Wgu D335 Practice Test 2 With Complete Solutions.

WGU D335 PRACTICETEST 2WITHCOMPLETESOLUTIONS
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1. CreateBGaBGsolutionBGthatBGacceptsBGthreeBGintegerBGinputsBGrepresentingBGthe
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BGnumber BGof BGtimes BGan BGemployee BGtravels BGto BGa BGjob BGsite. BGOutput BGthe
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BGtotal BGdistance BGtraveled BGto BGtwo BGdecimal BGplacesBGgiven BGtheBGfollowing
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BGmiles BGper BGemployee BGcommute BGto BGthe BGjob BGsite. BGOutput BGthe BGtotal
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BGdistance BGtraveled BGto BGtwo BGdecimal BGplaces BGgiven BGthe BGfollowing
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BGmiles BGper BGemployee BGcommute BGto BGthe BGjob BGsite:
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EmployeeBGA:BG15.62 v v




BGmiles BGEmployee BGB:
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BG41.85 BGmiles
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Employee BGC:BG32.67 BGmiles:BGtimes_traveledA BG= BGint(input())
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BGtimes_traveledB BG= BGint(input())
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times_traveledCBG=BGint(input()) v v




BGemployeeA BG= BG15.62 BG#miles
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BGemployeeB BG= BG41.85 BG#miles
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BGemployeeC BG= BG32.67 BG#miles
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distance_traveledA BG= BGtimes_traveledA BG* v v v




BGemployeeA
v BGdistance_traveledB BG= v v




BGtimes_traveledB
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BGdistance_traveledC
v BG= BGtimes_traveledC BG* v v v




BGemployeeC
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total_miles_traveled BG= BGdistance_traveledA BG+ BGdistance_traveledB BG+ v v v v v




BGdistance_trav- BGeledC
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print('Distance:BG{:.2f} BGmiles'.format(total_miles_traveled))
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1
BG/
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BG12
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, 2. CreateBGaBGsolutionBGthatBGacceptsBGanBGinputBGidentifyingBGtheBGnameBGofBGa
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BGtextBGfile,BGfor BGexample,BG"WordTextFile1.txt".BGEachBGtextBGfileBGcontains
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BGthreeBGrowsBGwithBGoneBGword BGper BGrow. BGUsing BGthe BGopen() BGfunction
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BGand BGwrite() BGand BGread() BGmethods, BGinteract BGwith BGthe BGinput BGtext BGfile
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BGto BGwrite BGa BGnew BGsentence BGstring BGcomposed BGof BGthe BGthree BGexisting
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BGwords BGto BGthe BGend BGof BGthe BGfile BGcontents BGon BGa BGnew BGline. BGOutput
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BGthe BGnew BGfile BGcontents.: BGfile_name BG= BGinput()
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with BGopen(file_name, BG'r') BGas BGf:
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word1 BG= v




BGstr(f.readline()).strip()
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BGword2 v BG= v




BGstr(f.readline()).strip()
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BGword3 v BG= v




BGstr(f.readline()).strip()
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f BG= BGopen(file_name, BG'r')
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BGlinesBG=
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BGf.read().splitlines() BGlines
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BG= BG' BG'.join(lines)
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BGf.close()
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print(f'{word1}\n{word2}\n{word3}\n{lines}')
3. Create BGa BGsolution BGthat BGaccepts BGan BGinteger BGinput BGrepresenting BGany
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BGnumber BGof BGounces. BGOutput BGthe BGconverted BGtotal BGnumber BGof BGtons,
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BGpounds, BGand BGremaining BGounces BGbased BGon BGthe BGinput BGounces BGvalue.
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BGThere BGare BG16 BGounces BGin BGa BGpound BGand BG2,000 BGpounds BGin BGa BGton.:
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BGounces_per_pound BG= BG16
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2
BG/
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BG12
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