SCIENCE FINAL EXAM — 2026/2027 | 100
QUESTIONS AND CORRECT ANSWERS |
GRADED A+ | 100% VERIFIED
CSC 126 – Introduction to Computer Science Final Examination | Core Domains: Programming Fundamentals, Algorithms & Problem
Solving, Data Types & Structures, Control Structures (Conditionals & Loops), Functions & Methods, Object-Oriented Programming
Basics, Arrays & Collections, Input/Output Operations, Recursion, Searching & Sorting Algorithms, Complexity Analysis (Big O
Notation), Software Development Life Cycle, Debugging & Testing, Pseudocode & Flowcharts, and Introductory Computational
Thinking | Undergraduate Computer Science Focus | Exam-Aligned Format
Exam Structure
CSC 126 Introduction to Computer Science Final Exam is commonly structured as follows:
100 total questions
Multiple-choice questions
Single-best-answer format
Application-, analysis-, and logic-based items
Code snippet analysis and debugging scenarios
Algorithm tracing and output prediction
Pseudocode interpretation
Comprehensive coverage of foundational computer science principles
Content Areas Covered
The exam questions are distributed across the following core domains:
Content Area Question Range Assigned Questions
Programming Fundamentals 12-16 questions 14
Data Types and Structures 10-14 questions 12
Control Structures (Conditionals & Loops) 12-16 questions 14
Functions and Methods 10-14 questions 12
Object-Oriented Programming Basics 8-12 questions 10
Algorithms and Problem Solving 10-14 questions 12
Searching and Sorting 8-12 questions 10
Complexity Analysis 6-10 questions 8
Arrays and Collections 8-12 questions 10
Software Development Concepts 6-8 questions 7
Error Handling and Debugging 4-6 questions 5
, Content Area Question Range Assigned Questions
Computational Thinking 4-6 questions 6
Programming Language Context
While CSC 126 focuses on foundational concepts applicable across languages, questions may reference common instructional
languages including Python, Java, C++, or pseudocode. Students should be prepared to interpret code snippets in a language-
agnostic manner, focusing on logic and structure rather than language-specific syntax variations.
Introduction & Answer Format
This CSC 126 Introduction to Computer Science Final Exam for the 2026/2027 academic cycle reflects comprehensive computer
science curriculum standards for undergraduate introductory programs. The examination evaluates foundational understanding of
programming principles, algorithmic thinking, data structures, problem-solving methodologies, and computational concepts
required for success in advanced computer science courses and software development pathways.
All correct answers must be presented in bold and green, followed by clearly defined, technically accurate rationales that reinforce
computer science principles, algorithmic logic, programming best practices, and computational thinking strategies.
Programming Fundamentals (Questions 1-14)
1. Which of the following is considered a low-level programming language directly executable by a computer's CPU
without a translator program?
A. Python
B. Java
C. Assembly Language
D. C++
Correct Answer: C. Assembly Language
Rationale: Assembly language is a low-level programming language that directly corresponds to the machine code instructions
of a particular computer architecture. It is typically translated into machine code by an assembler, which is a near one-to-one
mapping to CPU instructions.
, 2. What is the primary purpose of a 'compiler' in the software development process?
A. To execute a program line by line.
B. To translate source code directly into machine code before execution.
C. To manage memory allocation during runtime.
D. To identify and report syntax errors as they occur during typing.
Correct Answer: B. To translate source code directly into machine code before execution.
Rationale: A compiler translates an entire program's source code into executable machine code (or an intermediate bytecode)
before the program runs. This contrasts with an interpreter, which executes code line by line.
3. Consider the following pseudocode:
DECLARE num1 = 10
DECLARE num2 = 5
DECLARE result
result = num1 + num2 * 2
PRINT result
What is the predicted output?
A. 30
B. 20
C. 25
D. 15
Correct Answer: B. 20
Rationale: According to operator precedence (PEMDAS/BODMAS), multiplication is performed before addition. So, `num2 * 2` (5
* 2 = 10) is calculated first, then `10 + 10 = 20`.