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What determines the intensity of an ultrasound beam after it has travelled
through the body?
A. the sound wave's source
B. the medium through which the sound travels
C. both A and B
D. neither A nor B - ANSWER-C. The source and the medium both ultimately
determine the residual intensity of an ultrasound beam after it passes through
the body. Sound waves attenuate as they propagate. The initial intensity of a
sound beam is established by the source of the sound, the transducer. The
frequency, which is also determined by the transducer, affects the rate of
attenuation. In addition, the characteristics of the medium help to determine
attenuation. For example, bone and lung have a greater attenuation rate than soft
tissue. In contrast, water has a lower attenuation rate than soft tissue.
What determines the intensity of an ultrasound beam after it has travelled
through the body?
A. the sound wave's source
B. the medium through which the sound travels
C. both A and B
D. neither A nor B - ANSWER-A. As sound propagates, one of the ways to
measure its strength is to record its intensity. The intensity of the part of a bear
that continues to propagate in the forward direction as it reaches a boundary is
called the transmitted intensity. It is reported in units w/cm
,What are the units of pulse duration?
A. units of frequency (Hz, etc.)
B. msec only
C. units of time (sec, years, etc.)
D. units of distance (feet, etc.) - ANSWER-C.
The pulse duration is the actual time that a transducer is creating one pulse.
Hence, it has units of time. The typical range of pulse durations found in
diagnostic imaging equipment is 0.3 to 2 usec, but it is valid to report pulse
duration in any unit of time.
What determines the pulse duration?
A. the source of the wave
B. the medium in which the pulse travels
C. both A and B
D. neither A nor B - ANSWER-A.
The pulse duration is the actual time that a transducer is creating one sound
pulse and is determined by the ultrasound system. Pulse duration does not
include the listening time.
Waves that exist at the same location and time will combine. What is this
called?
A. inference
B. rarefaction
C. interference
D. longitudinal interaction - ANSWER-C.
The combination of many waves into a single wave is called interference.
,Two waves arrive at the same location and interfere. The resultant sound wave
is smaller than either of the two original waves. What is this called?
A. constructive interference
B. angular interaction
C. destructive interference
D. in-phase waves - ANSWER-C.
Destructive interference results when a pair of out-of-phase waves interfere with
each other. The sum of the two out-of-phasewaves has a smaller amplitude than
at least one of the original waves.
A pair of waves are in phase. What occurs when these waves interfere?
A. reflection
B. constructive interference
C. refraction
D. destructive interference - ANSWER-B. Waves that are in phase
constructively interfere with each other. The single wave that results from the
combination of the two in-phase waves will always have a higher amplitude
than either of the original waves.
What is the range of periods commonly found in waves produced by ultrasound
systems?
A. 0.001 to 1 s
B. 0.06 to 0.5 uS
C. 0.2 to 1 ms
D. 10 to 100 ns - ANSWER-B.
Ultrasonic imaging waves have a period in the range of 0.06 to 0.5 us. The
period is the time of a single cycle. Period is the reciprocal of frequency. A
wave with a frequency of 2 MHz has a period of 0.5 usec. A wave with a
frequency of 15 MHz has a period of 0.06 us.
, What determines the initial intensity of an ultrasound beam?
A. the source of the sound wave
B. the medium through which the sound travels
C. both A and B
D. neither A nor B - ANSWER-A.
The source of the acoustic wave determines the initial intensity (as well as the
wave's amplitude and power). At its point of origin, the strength of an acoustic
wave will not be related to the medium that the sound is about to enter.
What happens when the power in an ultrasound beam is unchanged, and at the
same time, the beam area doubles?
A. doubles
B. is halved
C. is quartered
D. remains the same - ANSWER-B.
Intensity is equal to power divided by beam area. In this case, the power is
unchanged while the beam area is doubled. Therefore, the beam's intensity is
halved. For example, if the original power was 2 watts and the initial beam area
was 2 cm?, then the starting intensity was 2 watts divided by 2 cm?, or 1
wattcm?. Now, beam area is doubled, from 2 to 4 cm?. The new intensity is 2
watts divided by 4 cm? or 0.5 watts/cm?. The initial intensity was 1, and the
final intensity is 0.5 watts/cm?. therefore, the intensity has been halved.
With standard ultrasonic imaging, what happens to the period of a wave as it
propagates?
A. increases
B. decreases
C. remains the same - ANSWER-C.
Certain parameters of a wave change as the wave travels through the body.