Chemistry 101 Final Exam Ivy Tech Newest 2025/2026
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Diatomic O2 can react with the element magnesium to
form magnesium oxide (MgO). The balanced chemical
equation is:
O2 + Mg ⟶ 2 MgO
If 4 moles of magnesium totally reacted with more than
enough O2, how many moles of MgO would be expected
to form?
A. 8 Moles
B. 2 Moles
C. 4 Moles
D. 1 Mole
E. Not Enough Info - Answer-C
Which of the following is TRUE?
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A. Stoichiometry allows prediction of how much of the
reactants are necessary to form a given amount of
product.
B. All of the above are true.
C. Stoichiometry allows prediction of the amount of
products that form in a chemical reaction based on the
amounts of reactants.
D. Stoichiometry shows the numerical relationship
between chemical quantities in a balanced chemical
equation. - Answer-B
Diatomic N2 can react with diatomic H2 to form ammonia
(NH3). The balanced chemical equation is:
N2 + 3 H2 ⟶ 2 NH3
If 6 moles of H2 totally reacted with more than enough N2,
how many moles of ammonia would be expected to form?
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A. 4 Moles
B. 6 Moles
C. 3 Moles
D. 2 Moles
E. Not enough info - Answer-A
How many grams of the excess reactant remain assuming
the reaction goes to completion and that you start with
15.5 g of Na2S and 12.1 g of CuSO4?
Reaction: Na2S+ CuSO4 ⟶ Na2SO4 + CuS
A. 0.05
B. 9.58
C. 5.92
D. 15.45 - Answer-B
Calculate the maximum number of grams of NH3 that can
be produced by the reaction of 2.00 g of N2 with 3.00 g of
H2.
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Reaction: N2 (g) + 3H2 (g) ⟶ 2 NH3 (g)
A. 2.43
B. 0.964
C. None of the above
D. 4.00
E. 17.0 - Answer-A
Which is the limiting reactant in the following reaction
given that you start with 42.0 g of CO2 and 99.9 g KOH?
Reaction: CO2+ 2 KOH ⟶ K2CO3 + H2O
A. CO2
B. Not enough information
C. KOH
D. K2CO3
E. H2O - Answer-C