MIP1501
ASSIGNMENT 3 2025
UNIQUE NO. 178273
DUE DATE: 30 JULY 2025
,MIP1501 – Assignment 03
UNIQUE NUMBER: 178273
Name:
Student Number:
Date Submitted: Before 30 July 2025
QUESTION 1 (31 MARKS)
1.1
A tractor travels 90 km on 18 litres of fuel. How much fuel is needed for 130 km?
90 km ÷ 18 litres = 5 km/litre
130 km ÷ 5 = 26.00 litres
1.2
7 kg of tomatoes cost R56.63. What’s the cost of 10 kg?
R56.63 ÷ 7 = R8.09/kg
R8.09 × 10 = R80.90
1.3
30 men build a wall in 20 days. How long will 25 men take?
30 men × 20 days = 600
600 ÷ 25 = 24 days
, 1.4
Meat calculations:
1.4.1
R19 per 200g = 5 × R19 = R95 per kg
1.4.2
2.5 kg = 10 × 250g
10 × R55 = R550
1.4.3
6 guests × 3 = 18 guests; 3 weeks: Multiply by 3
Rump: 1 kg × 3 × 3 = 9 kg
Mince: 2 kg × 3 × 3 = 18 kg
Chicken: 1.5 kg × 3 × 3 = 13.5 kg
Fillet: 2.5 kg × 3 × 3 = 22.5 kg
1.4.4
Rump: 9 kg × R150 = R1350
Mince: 18 kg × R84 = R1512
Chicken: 13.5 × R95 = R1282.50
Fillet: 22.5 × R220 = R4950
Total: R9094.50
1.5 Problem Solving
ASSIGNMENT 3 2025
UNIQUE NO. 178273
DUE DATE: 30 JULY 2025
,MIP1501 – Assignment 03
UNIQUE NUMBER: 178273
Name:
Student Number:
Date Submitted: Before 30 July 2025
QUESTION 1 (31 MARKS)
1.1
A tractor travels 90 km on 18 litres of fuel. How much fuel is needed for 130 km?
90 km ÷ 18 litres = 5 km/litre
130 km ÷ 5 = 26.00 litres
1.2
7 kg of tomatoes cost R56.63. What’s the cost of 10 kg?
R56.63 ÷ 7 = R8.09/kg
R8.09 × 10 = R80.90
1.3
30 men build a wall in 20 days. How long will 25 men take?
30 men × 20 days = 600
600 ÷ 25 = 24 days
, 1.4
Meat calculations:
1.4.1
R19 per 200g = 5 × R19 = R95 per kg
1.4.2
2.5 kg = 10 × 250g
10 × R55 = R550
1.4.3
6 guests × 3 = 18 guests; 3 weeks: Multiply by 3
Rump: 1 kg × 3 × 3 = 9 kg
Mince: 2 kg × 3 × 3 = 18 kg
Chicken: 1.5 kg × 3 × 3 = 13.5 kg
Fillet: 2.5 kg × 3 × 3 = 22.5 kg
1.4.4
Rump: 9 kg × R150 = R1350
Mince: 18 kg × R84 = R1512
Chicken: 13.5 × R95 = R1282.50
Fillet: 22.5 × R220 = R4950
Total: R9094.50
1.5 Problem Solving