Nicet Level 1 - Water Based Layout| Latest Update
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________ indicates a mandatory req. according to NFPA definitions. - Correct Answers-Shall.
(Ref. NFPA 13 2016, Sec. 3.2.4.)
_________ indicates a mandatory requirement according to NFPA definitions? - Correct
Answers-Shall. Reference NFPA 13 2016, Section 3.2.4.
100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. How many feet of 1 1/2 in. pipe will
produce the same friction loss? - Correct Answers-Assume this is Schedule 40 pipe, C = 120.
Use the Hazen-Williams formula to calculate the friction loss for the 1 ¼ in. pipe and the 1 ½ in.
pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
,For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.61 4.87
P friction loss = 0.317 psi/ft
Step #2: Determine the total friction loss for 100 gpm flowing through 100 ft. of 1 ¼ in. Schedule
40 black steel pipe: 100 ft. x 0.672 psi/ft = 67.2 psi
Step #3: Determine the pipe length to produce the same friction loss in the 1 ½ in. pipe:
y ft. x 0.317 psi/ft = 67.2 psi
, y = 67.2 ÷ 0.317
y = 212 ft.
100 gpm is flowing through 100' of 1 1/4in Schedule 40 pipe. How many feet of 1 1/2in pipe will
produce the same friction loss? - Correct Answers-Step #1: Assume this is Schedule 40 pipe,
C = 120. Use the Hazen-Williams formula to calculate the friction loss for the 1 ¼ in. pipe and
the 1 ½ in. pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
2025/2026| Real-Based Questions with Approved
Answers| Guaranteed Perfect Score A+
________ indicates a mandatory req. according to NFPA definitions. - Correct Answers-Shall.
(Ref. NFPA 13 2016, Sec. 3.2.4.)
_________ indicates a mandatory requirement according to NFPA definitions? - Correct
Answers-Shall. Reference NFPA 13 2016, Section 3.2.4.
100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. How many feet of 1 1/2 in. pipe will
produce the same friction loss? - Correct Answers-Assume this is Schedule 40 pipe, C = 120.
Use the Hazen-Williams formula to calculate the friction loss for the 1 ¼ in. pipe and the 1 ½ in.
pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
,For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.61 4.87
P friction loss = 0.317 psi/ft
Step #2: Determine the total friction loss for 100 gpm flowing through 100 ft. of 1 ¼ in. Schedule
40 black steel pipe: 100 ft. x 0.672 psi/ft = 67.2 psi
Step #3: Determine the pipe length to produce the same friction loss in the 1 ½ in. pipe:
y ft. x 0.317 psi/ft = 67.2 psi
, y = 67.2 ÷ 0.317
y = 212 ft.
100 gpm is flowing through 100' of 1 1/4in Schedule 40 pipe. How many feet of 1 1/2in pipe will
produce the same friction loss? - Correct Answers-Step #1: Assume this is Schedule 40 pipe,
C = 120. Use the Hazen-Williams formula to calculate the friction loss for the 1 ¼ in. pipe and
the 1 ½ in. pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
