StraighterLine Exam 2 (Chpt. 4-6) exam questions and 100% correct answers 2025

StraighterLine Exam 2 (Chpt. 4-6)
Which of the following is soluble in water?



a. AgCl

b. Rb2CrO4

c. Hg2I2

d. CaSO4

e. PbBr2 - ✔✔ correct answer b. Rb2CrO4



Based on the solubility rules, which of these processes will occur if solutions of CuSO4(aq) and
BaCl2(aq) are mixed?



Select one:

a. CuCl2 will precipitate; Ba2+ and SO42- are spectator ions.

b. CuSO4 will precipitate; Ba2+ and Cl- are spectator ions.

c. BaSO4 will precipitate; Cu2+ and Cl- are spectator ions.

d. BaCl2 will precipitate; Cu2+ and SO42- are spectator ions.

e. No precipitate will form. - ✔✔ correct answer c. BaSO4 will precipitate; Cu2+ and Cl- are spectator
ions.



Which is the net ionic equation for the reaction between aqueous solutions of lithium hydroxide and
hydrobromic acid?LiOH(aq) + HBr(aq) → H2O(l) + LiBr(aq)



Select one:

a. LiOH(aq) → Li+(aq) + OH-(aq)

b. HBr(aq) → H+(aq) + Br-(aq)

c. H+(aq) + OH-(aq) → H2O(l)

d. Li+(aq) + Br-(aq) → LiBr(aq)

e. Li+(aq) + OH-(aq)+ H+(aq) + Br-(aq) → H2O(l) + LiBr(aq) - ✔✔ correct answer c. H+(aq) + OH-(aq) →
H2O(l)



Which salt is formed in the neutralization reaction of hydrochloric acid with calcium hydroxide?

, StraighterLine Exam 2 (Chpt. 4-6)
Select one:

a. CaO

b. CaCl

c. CaH2

d. CaCl2

e. NaCl - ✔✔ correct answer d. CaCl2



Based on the solubility rules, which one of these compounds is insoluble in water?



Select one:

a. NaCl

b. MgBr2

c. FeCl2

d. AgBr

e. ZnCl2 - ✔✔ correct answer d. AgBr



What is the oxidizing agent in the following reaction?5Fe2+(aq) + MnO4-(aq) + 8H+(aq) → 5Fe3+(aq)
+ Mn2+(aq) + 4H2O(l)



Select one:

a. Fe2+

b. MnO4-

c. H+

d. Mn2+

e. Fe3+ - ✔✔ correct answer b. MnO4-



What is the oxidation number of oxygen in potassium superoxide, KO2?



Select one:

a. +1

b. 0