑆 = 𝑄𝑄 = +𝜌𝑆4𝜋𝑎2
Thus, inside the
sphere
, Assuming a potential of 𝑉0 between the inner we have:
𝑏 𝜖 𝑟2 𝜖 𝑎 𝑏
Thus:
1
In the case of a metallic marble, 𝑏 → ∞, and hence: 𝐶 = 4𝜋 0 𝑎. Letting 0 = ×
36𝜋
10−9, and 𝑎 = 0.5𝑐𝑚, it yields .
2. Consider the parallel plate capacitor containing two different dielectrics. Find the total
capacitance as a function of the parameters shown in the figure.
Area: A
1
2
ck
