Test Bank for Applied Physics, 12th Edition by Dale Ewen

Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 1 The Physics Tool Kit

1) The metric prefix for 0.010 is ________.
Answer: centi

2) The metric symbol, or abbreviation, for milli is ________.
Answer: m

Write the following number(s) in scientific notation:

3) 45,000
Answer: 4.5 × 104

4) 0.0000742
Answer: 7.42 × 10-5

Write the following number in decimal form:

5) 3.28 × 10-4
Answer: 0.000328

6) 2.65 × 108
Answer: 265,000,000

Fill in each blank: (Round to three significant digits when necessary.)

7) 1.2 km = ________ m
Answer: 1200

8) 6.9 L = ________ ml
Answer: 6900

9) 750 μm = ________ mm
Answer: 0.75

10) 670 mm2 = ________ cm2
Answer: 6.7

11) 6500 cm3 = ________ m3
Answer: 0.0065

12) 15 kg = ________ lb
Answer: 166



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,13) 96 in. = ________ yd
Answer: 2.67

14) 15 ft3 = ________ m3
Answer: 0.425

Determine the accuracy (the number of significant digits) in each measurement:

15) 20,900 m
Answer: 3

16) 0.04060 s
Answer: 4

17) 3.6 × 10-12 km
Answer: 2

Determine the precision of each measurement:

18) 23.9 m
Answer: 0.1 m

19) 14,050 ft
Answer: 10 ft

20) 5.0 × 104 s
Answer: 1000 s

21) Use the rules of measurement to add 18.5 m; 2070 cm; 95.25 cm; 0.045 m.
Answer: 40.2 m

22) Find the area of a rectangle 22.6 m long and 4.60 m wide.
Answer: 104 m2

23) Find the volume of a rectangular box 18.0 cm long, 9.0 cm wide, and 6.00 cm high.
Answer: 970 cm3

Express each of the following values using scientific notation:

24) 0.0001042 mi.
Answer: 1.042 × 10-4 mi

25) 6,800,000 in.
Answer: 6.8 × 106 in.



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,26) 0.00481 L
Answer: 4.81 × 10-3 L

27) 0.000000015 gal
Answer: 1.5 × 10-9 gal

28) 127,500 cm
Answer: 1.275 × 105 cm

29) 0.00008207 km
Answer: 8.207 × ×10-5 km

30) 89,600,000 g
Answer: 8.96 × 107 g

31) 18,000 in.
Answer: 1.8 × 104 in.

Perform the following conversion(s):

32) 47.5 ft3 = ________ gal = ________ L
Answer: 355 gal = 1340 L

33) 20 m2 = ________ ft2 = ________ cm2
Answer: 2380 ft2 = 2,20,000 cm2

34) 923 m3 = ________ yd3 = ________ gal
Answer: 1210 yd3 = 243,000 gal

35) 55.0 gal = ________ L = ________ ft3
Answer: 208 L = 7.36 ft3




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, Applied Physics, 12e (Ewen/Schurter/Gunderson)
Chapter 2 Problem Solving

1) What is the difference between a subscript and an exponent?
Answer: An exponent is a mathematical operation. A subscript is used to define a variable a
specific feature or component of a variable.

2) What is the difference between a formula and a working equation?
Answer: A formula is a basic equation, usually expressed in letters and numbers. A working
equation is created when the desired variable is isolated on one side of the equation.

3) What is the purpose of estimation when problem solving?
Answer: Estimating the expected answer in problem solving can serve as a check to make sure
the answer is correct.

4) Solve for m in the formula F = ma.
Answer: m = F/a

5) Solve for t in the formula s = 1/2 (vf + vi)t.
Answer: t = 2s / (vf + vi)

6) Solve for vf in the formula s = 1/2 (vf + vi)t.
Answer: vf = (2s/t) - vi

7) Solve for h in PE = mgh.
Answer: h = PE / mg

8) Given V= πr2h, if r = 5.0 cm and V = 250 cm2, what is h?
Answer: h = 3.2 cm

9) Given A = 1/2 bh, if b = 10.0 cm and h = 12.2 cm, what is A?
Answer: A = 61.0 cm2

10) A cone has a volume of 315 cm3 and a radius of 7.50 cm. What is its height?
Answer: h = 5.35 cm

11) A right triangle has a side of 82.4 mm and a side of 19.6 mm. Find the length of the
hypotenuse.
Answer: 84.7 mm

12) Given a cylinder with a radius of 14.4 cm and a height of 16.8 cm, find the lateral surface
area.
Answer: 1520 cm2




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