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Chem 103, 120 module 1 to 6 Exam: Financial Accounting II (Portage Learning)_Rasmussen University: AI Verified Answers, 100% Correct

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Chem 103, 120 module 1 to 6 Exam: Financial Accounting II (Portage Learning)_Rasmussen University: AI Verified Answers, 100% Correct

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Chem 103/120 module 1 to 6 exam and
final exam with answers
Financial Accounting II (Rasmussen
University)
Portage Learning
2023 MODULES 1-6 PRE PREDICTOR EXAM
Introduction To General, Organic, And Biological
Chemistry with Lab


MODULE 1 EXAM
QUIZ# 1
1. Convert 845.3 to exponential form and explain your
answer.
2. Convert 3.21 x 10-5 to ordinary form and explain your
answer.
1. Convert 845.3 = larger than 1 = positive exponent,
move decimal 2 places = 8.453 x 102
2. Convert 3.21 x 10-5 = negative exponent = smaller
than 1, move decima l 5places = 0.0000321
QUIZ# 2
Using the following information, do the conversions
shown below, showing all work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4
quarts

,1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2
pints
kilo (= 1000) milli (= 1/1000) centi
(=1/100)
deci (= 1/10)
1. 24.6 grams = ? kg
2. 6.3 ft = ? inches
1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg
2. 6.3 ft x 12 in / 1 ft = 75.6 inches
Please always use the correct units in your final answer
QUIZ# 3
Do the conversions shown below, showing all work:
1. 28oC =? °K
2. 158oF =? °C
3. 343oK =? °F
1. 28°C + 273 = 301 °K °C → °K (make larger)
+273
2. 158°F - 32 ÷ 1.8 = 70 °C °F → °C (make
smaller)-32 ÷1.8
3. 343°K - 273 = 70 °C x 1.8 + 32 = 158°F °K → °C
→ °F

,QUIZ# 4
Be sure to show the correct number of significant figures
in each calculation.
1. Show the calculation of the mass of a 18.6 ml sample
of freon with
density of 1.49 g/ml
2. Show the calculation of the density of crude oil if 26.3
g occupies 30.5
ml.
1. M = D x V = 1.49 x 18.6 = 27.7 g
2. D = M / V = 26..5 = 0.862 g/ml


QUIZ# 5
1. 3.0600 contains ? significant figures.
2. 0.0151 contains ? significant figures.
3. 3.0600 ÷ 0.0151 = ? (give answer to correct number of
significant
figures)
1. 3.0600 contains 5 significant figures.
2. 0.0151 contains 3 significant figures.
3. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 significant
figures for 0.0151)

, QUIZ# 6
Classify each of the following as an element, compound,
solution or
heterogeneous mixture and explain your answer.
1. Coca cola
2. Calcium
3. Chili
1. Coca cola - is not on periodic table (not element) - no
element names
(not compound) appears to be one substance = Solution
2. Calcium - is on periodic table = Element
3. Chili - is not on periodic table (not element) - no
element names (not
compound) appears as more than one substance (meat,
beans,
sauce) = Hetero Mix
QUIZ# 7
Classify each of the following as a chemical change or a
physical change
1. Charcoal burns
2. Mixing cake batter with water

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