AAMC FL 1 FULL REVIEW CHEM/PHYS
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Updated
The radioactive decay described in the passage results in the formation
of which two atoms?
A.N and S
B.B and Si
C.B and S
D.N and Si
Beta decay is talked about in the passage.
passage: SDS-PAGE analysis from muscle extracts visualized with either
14C or 32P - correct answer -The answer to this question is A because
the type of radioactive decay is b-1 so a neutron is converted into a
proton
Carbon becomes nitrogen
,Phosphorus becomes Sulfur
Alpha decay - correct answer -Alpha particle is emitted. AKA a helium
particle. 2 proton, 2 neutrons. 4He2.
What happens?
-4 from mass number
-2 from atomic number
***only happens to atoms with big ass nuclei
-easily blocked
Beta decay - correct answer -Changing nucleus by 1
Ejection of beta particle (aka an electron)
Atomic number goes UP by one!
,Compared to normal glycogen, the amount of what type of bond is
decreased in Lafora bodies?
A.Phosphomonoester
B.Phosphodiester
C.α-1,4-Glycosidic bond
D.α-1,6-Glycosidic bond
Passage: Lafora disease is a fatal progressive epilepsy that is
characterized by the formation of deposits of sparsely branched,
insoluble glycogen-like polymers called Lafora bodies - correct answer -
D.
Normal glycogen has 1-4 alpha branching
HOWEVER, lafora bodies have LESS branching.
Each of the following equations shows the dissociation of an acid in
water. Which of the reactions occurs to the LEAST extent?
, A.HCl + H2O → H3O+ + Cl−
B.HPO42− + H2O → H3O+ + PO43−
C.H2SO4 + H2O → H3O+ + HSO4−
D.H3PO4 + H2O → H3O+ + H2PO4− - correct answer -B. The answer to
this question is B. HPO42− has a high negative charge and so
dissociation of it will occur to the least extent. It can act as a base or
acid----> weak acid
In the above figure, an object O is at a distance of three focal lengths
from the center of a convex lens. What is the ratio of the height of the
image to the height of the object?
A.1/3
B.1/2
C.2/3
D.3/2 - correct answer -ratio of the image height to the object height is
equal to the ratio of the lens-image distance to the object-lens distance.
3F ´ 1F/(3F - 1F) = (3/2)F, where F is the focal length.
The ratio sought is then equal to (3/2)F/(3F) = 1/2.
Questions and Answers 100% Pass
|Already Graded A+| Verified and
Updated
The radioactive decay described in the passage results in the formation
of which two atoms?
A.N and S
B.B and Si
C.B and S
D.N and Si
Beta decay is talked about in the passage.
passage: SDS-PAGE analysis from muscle extracts visualized with either
14C or 32P - correct answer -The answer to this question is A because
the type of radioactive decay is b-1 so a neutron is converted into a
proton
Carbon becomes nitrogen
,Phosphorus becomes Sulfur
Alpha decay - correct answer -Alpha particle is emitted. AKA a helium
particle. 2 proton, 2 neutrons. 4He2.
What happens?
-4 from mass number
-2 from atomic number
***only happens to atoms with big ass nuclei
-easily blocked
Beta decay - correct answer -Changing nucleus by 1
Ejection of beta particle (aka an electron)
Atomic number goes UP by one!
,Compared to normal glycogen, the amount of what type of bond is
decreased in Lafora bodies?
A.Phosphomonoester
B.Phosphodiester
C.α-1,4-Glycosidic bond
D.α-1,6-Glycosidic bond
Passage: Lafora disease is a fatal progressive epilepsy that is
characterized by the formation of deposits of sparsely branched,
insoluble glycogen-like polymers called Lafora bodies - correct answer -
D.
Normal glycogen has 1-4 alpha branching
HOWEVER, lafora bodies have LESS branching.
Each of the following equations shows the dissociation of an acid in
water. Which of the reactions occurs to the LEAST extent?
, A.HCl + H2O → H3O+ + Cl−
B.HPO42− + H2O → H3O+ + PO43−
C.H2SO4 + H2O → H3O+ + HSO4−
D.H3PO4 + H2O → H3O+ + H2PO4− - correct answer -B. The answer to
this question is B. HPO42− has a high negative charge and so
dissociation of it will occur to the least extent. It can act as a base or
acid----> weak acid
In the above figure, an object O is at a distance of three focal lengths
from the center of a convex lens. What is the ratio of the height of the
image to the height of the object?
A.1/3
B.1/2
C.2/3
D.3/2 - correct answer -ratio of the image height to the object height is
equal to the ratio of the lens-image distance to the object-lens distance.
3F ´ 1F/(3F - 1F) = (3/2)F, where F is the focal length.
The ratio sought is then equal to (3/2)F/(3F) = 1/2.
