WGU OUM2 Task 1 |Passed On First Attempt |Latest Update wit
Complete Solution
Complete each column in this template for each of the four problems from the attached “Student
Work Sample.” In the first column, include all of your work for the correct solution to each
problem. In the second column, explain the misconceptions that led to the student errors. In
the third column, provide written feedback to the student. Include both positive and
guiding comments.
Solution to the Explanation of Feedback for
Question Number
Problem Misconception Student
1. Solve for x The student did not You did a great job
x +5=−x +9 x +5=−x +9 combine like terms remembering to
x + x=9−5 correctly. They get like terms on
x + x=9−5 mistakening said the same side of
x2=4 2 x=4
x + x=x 2 rather than the equation to
x=± 2 x=2 solve! Remember
x + x=2 x. This is a
when we add like
common error as
terms with a
students multiple
the x terms instead variable we only
of adding. add the
coefficeients and
do not change the
exponents. For
example
2 x + 4 x=6 x
because 2+ 4=6.
2. Solve for x The student did not You were on the
2
( x + 4 ) =36 2
( x + 4 ) =36 properly expand right track at the
( x + 4 )2. Instead of beginning of the
x + 4=± 6 problem and I
using the FOIL
x2+16=36 x=−4 ± 6 loved that you
method to expand
x2=20 x=−4 +6 x=−4−6 they only gave the remembered that
x=2 x=−10 when we take a
x=± √20 squared to the x
Or term and 42, leading square root, ± goes
x=± 2 √5 out in front. But
( x + 4 )2=36 to x2 +16. When
2 remember when
x +8 x +16=36 expanded properly it we expand the
x2+8 x−20=0 is x2+ 4 x + 4 x +16. Binomial, we have
( x +10) ( x−2)=0 to use FOIL. First,
x +10=0 x−2=0 Outer, Inner and
Last. Anytime we
x=−10 x=2 square a binomial,
we should always
get a trinomial.
3. Solve for x The misconception The work you
3 2 3 2
x −6 x +5 x=0 in this problem is the showed on this
x −6 x +5 x=0
student divided out problem was
x ( x2−6 x +5 ) =0 the GCF of x, but did excellent. The only
x3−6 x 2 +5 x
Complete Solution
Complete each column in this template for each of the four problems from the attached “Student
Work Sample.” In the first column, include all of your work for the correct solution to each
problem. In the second column, explain the misconceptions that led to the student errors. In
the third column, provide written feedback to the student. Include both positive and
guiding comments.
Solution to the Explanation of Feedback for
Question Number
Problem Misconception Student
1. Solve for x The student did not You did a great job
x +5=−x +9 x +5=−x +9 combine like terms remembering to
x + x=9−5 correctly. They get like terms on
x + x=9−5 mistakening said the same side of
x2=4 2 x=4
x + x=x 2 rather than the equation to
x=± 2 x=2 solve! Remember
x + x=2 x. This is a
when we add like
common error as
terms with a
students multiple
the x terms instead variable we only
of adding. add the
coefficeients and
do not change the
exponents. For
example
2 x + 4 x=6 x
because 2+ 4=6.
2. Solve for x The student did not You were on the
2
( x + 4 ) =36 2
( x + 4 ) =36 properly expand right track at the
( x + 4 )2. Instead of beginning of the
x + 4=± 6 problem and I
using the FOIL
x2+16=36 x=−4 ± 6 loved that you
method to expand
x2=20 x=−4 +6 x=−4−6 they only gave the remembered that
x=2 x=−10 when we take a
x=± √20 squared to the x
Or term and 42, leading square root, ± goes
x=± 2 √5 out in front. But
( x + 4 )2=36 to x2 +16. When
2 remember when
x +8 x +16=36 expanded properly it we expand the
x2+8 x−20=0 is x2+ 4 x + 4 x +16. Binomial, we have
( x +10) ( x−2)=0 to use FOIL. First,
x +10=0 x−2=0 Outer, Inner and
Last. Anytime we
x=−10 x=2 square a binomial,
we should always
get a trinomial.
3. Solve for x The misconception The work you
3 2 3 2
x −6 x +5 x=0 in this problem is the showed on this
x −6 x +5 x=0
student divided out problem was
x ( x2−6 x +5 ) =0 the GCF of x, but did excellent. The only
x3−6 x 2 +5 x
