AAMC FL 4 LATEST 2025 EXAM
QUESTIONS AND CORRECT ANSWERS
(VERIFIED ANSWERS) | A+ GRADE
If methane (CH4) were substituted for NH3 in the
aluminum can, the crushing of the can would:
A. occur because CH4, being polar, would dissolve in the
water in the tray.
B. occur because CH4, being non polar, would dissolve in
the water in the tray
C. not occur because CH4, being polar, would don't
dissolve the water in the tray
D. not occur because CH4, being non polar, would not
dissolve in the water of the tray Correct Answer D.
Can crushing will not occur. CH4 is a non polar molecule
and will not dissolve appreciably in water. Since the CH4
will remain in the gas phase, the can will not be crushed
by the formation of a vacuum inside the can
Ca(OH)2 and CaCl2, in the reaction shown in Equation 1
are best described as compounds of:
A. an alkali metal
B. an alkaline earth metal
C. a metalloid
D. a transition metal Correct Answer B.
,The alkaline earth metals comprise Group 2 of the
Periodic Table. Calcium Ca, is a member of this family
found in prior 4.
Which conclusion can be drawn from the experimental
results described in the passage?
A. Compound 1 selectively sensitizes cancer cells to the
chemotherapy action of Compound 2
B. Compound 1 sensitizes all cells to chemotherapeutic
action
C. Compound 2 induces apoptosis in cancer cells only in
conjunction with treatment with Compound 1
D. Compound 2 inhibits the NF-kB signaling pathway,
which leads to apoptosis Correct Answer A.
The results shown in Figure 1 and Table 1 show that
treatment of cancerous cell lines with Compound 1
sensitizes cancer cells to chemotherapeutic action as a
result of exposure to Compound 2.
What is the concentration of acute leukemia CC95
Combination value in micro molar units?
A. 6 x 10^ -10 μM
B. 6 x 10^-7 μM
C. 6 x 10^-4 μM
D. 6 x 10^-2 μM Correct Answer C.
,The CC95 Combination value for acute leukemia cells was
0.6 nM or 0.6 x 10^-9 M. This corresponds to 0.6 x 10^-9 x
(1 μM/ 1x10^-6 M) = 0.6 x 10^-3 μM or 6 x 10^-4 μM.
Compared to treatment with Compound 2 alone, which cell
line shows the greatest enhancement of chemotherapeutic
activity as a result of sensitization of Compound 1?
A. Acute leukemia
B. Fibrosarcoma
C. Cervical carcinoma
D. Noncancerous fibroblast Correct Answer A.
The ratio of value of CC95 to CC95 Combination gives the
"fold enhancement" that is produced using a combination
of compounds 1 and 2 instead of just Compound 2 alone.
Acute leukemia cells show a 74-fold enhancement in
apoptotic activity by using the combination of Compound 1
and 2, while the other cancer cell lines show only a
roughly 10 fold enhancement
Assume that cellular uptake rates and drug delivery rates
of compounds 1 and 2 are identical. If the proposed
mechanism of sensitization by Compound 1 is correct,
what cancer cell treatment protocol is most likely to
produce the most apoptosis 20 h after treatment?
A. Administration of both Compound 1 and Compound 2
simultaneously
B. Administration of Compound 1 followed by Compound 2
after 0.5 h
, C. Administration of Compound 2 followed by Compound
1 after 0.5 h
D. Administration of Compound 2 followed by Compound
1 after 1 d Correct Answer B.
The NF-kB signaling pathway is anti-apoptotic and is
initiated by degradation and release of the inhibitor binding
protein IkB. Once started, this process is not easily
reversed. If the chemotherapeutic agent is administer at
the same time as the sensitizing agent, this is good reason
to believe that some cells be be exposed to Compound 2
prior to Compound 1 as a result of random probability. The
researchers found that administration of Compound 1 prior
to Compound 2 by 0.5 h provided benefit.
A carbonyl group contains what type of bonding interaction
between C and O atoms?
A. One σ only
B. One σ and one π only
C. One π only
D. One σ and two π only Correct Answer B.
A carbonyl group contains a C=O double bond. The first
bonding interaction between atoms is always a σ. The
second bond is formed from π symmetry orbitals.
Which of the following atoms gains one electron most
readily?
