GCSE PHYSICS (9–1): Actual June 2025 PAST PAPER 2 – Higher Tier. All Assessment Questions & Mark Scheme [Edexcel 1PH0/2H]

GCSE PHYSICS (9–1): Actual June 2025 PAST PAPER 2 – Higher Tier. All Assessment
Questions & Mark Scheme [Edexcel 1PH0/2H]

Exam Resource Summary

The GCSE Physics (9–1) June 2025 Paper 2 – Higher Tier (Edexcel 1PH0/2H) – All Assessment
Questions & Mark Scheme resource compiles the complete official examination paper and its full
marking guide. It assesses advanced understanding of key physics topics including waves, magnetism,
electromagnetism, space physics, and experimental skills. Each question is accompanied by precise mark
scheme explanations to illustrate how to structure high-level responses and gain full marks. This
essential revision and practice resource supports students aiming for top grades in the May/June 2026
Edexcel GCSE Physics (9–1) Paper 2 – Higher Tier exam.



Turn over

, Answer ALL questions. Write your answers in the spaces provided.

Some questions must be answered with a cross in one of the four boxes . If you change your




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mind about an answer, put a line through the box and then mark your new answer with
a cross .
1 Figure 1 shows a pool full of water.




(Source: © AnaKulagina/Shutterstock)

Figure 1




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(a) (i) The pressure on the ground due to the water in the pool is 3500 Pa.

The density of water is 103 kg / m3.
The gravitational field strength, g, = 10 N / kg.
Calculate the depth of the water in the pool.
(2)




depth =........................... m
(ii) Figure 2 shows part of the side and base of the pool.

side
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base

X

Figure 2
The water in the pool causes a force on the base of the pool.

Draw an arrow on Figure 2 to show the direction of this force at point X.
(1)




2

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, (b) A smaller pool has the same depth of water but has only half the area in contact
with the ground.
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The pressure on the ground underneath the smaller pool is
(1)
A twice the pressure underneath the larger pool

B ten times the pressure underneath the larger pool

C half the pressure underneath the larger pool
D the same as the pressure underneath the larger pool

(c) A small hole is made in the base of the large pool shown in Figure 1.
The area of the hole is 1.5 mm2. The pressure at the base of the pool due to the
water is 3500 Pa.

Calculate the force on the ground directly below the hole due to the water in
the pool.

Use the equation
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F
P
A
(2)




force = .......................... N
(d) A bigger hole is made in the base of the same pool.
Compare the force on the ground directly below the bigger hole with the force on
the ground directly below the original hole.
(1)
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. . . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. .. . . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . . .. . .. .. . . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. .. . . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . . ......................



. . . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. .. . . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . . .. . .. .. . . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. .. . . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . .. . . ......................



(Total for Question 1 = 7 marks)




3

■■■■ Turn over

, 2 (a) A student places a trolley at the top of a runway, as shown in Figure 3.

trolley




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light gate
timer
runway 00:00:00




Figure 3

The student had to lift the trolley through a height of 26 cm to put it at the top of
the runway.

The gravitational potential energy, ΔGPE, of the trolley increases by 4.1 J when
lifted to the top of the runway.




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The gravitational field strength, g, = 10 N / kg.
(i) Show that the mass of the trolley is about 1.6 kg.

Use the equation

ΔGPE
m
g  Δh
(2)




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4

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