PRINCIPLES OF PHYSICS, EXTENDED, INTERNA ONAL
ADAPTA ON,
12TH EDI ON HALLIDAY & RESNICK CHAPTER 1 - 44 +
ANSWER KEYS
SOLUTION MANUAL
,ANSWER KEYS AT PAGE 1860
Table of Contents
1 Measurement
2 Mo on Along a Straight
Line 3 Vectors
4 Mo on in Two and Three
Dimensions 5 Force and Mo on--I
6 Force and Mo on--II
7 Kine c Energy and Work
8 Poten al Energy and Conserva on of
Energy 9 Center of Mass and Linear
Momentum
10 Rota on
11 Rolling, Torque, and Angular
Momentum 12 Equilibrium and Elas city
13 Gravita on
14 Fluids
15 Oscilla ons
16 Waves--I
17 Waves--II
18 Temperature, Heat, and the First Law of
Thermodynamics 19 The Kine c Theory of Gases
20 Entropy and the Second Law of Thermodynamics
,
21 Coulomb's Law
22 Electric Fields
23 Gauss' Law
24 Electric Poten al
25 Capacitance
26 Current and
Resistance 27 Circuits
28 Magne c Fields
29 Magne c Fields Due to
Currents 30 Induc on and
Inductance
31 Electromagne c Oscilla ons and Alterna ng
Current 32 Maxwell's Equa ons; Magne sm of Ma?er
33 Electromagne c Waves
34 Images
35 Interference
36 Diffrac on
37 Rela vity
38 Photons and Ma?er
Waves 39 More About
Ma?er Waves 40 All About
Atoms
41 Conduc on of Electricity in Solids
42 Nuclear Physics
43 Energy from the Nucleus
44 Quarks, Leptons, and the Big Bang
, Chapter 1
1. THINK In this problem we’re given the radius of Earth, and asked to compute its
circumference, surface area and volume.
EXPRESS Assuming Earth tobe a sphere ofradius
3
RE .37 10 km m
6 6
m 10 6.37 103 km,
the corresponding circumference, surface area and volume are:
2 4 3
C 2 R , A 4 R, V R .
E E E
The geometric formulas are given in Appendix E. 3
ANALỴZE (a) Using the formulas given above, we find the circumference tobe
C 2 RE 2 (6.37 103 km) 4.00 104 km.
(b) Similarlỵ, the surface area of Earth is
5.10 108 km2 ,
2
A 4 RE2 4 103 km
6.37
(c) and its volume is
4 4 3
V R3 6.37 103 km 1.08 1012 km3.
E
3 3
2 3
LEARN From the formulas given, we see that C RE , A RE , and V RE . The ratios
of volume to surface area, and surface area to circumference are V / A RE / 3 and
A / C 2RE .
2
. The conversion factors are: 1 grỵ 1/10 line , 1 line 1/12 inch and 1 point = 1/72 inch.
The factors implỵ that
1 grỵ = (1/10)(1/12)(72 points) = 0.60 point.
Thus, 1 grỵ2 = (0.60 point)2 = 0.36 point2, which means that 0.50 grỵ2 = 0.18 point 2 .
3. The metric prefixes (micro, pico, nano, …) are given for readỵ reference on the inside front
cover of the textbook (see also Table 1–2).
1
ADAPTA ON,
12TH EDI ON HALLIDAY & RESNICK CHAPTER 1 - 44 +
ANSWER KEYS
SOLUTION MANUAL
,ANSWER KEYS AT PAGE 1860
Table of Contents
1 Measurement
2 Mo on Along a Straight
Line 3 Vectors
4 Mo on in Two and Three
Dimensions 5 Force and Mo on--I
6 Force and Mo on--II
7 Kine c Energy and Work
8 Poten al Energy and Conserva on of
Energy 9 Center of Mass and Linear
Momentum
10 Rota on
11 Rolling, Torque, and Angular
Momentum 12 Equilibrium and Elas city
13 Gravita on
14 Fluids
15 Oscilla ons
16 Waves--I
17 Waves--II
18 Temperature, Heat, and the First Law of
Thermodynamics 19 The Kine c Theory of Gases
20 Entropy and the Second Law of Thermodynamics
,
21 Coulomb's Law
22 Electric Fields
23 Gauss' Law
24 Electric Poten al
25 Capacitance
26 Current and
Resistance 27 Circuits
28 Magne c Fields
29 Magne c Fields Due to
Currents 30 Induc on and
Inductance
31 Electromagne c Oscilla ons and Alterna ng
Current 32 Maxwell's Equa ons; Magne sm of Ma?er
33 Electromagne c Waves
34 Images
35 Interference
36 Diffrac on
37 Rela vity
38 Photons and Ma?er
Waves 39 More About
Ma?er Waves 40 All About
Atoms
41 Conduc on of Electricity in Solids
42 Nuclear Physics
43 Energy from the Nucleus
44 Quarks, Leptons, and the Big Bang
, Chapter 1
1. THINK In this problem we’re given the radius of Earth, and asked to compute its
circumference, surface area and volume.
EXPRESS Assuming Earth tobe a sphere ofradius
3
RE .37 10 km m
6 6
m 10 6.37 103 km,
the corresponding circumference, surface area and volume are:
2 4 3
C 2 R , A 4 R, V R .
E E E
The geometric formulas are given in Appendix E. 3
ANALỴZE (a) Using the formulas given above, we find the circumference tobe
C 2 RE 2 (6.37 103 km) 4.00 104 km.
(b) Similarlỵ, the surface area of Earth is
5.10 108 km2 ,
2
A 4 RE2 4 103 km
6.37
(c) and its volume is
4 4 3
V R3 6.37 103 km 1.08 1012 km3.
E
3 3
2 3
LEARN From the formulas given, we see that C RE , A RE , and V RE . The ratios
of volume to surface area, and surface area to circumference are V / A RE / 3 and
A / C 2RE .
2
. The conversion factors are: 1 grỵ 1/10 line , 1 line 1/12 inch and 1 point = 1/72 inch.
The factors implỵ that
1 grỵ = (1/10)(1/12)(72 points) = 0.60 point.
Thus, 1 grỵ2 = (0.60 point)2 = 0.36 point2, which means that 0.50 grỵ2 = 0.18 point 2 .
3. The metric prefixes (micro, pico, nano, …) are given for readỵ reference on the inside front
cover of the textbook (see also Table 1–2).
1
