2026 TESU Physics 116 Final Exam New Latest Version
with All the Questions and answers
FORMULAS YOU MUST KNOW BY HEART
Motion
• v=v0+atv = v_0 + atv=v0+at
• x=x0+v0t+12at2x = x_0 + v_0 t + \frac{1}{2}at^2x=x0+v0t+21at2
• v2=v02+2aΔxv^2 = v_0^2 + 2a\Delta xv2=v02+2aΔx
Forces
• F=maF = maF=ma
• Ff=μNF_f = \mu NFf=μN
• W=mgW = mgW=mg
Energy
• KE=12mv2KE = \frac{1}{2}mv^2KE=21mv2
• PE=mghPE = mghPE=mgh
• W=FdcosθW = Fd\cos\thetaW=Fdcosθ
Momentum
• p=mvp = mvp=mv
• ∑pbefore=∑pafter\sum p_{before} = \sum p_{after}∑pbefore=∑pafter
Circular Motion
• Fc=mv2rF_c = \frac{mv^2}{r}Fc=rmv2
, • ac=v2ra_c = \frac{v^2}{r}ac=rv2
MOST-TESTED & HARDEST QUESTIONS (1–20)
1. A car accelerates from rest at 4 m/s² for 5 seconds. How far does it travel?
A. 25 m
B. 50 m
C. 75 m
D. 100 m
✅ Correct Answer: B
Explanation
Use:
x=12at2=12(4)(52)=50 mx = \frac{1}{2}at^2 = \frac{1}{2}(4)(5^2) = 50 \text{ m}x=21at2=21(4)(52)=50 m
2. Which graph represents constant velocity?
A. Curved position-time graph
B. Straight sloped position-time graph
C. Horizontal velocity-time graph
D. Sloped velocity-time graph
✅ Correct Answer: B
Trap: Constant velocity ≠ flat position graph
It means constant slope.
3. A net force of 10 N acts on a 2-kg mass. What is the acceleration?
A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²
✅ Correct Answer: B
a=Fm=102=5a = \frac{F}{m} = \frac{10}{2} = 5a=mF=210=5
4. Which situation best demonstrates Newton’s 3rd Law?
with All the Questions and answers
FORMULAS YOU MUST KNOW BY HEART
Motion
• v=v0+atv = v_0 + atv=v0+at
• x=x0+v0t+12at2x = x_0 + v_0 t + \frac{1}{2}at^2x=x0+v0t+21at2
• v2=v02+2aΔxv^2 = v_0^2 + 2a\Delta xv2=v02+2aΔx
Forces
• F=maF = maF=ma
• Ff=μNF_f = \mu NFf=μN
• W=mgW = mgW=mg
Energy
• KE=12mv2KE = \frac{1}{2}mv^2KE=21mv2
• PE=mghPE = mghPE=mgh
• W=FdcosθW = Fd\cos\thetaW=Fdcosθ
Momentum
• p=mvp = mvp=mv
• ∑pbefore=∑pafter\sum p_{before} = \sum p_{after}∑pbefore=∑pafter
Circular Motion
• Fc=mv2rF_c = \frac{mv^2}{r}Fc=rmv2
, • ac=v2ra_c = \frac{v^2}{r}ac=rv2
MOST-TESTED & HARDEST QUESTIONS (1–20)
1. A car accelerates from rest at 4 m/s² for 5 seconds. How far does it travel?
A. 25 m
B. 50 m
C. 75 m
D. 100 m
✅ Correct Answer: B
Explanation
Use:
x=12at2=12(4)(52)=50 mx = \frac{1}{2}at^2 = \frac{1}{2}(4)(5^2) = 50 \text{ m}x=21at2=21(4)(52)=50 m
2. Which graph represents constant velocity?
A. Curved position-time graph
B. Straight sloped position-time graph
C. Horizontal velocity-time graph
D. Sloped velocity-time graph
✅ Correct Answer: B
Trap: Constant velocity ≠ flat position graph
It means constant slope.
3. A net force of 10 N acts on a 2-kg mass. What is the acceleration?
A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²
✅ Correct Answer: B
a=Fm=102=5a = \frac{F}{m} = \frac{10}{2} = 5a=mF=210=5
4. Which situation best demonstrates Newton’s 3rd Law?
