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TSI MATH PLACEMENT STUDY GUIDE QUESTIONS AND ANSWERS

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TSI MATH PLACEMENT STUDY GUIDE QUESTIONS AND ANSWERS One third of 84 is 84 × 1/3 = 84÷3 = 28. 28 people 25 years old or younger applied for the job. Two seventh of 84 is 84 × 2/7= 2×84÷7 = 24. 24 people who were at least 50 years old applied for the job. 84 - 28 - 24 = 32. 32 people applied for the job who were between 25 and 50. - correct answer One third of the candidates for a job were 25 years old or younger. Two sevenths of the candidates were at least 50 years old. If 84 people applied for the job, how many were between 25 and 50? It can be confirmed by division that (a), (b) and (c) are factors of 450, while 100 is not. The multiples of 25 are 25, 50, 75,.... 75 is both a factor of 450 and multiple of 25. - correct answer Which of the following is a factor of 450 and multiple of 25? h =15 + 3.2t gives the height of a shrub in inches after t weeks. When planting occurs the height is 15 + 3.2× 0 = 15 inches After one week the height is 15 + 3.2× 1 = 18.2 inches The rate at which the height increases is 18.2 - 15 = 3.2 inches - correct answer The formula h - 15 = 3.2t gives the height h in inches of a plant t weeks after planting. Which is the rate at which the plant's height is increasing?

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TSI MATH PLACEMENT STUDY
GUIDE QUESTIONS AND
ANSWERS

One third of 84 is 84 × 1/3 = 84÷3 = 28. 28 people 25 years old or younger applied for the job.
Two seventh of 84 is 84 × 2/7= 2×84÷7 = 24.

24 people who were at least 50 years old applied for the job. 84 - 28 - 24 = 32.

32 people applied for the job who were between 25 and 50. - correct answer ✔✔One third of
the candidates for a job were 25 years old or younger. Two sevenths of the candidates were at
least 50 years old. If 84 people applied for the job, how many were between 25 and 50?



It can be confirmed by division that (a), (b) and (c) are factors of 450, while 100 is not. The
multiples of 25 are 25, 50, 75,....

75 is both a factor of 450 and multiple of 25. - correct answer ✔✔Which of the following is a
factor of 450 and multiple of 25?



h =15 + 3.2t gives the height of a shrub in inches after t weeks. When planting occurs the height
is 15 + 3.2× 0 = 15 inches

After one week the height is 15 + 3.2× 1 = 18.2 inches

The rate at which the height increases is 18.2 - 15 = 3.2 inches - correct answer ✔✔The formula
h - 15 = 3.2t gives the height h in inches of a plant t weeks after planting.

Which is the rate at which the plant's height is increasing?



nitial me ans at the beginning. At the beginning t is 0. h =15 + 3.2t gives the height of a shrub in
inches after t weeks. When planting occurs the height is 15 + 3.2× 0 = 15 inches - correct answer
✔✔the formula h-15 =3.2t gives the height h inches of a plant t weeks after planting

how high was the initial height of the shrub

, h =15 + 3.2t gives the height of a shrub in inches after t weeks. When the height is 31 inches 31
= 15 + 3.2t

3.2t = 16

t = 16÷3.2

t=5

The height is 31 inches after 5 weeks - correct answer ✔✔The formula h -15 = 3.2t gives the
height h in inches of a plant t weeks after planting.

When was the height 31 inches?



It is clear from the diagram that the T -axis is the mirror line or axis of symmetry of this diagram.
The equation of the T- axis is t = 0.

The equation of the axis of symmetry of this graph is t = 0 - correct answer ✔✔A graph of the
temperature T (degrees Fahrenheit) in a refrigerator t hours after midday.

What is the equation of the axis of symmetry of this graph?



It is apparent from the graph that it is not linear hence the answer cannot be (A) If an attempt is
made to solve (B) it will be found there is no real solution. One of the solutions to (D) is 8, which
gives a negative value. (C) is the only possible solution.



9+t2=8 - correct answer ✔✔A graph of the temperature T (degrees Fahrenheit) in a refrigerator
t hours after midday.

It is necessary to find the times when the temperature is 8o F. Which of the following is the
correct equation to do this.



The point on the graph corresponding to t = 1 is (1,8). The point on the graph corresponding to t
= 2 is (2,5). The slope of the straight line joining them is (5 - 8)÷(2 - 1) = -3.

The equation is T = -3t + c As (2,5) lies the line we can substitute for t and T.

5 = -3×2 + c

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