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Exam (elaborations)

Linear Equations: Solutions, Intercepts, and Graphing Exercises TEST BANK

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This document contains a series of algebra problems focused on linear equations, intercepts, and graphing. The problems involve verifying whether points lie on a line, solving for slope and intercept values, rewriting equations into slope-intercept form, and calculating x- and y-intercepts. Several problems include small coordinate-plane graphs to illustrate the solutions. The content is consistent with middle school or early high school algebra coursework, guiding students through essential skills for understanding and visualizing linear relationships.

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Institution
College Algebra
Course
College Algebra











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Written for

Institution
College Algebra
Course
College Algebra

Document information

Uploaded on
November 20, 2025
Number of pages
459
Written in
2025/2026
Type
Exam (elaborations)
Contains
Questions & answers

Subjects

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@PROFDOCDIGITALLIBRARIES




Table of Contents
Chapter 1: Linear Equations and Straight Lines 1–1
Chapter 2: Matrices 2–1

Chapter 3: Linear Programming, A Geometric Approach 3–1

Chapter 4: The Simplex Method 4–1

Chapter 5: Sets and Counting 5–1

Chapter 6: Probability 6–1

Chapter 7: Probability and Statistics 7–1

Chapter 8: Markov Processes 8–1

Chapter 9: The Theory of Games 9–1

Chapter 10: The Mathematics of Finance 10–1

Chapter 11: Logic 11–1

Chapter 12: Difference Equations and Mathematical Models 12–1

,
,@PROFDOCDIGITALLIBRARIES




Chapter 1
Exercises 1.1
6. 5
Left 1, down
1. 2
Right 2, up 3 y
y


(2, 3)
x
x
2




7. Left 20, up 40
2. Left 1, up 4 y
y

(–20, 40)
(–1, 4)
x
x




8. Right 25, up 30
3. Down 2 y
y


(25, 30)
x
x
(0, –2)




9. Point Q is 2 units to the left and 2 units up or
4. Right 2
y (—2, 2).

10. Point P is 3 units to the right and 2 units down or
(3,—2).
x
(2, 0) 1
11. —2(1) + (3) = —2 +1 = —1so yes the point is
3
on the line.

5. Left 2, up 1 1
y 12. —2(2) + (6) = —1 is false, so no the point is not
3
on the line

(–2, 1)
x

, 1 24. 0 = 5
13. —2x + y = —1 Substitute the x and y
no solution
3
coordinates of the point into the equation: x-intercept: none
l'1 ıh 'l1ıh 1 When x = 0, y = 5
'y' , 3ı → —2' ı+ (3) = —1 → —1+1 = —1 is y- intercept: (0, 5)
2 J y 2J 3
a false statement. So no the point is not on the 25. When y = 0, x = 7
line. x-intercept: (7, 0)
l 1 h l1 h 0=7
14. —2 ' ı +' ı (—1) = —1 is true so yes the point is no solution
y-intercept: none
'y3ıJ 'y3ıJ
on the line. 26. 0 = –8x
x=0
15. m = 5, b = 8 x-intercept: (0, 0)
y = –8(0)
16. m = –2 and b = –6
y=0
17. y = 0x + 3; m = 0, b = 3 y-intercept: (0, 0)
1
27. 0 = x – 1
2 2
18. y = x + 0; m = , b=0
3
3 3
x=3
19. 14x + 7 y = 21 x-intercept: (3, 0)
1
7 y = —14x + 21 y = (0) – 1
3
y = —2x + 3
y = –1
y-intercept: (0, –1)
20. x — y = 3 y
—y = —x + 3
y = x —3
(3, 0)
x
21. 3x = 5
(0, –1)
5
x=
3
1 2 28. When x = 0, y = 0.
22. – x+ y = 10
2 3 When x = 1, y = 2.
2 1 y
y= x +10
3 2
3
y= x +15 (1, 2)
4 x
(0, 0)
23. 0 = —4x +8
4x = 8
x=2
x-intercept: (2, 0)
y = –4(0) + 8
y=8
y-intercept: (0, 8)
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