A. Ar
QUESTIONS AND CORRECT ANSWERS
(VERIFIED ANSWERS) | A+ GRADE
If methane (CH4) were substituted for NH3 in the
aluminum can, the crushing of the can would:
A. occur because CH4, being polar, would dissolve in the
water in the tray.
B. occur because CH4, being non polar, would dissolve in
the water in the tray
C. not occur because CH4, being polar, would don't
dissolve the water in the tray
D. not occur because CH4, being non polar, would not
dissolve in the water of the tray Correct Answer D.
Can crushing will not occur. CH4 is a non polar molecule
and will not dissolve appreciably in water. Since the CH4
will remain in the gas phase, the can will not be crushed
by the formation of a vacuum inside the can
Ca(OH)2 and CaCl2, in the reaction shown in Equation 1
are best described as compounds of:
A. an alkali metal
B. an alkaline earth metal
C. a metalloid
D. a transition metal Correct Answer B.
,The alkaline earth metals comprise Group 2 of the
Periodic Table. Calcium Ca, is a member of this family
found in prior 4.
Which conclusion can be drawn from the experimental
results described in the passage?
A. Compound 1 selectively sensitizes cancer cells to the
chemotherapy action of Compound 2
B. Compound 1 sensitizes all cells to chemotherapeutic
action
C. Compound 2 induces apoptosis in cancer cells only in
conjunction with treatment with Compound 1
D. Compound 2 inhibits the NF-kB signaling pathway,
which leads to apoptosis Correct Answer A.
The results shown in Figure 1 and Table 1 show that
treatment of cancerous cell lines with Compound 1
sensitizes cancer cells to chemotherapeutic action as a
result of exposure to Compound 2.
What is the concentration of acute leukemia CC95
Combination value in micro molar units?
A. 6 x 10^ -10 μM
B. 6 x 10^-7 μM
C. 6 x 10^-4 μM
D. 6 x 10^-2 μM Correct Answer C.
,The CC95 Combination value for acute leukemia cells was
0.6 nM or 0.6 x 10^-9 M. This corresponds to 0.6 x 10^-9 x
(1 μM/ 1x10^-6 M) = 0.6 x 10^-3 μM or 6 x 10^-4 μM.
Compared to treatment with Compound 2 alone, which cell
line shows the greatest enhancement of chemotherapeutic
activity as a result of sensitization of Compound 1?
A. Acute leukemia
B. Fibrosarcoma
C. Cervical carcinoma
D. Noncancerous fibroblast Correct Answer A.
The ratio of value of CC95 to CC95 Combination gives the
"fold enhancement" that is produced using a combination
of compounds 1 and 2 instead of just Compound 2 alone.
Acute leukemia cells show a 74-fold enhancement in
apoptotic activity by using the combination of Compound 1
and 2, while the other cancer cell lines show only a
roughly 10 fold enhancement
Assume that cellular uptake rates and drug delivery rates
of compounds 1 and 2 are identical. If the proposed
mechanism of sensitization by Compound 1 is correct,
what cancer cell treatment protocol is most likely to
produce the most apoptosis 20 h after treatment?
A. Administration of both Compound 1 and Compound 2
simultaneously
B. Administration of Compound 1 followed by Compound 2
after 0.5 h
, C. Administration of Compound 2 followed by Compound
1 after 0.5 h
D. Administration of Compound 2 followed by Compound
1 after 1 d Correct Answer B.
The NF-kB signaling pathway is anti-apoptotic and is
initiated by degradation and release of the inhibitor binding
protein IkB. Once started, this process is not easily
reversed. If the chemotherapeutic agent is administer at
the same time as the sensitizing agent, this is good reason
to believe that some cells be be exposed to Compound 2
prior to Compound 1 as a result of random probability. The
researchers found that administration of Compound 1 prior
to Compound 2 by 0.5 h provided benefit.
A carbonyl group contains what type of bonding interaction
between C and O atoms?
A. One σ only
B. One σ and one π only
C. One π only
D. One σ and two π only Correct Answer B.
A carbonyl group contains a C=O double bond. The first
bonding interaction between atoms is always a σ. The
second bond is formed from π symmetry orbitals.
Which of the following atoms gains one electron most
readily?
A. Ar
