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SOA EXAM 2025/2026 QUESTIONS AND ANSWERS

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Chapter 0 Topics mentioned in Chapter 0 that these flash cards do not cover: - ANS - graphing inequalities - piecewise functions - one to one functions - limits and continuity - basic rules of differentiation - basic integration - method of substitution Chapter 0 For any two sets A and B, (A∩B)∪(A∩B') = - ANS A Chapter 0 Two sets A and B are disjoint if A∩B = - ANS ∅ Chapter 0 n(S) is defined to be - ANS the number of elements in a set Chapter 0 2 | Page @COPYRIGHT 2025/2026 ALLRIGHTS RESERVED n(A∩B) + n(A∩B') = - ANS n(A) Chapter 0 In order to account for double counting, n(A∪B) = - ANS n(A) + n(B) - n(A∩B) Chapter 0 In order to account for double counting in three sets, n(A∪B∪C) = - ANS n(A) + n(B) + n(C) - n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C) (how does this work for a number of sets greater than three?) Chapter 0 The inverse of a function ƒ(x) = y is - ANS the function solved for x in terms of y, such that if ƒ(x₀) = y₀, ƒ⁻¹(y₀) = x₀ Chapter 0 A quadratic function of the form ax² + bx + c = 0 can be solved with the quadratic equation: - ANS [-b ± √(b² - 4ac)] / 2a Chapter 0 y = b^x ↔ log.b(y) = - ANS x Chapter 0 The natural logarithm is - ANS log.e(y) = ln(y) Chapter 0 Important properties of logarithms: - ANS ... Chapter 0 3 | Page @COPYRIGHT 2025/2026 ALLRIGHTS RESERVED Partial differentiation with respect to x is found by - ANS differentiating with respect to x and regarding y as a constant, then substituting in x₀ and y₀ Chapter 0 Antiderivatives of frequently used functions: - ANS (for individual flash cards, see other deck) Chapter 0 Useful integration rules: - ANS (for individual flash cards, see other deck) Chapter 0 Integration by parts: - ANS ∫ v × du = v × u - ∫ dv × u Chapter 0 ∫ e^(ax) = - ANS [axe

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SOA EXAM 2025/2026 QUESTIONS AND
ANSWERS




Chapter 0

Topics mentioned in Chapter 0 that these flash cards do not cover: - ANS - graphing
inequalities
- piecewise functions
- one to one functions
- limits and continuity
- basic rules of differentiation
- basic integration
- method of substitution


Chapter 0

For any two sets A and B, (A∩B)∪(A∩B') = - ANS A


Chapter 0

Two sets A and B are disjoint if A∩B = - ANS ∅


Chapter 0

n(S) is defined to be - ANS the number of elements in a set


Chapter 0

1 | Page @COPYRIGHT 2025/2026 ALLRIGHTS RESERVED

,n(A∩B) + n(A∩B') = - ANS n(A)


Chapter 0

In order to account for double counting, n(A∪B) = - ANS n(A) + n(B) - n(A∩B)


Chapter 0

In order to account for double counting in three sets, n(A∪B∪C) = - ANS n(A) + n(B) + n(C) -
n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C)
(how does this work for a number of sets greater than three?)


Chapter 0

The inverse of a function ƒ(x) = y is - ANS the function solved for x in terms of y, such that if
ƒ(x₀) = y₀, ƒ⁻¹(y₀) = x₀


Chapter 0
A quadratic function of the form ax² + bx + c = 0 can be solved with the quadratic equation: -
ANS [-b ± √(b² - 4ac)] / 2a


Chapter 0

y = b^x ↔ log.b(y) = - ANS x


Chapter 0

The natural logarithm is - ANS log.e(y) = ln(y)


Chapter 0

Important properties of logarithms: - ANS ...


Chapter 0



2 | Page @COPYRIGHT 2025/2026 ALLRIGHTS RESERVED

, Partial differentiation with respect to x is found by - ANS differentiating with respect to x and
regarding y as a constant, then substituting in x₀ and y₀


Chapter 0

Antiderivatives of frequently used functions: - ANS (for individual flash cards, see other deck)


Chapter 0

Useful integration rules: - ANS (for individual flash cards, see other deck)


Chapter 0

Integration by parts: - ANS ∫ v × du = v × u - ∫ dv × u


Chapter 0

∫ e^(ax) = - ANS [axe^(ax) - e^(ax)] / a^2


Chapter 0

∫ xe^(ax) = - ANS xe^(ax) / a - e^(ax) / a^2


Chapter 0
Geometric progression : a, ar, ar², ar³, ...

Sum of first n terms: - ANS a + ar + ar² + ... + arⁿ⁻¹ = a[1 + r + r² + ... + rⁿ⁻¹] = a × (rⁿ-1)/(r-1) = a
× (1- rⁿ)/(1-r)


Chapter 0

∫ xⁿe^(-cx) = - ANS n!/c^(n+1)


Chapter 0

Infinite sum of geometric series: - ANS a/(1-r)


3 | Page @COPYRIGHT 2025/2026 ALLRIGHTS RESERVED

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