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Chem 104 Exam 1 Study Guide

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General Overlay: Topic 8, 9, 10, 11, 12, 13

Topic 8: Heat and Work

Video A: Energy In Reactions
●​ Chemical reactions are based on changes in ENERGY as bonds are broken and formed.
●​ Energy cannot be created or destroyed and can be transferred from one body to
another.
●​ Exothermic: release energy during a chemical reaction to form bonds
○​ Energy transferred out of the system to the surroundings.
○​ Potential energy decreases
○​ Surroundings gain energy
○​ Heat is a product
●​ Endothermic: gain energy during a chemical reaction to break bonds
○​ Energy is transferred into the system
○​ Potential energy increases
○​ Surroundings lose energy
○​ Heat is a reactant
●​ Heat of a chemical reaction (q) is due to the change in potential energy or in other words
the making and breaking of bonds.
Heat = q = ΔH (change in enthalpy)
●​ Enthalpy: how much energy is released/absorbed within a reaction.
ΔH ﹤0 = Exothermic
ΔH ﹥0 = Endothermic
●​ The net ΔHrxn depends on the strength of the bonds that are broken and the bonds that
are formed.
ΔHrxn= ΔHformed + ΔHbroken
○​ For most reactions we cannot predict ΔHrxn by simply looking at the reaction.
Exothermic: ​ ​ ​ ​ ​ ​ ​ ​ Endothermic:
|ΔHformed| ﹥ ΔHbroken ​ ​ ​ ​ ​ ​ ​ |ΔHformed| ﹤ΔHbroken

Video B: First Law of Thermodynamics

●​ The only way to make a system experience change in its energy is through the process
of energy transfer to or from the surroundings as either heat or work.
ΔEsystem = KEAVE + PEAVE

PEAVE = interactions between molecules, intermolecular forces and bonding interactions
KEAVE = motion

●​ Internal energy of the system is the sum of the average kinetic energy and the average
potential energy of the molecules in the system.
●​ For the Universe: ΔE = 0

, ●​ There are two different ways to change the energy of the system
○​ Heat: random motion of particles in multiple directions
○​ Work: motion against an opposing force and causes matter to move
●​ Work is creating a force acting over a distance.
●​ Heat is when energy is lost/dissipated and there is no work.
●​ Work and heat represents the transfer of energy.
ΔE = q+w
●​ We track ENERGY transfer between a system and its surroundings


Work Heat

Work done by the surroundings Heat into the system
W﹥0 Q﹥0
Energy of the system increases Energy of the system increases

Work done by the system Heat out of the system
W﹤0 Q﹤0
Energy of the system decreases Energy of the system decreases


Video C: Pressure-Work Volume




Review: Ideal Gas Postulates
1)​ Gas molecules have no volume of their own.
2)​ Gas molecules are perfectly elastic collisions and are in constant linear motion.
3)​ Gas molecules experience no intermolecular forces acting between one another.
4)​ The Kinetic Energy of an ideal gas is directly proportional to its temperature measured in
degrees K.

Equations: PV = nRT
​ R = 0.082 L-atm/mol-K
Internal Energy to Temperature
​ KE = (3/2) nRT
​ KEMolar = (3/2) RT
Any collection of gases at same temperature have the same KE molar.




●​ Work due to the expansion or compression of gas (PV work) is equal to the negative
external pressure of gas (Pexternal) times the change in volume of gas (ΔV).
WPV = - (Pexternal) ((ΔV)

, ●​ For any gas compression: ΔV ﹤0
○​ When a gas expands (more moles of gas on product side) its volume increases.
It pushes against an external pressure and its energy goes down.
○​ Work is being done to the gas; work must be positive (w > 0).
●​ For any gas expansion: ΔV﹥0
○​ When a gas is compressed (less moles of gas on the product side) its volume
decreases. An external force pushes on the gas and its energy goes up.
○​ Work is being done by the gas; work must be negative (w < 0).

Video D: Calorimetry Calculation (1 system problem)
●​ Calorimetry: measures heat of a reaction at constant temperature in ℃.
○​ Heat: process for the transfer of energy
○​ Temperature: internal kinetic energy of the system.
●​ Specific Heat Capacity: energy required to raise the temperature of 1 gram of a
substance by 1 ℃ or in other words, how much energy is required to change the
temperature of a substance.
C = J/(g x deg) or Cal/(g x deg)

Equation for Calorimetry: ​ ​ ​
Q = mcΔT

T = temperature
m = mass of a substance
c = specific heat capacity

●​ Substances with small heat capacity values heat up very quickly (e.g metals)
●​ Substances with high heat capacity values will need a lot of heat to raise the
temperature of that substance.
●​ The specific heat capacity of water is 4.184 J/(g・deg)
●​ When energy is absorbed by the system as heat, q is positive.
●​ When energy is released by the system as heat, q is negative.

HOW TO APPROACH 1-SYSTEM CALORIMETRY CALCULATION
●​ List out the variables given, m (mass), c (specific heat), ΔT ( Tf - Ti), q (heat in Joules)
●​ Isolate the variable that is being asked for and solve.

Sample Problem:

1.​ If I have 32 grams of unknown metal ( c= 3.68 J/(℃-g) ) at 25 ℃ and I transfer 120 of
energy to the metal, what is the new temperature?
m= 32 grams
c= 3.68 J/(℃-g)
ΔT= ?

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