CHM 113 EXAM SCRIPT 2026 FULL QUESTIONS
AND CORRECT ANSWERS ALREADY PASSED
◉ Specific Gravity. Answer: the ratio of the density of the substance to
the density of water
◉ Intensive Property. Answer: physical property not dependent on the
size of the sample
◉ Extensive Property. Answer: depends on the size of the sample
◉ For a piece of wood having:
Length = 10.35 cm
Width = 6.42 cm
Height = 1.90 cm
Mass = 72.412 g
Calculate the density. Answer: d = m/v
d = (72.412)/(10.35*6.45*1.90)
d = 0.571 g/cm^3
◉ A cylinder has:
,diameter = 1.28 cm
height = 3.85 cm
mass = 39.730 g
What is its density?. Answer: d = 39.730/4.954
d = 8.019 g/cm^3
◉ A rock weighs:
143 g in air
82 g in H2O
mass displaced?
volume H2O displaced?
density?. Answer: V = 61g/cm^3
1. 61g
2. 61g
3. 143/61 = 2.344 g/cm^3
◉ A graduated cylinder weighs 28.102 g. A solution has been created
which levitates a piece of PVC. The graduated cylinder containing 6.25
mL of that solution weighs 34.200 g. Density?. Answer: d = (34.200 -
28.102)/6.25
◉ Increasing denisty. Answer: 1 - gas
2 - liquid
, 3 - solid
◉ Increasing density of H2O. Answer: 1 - gas
2 - solid
3 - liquid
◉ If an object has a density of 0.5g/mL, will it float or sink when placed
in water? Why?. Answer: It will float in water because it is less dense
than water which has a density of 1g/mL
◉ A rock has a mass of 20g in air, and 10g in water. Density of the
rock?. Answer: d = 20/10
d = 2g/cm^3
◉ If a 10 mL solution with a density of 1.5g/mL levitates a 1 g piece
PVC, what is the density of the PVC?. Answer: density of PVC =
density of solution
◉ A cylinder has a diameter of 1.6mm, a height of 2 cm and a mass of
50 g. Density?. Answer: d = 50/0.0402
d = 1243.78 g/cm^3
◉ Units of density. Answer: g/cm^3 or g/mL
AND CORRECT ANSWERS ALREADY PASSED
◉ Specific Gravity. Answer: the ratio of the density of the substance to
the density of water
◉ Intensive Property. Answer: physical property not dependent on the
size of the sample
◉ Extensive Property. Answer: depends on the size of the sample
◉ For a piece of wood having:
Length = 10.35 cm
Width = 6.42 cm
Height = 1.90 cm
Mass = 72.412 g
Calculate the density. Answer: d = m/v
d = (72.412)/(10.35*6.45*1.90)
d = 0.571 g/cm^3
◉ A cylinder has:
,diameter = 1.28 cm
height = 3.85 cm
mass = 39.730 g
What is its density?. Answer: d = 39.730/4.954
d = 8.019 g/cm^3
◉ A rock weighs:
143 g in air
82 g in H2O
mass displaced?
volume H2O displaced?
density?. Answer: V = 61g/cm^3
1. 61g
2. 61g
3. 143/61 = 2.344 g/cm^3
◉ A graduated cylinder weighs 28.102 g. A solution has been created
which levitates a piece of PVC. The graduated cylinder containing 6.25
mL of that solution weighs 34.200 g. Density?. Answer: d = (34.200 -
28.102)/6.25
◉ Increasing denisty. Answer: 1 - gas
2 - liquid
, 3 - solid
◉ Increasing density of H2O. Answer: 1 - gas
2 - solid
3 - liquid
◉ If an object has a density of 0.5g/mL, will it float or sink when placed
in water? Why?. Answer: It will float in water because it is less dense
than water which has a density of 1g/mL
◉ A rock has a mass of 20g in air, and 10g in water. Density of the
rock?. Answer: d = 20/10
d = 2g/cm^3
◉ If a 10 mL solution with a density of 1.5g/mL levitates a 1 g piece
PVC, what is the density of the PVC?. Answer: density of PVC =
density of solution
◉ A cylinder has a diameter of 1.6mm, a height of 2 cm and a mass of
50 g. Density?. Answer: d = 50/0.0402
d = 1243.78 g/cm^3
◉ Units of density. Answer: g/cm^3 or g/mL
