Nicet Level 1 - Water Based
Layout Comprehensive
Questions (Frequently Tested)
with Verified Answers.
Toggle hangers shall be permitted only for the support of pipe __________ inches or smaller in size
under ceilings of hollow tile or metal lath and plaster. - Answer: 1 2/2 in. (ref. NFPA 13 2016 Sec.
9.2.1.1.2.
While conducting a flow test, the chosen hydrant should be ______ - Answer: As close to the property
where the sprinkler system is being installed. (Ref, NFPA 13 Sec. A.24.2.2. or NFPA 291)
What formula is used to determine the discharge coefficiant relating pressure and flow rate? - Answer: K
= Q / (Square root of P)
What best describes a tree system? - Answer: Cross mains and the branch lines are not tied together,
providing only one path of water flow.
Factors that define Occupancy Group Hazard 2 include: - Answer: Quantity and combustibility of
contents are moderate to high.
Stockpiles of contents with moderate rates of heat release do not exceed 12 ft and stockpiles with high
heat release do not exceed 8 ft
(Ref NFPA 13 Sec. 5.3.2)
Which of the following standards contain reqs. pertaining to the installation of underground piping? -
Answer: NFPA 13 & 24 (Both in Chapter 10)
Which of the following should you inspect on an extension cord before each use? - Answer: The
grounding prong & the insulation for nicks, cuts, or damage
,________ indicates a mandatory req. according to NFPA definitions. - Answer: Shall.
(Ref. NFPA 13 2016, Sec. 3.2.4.)
100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. How many feet of 1 1/2 in. pipe will produce
the same friction loss? - Answer: Assume this is Schedule 40 pipe, C = 120. Use the Hazen-Williams
formula to calculate the friction loss for the 1 ¼ in. pipe and the 1 ½ in. pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
, c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.61 4.87
P friction loss = 0.317 psi/ft
Step #2: Determine the total friction loss for 100 gpm flowing through 100 ft. of 1 ¼ in. Schedule 40
black steel pipe: 100 ft. x 0.672 psi/ft = 67.2 psi
Step #3: Determine the pipe length to produce the same friction loss in the 1 ½ in. pipe:
y ft. x 0.317 psi/ft = 67.2 psi
y = 67.2 ÷ 0.317
y = 212 ft.
A basic contract: (choose all that apply) - Answer: Contains the names of the parties involved,
References the contract documents, Discusses the work that is to be done, and Discusses start and
completion dates.
Define both the constant, y, and the exponent ,z, for q in the Hazen-Williams friction loss formula shown
Below:
Layout Comprehensive
Questions (Frequently Tested)
with Verified Answers.
Toggle hangers shall be permitted only for the support of pipe __________ inches or smaller in size
under ceilings of hollow tile or metal lath and plaster. - Answer: 1 2/2 in. (ref. NFPA 13 2016 Sec.
9.2.1.1.2.
While conducting a flow test, the chosen hydrant should be ______ - Answer: As close to the property
where the sprinkler system is being installed. (Ref, NFPA 13 Sec. A.24.2.2. or NFPA 291)
What formula is used to determine the discharge coefficiant relating pressure and flow rate? - Answer: K
= Q / (Square root of P)
What best describes a tree system? - Answer: Cross mains and the branch lines are not tied together,
providing only one path of water flow.
Factors that define Occupancy Group Hazard 2 include: - Answer: Quantity and combustibility of
contents are moderate to high.
Stockpiles of contents with moderate rates of heat release do not exceed 12 ft and stockpiles with high
heat release do not exceed 8 ft
(Ref NFPA 13 Sec. 5.3.2)
Which of the following standards contain reqs. pertaining to the installation of underground piping? -
Answer: NFPA 13 & 24 (Both in Chapter 10)
Which of the following should you inspect on an extension cord before each use? - Answer: The
grounding prong & the insulation for nicks, cuts, or damage
,________ indicates a mandatory req. according to NFPA definitions. - Answer: Shall.
(Ref. NFPA 13 2016, Sec. 3.2.4.)
100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. How many feet of 1 1/2 in. pipe will produce
the same friction loss? - Answer: Assume this is Schedule 40 pipe, C = 120. Use the Hazen-Williams
formula to calculate the friction loss for the 1 ¼ in. pipe and the 1 ½ in. pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
, c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.61 4.87
P friction loss = 0.317 psi/ft
Step #2: Determine the total friction loss for 100 gpm flowing through 100 ft. of 1 ¼ in. Schedule 40
black steel pipe: 100 ft. x 0.672 psi/ft = 67.2 psi
Step #3: Determine the pipe length to produce the same friction loss in the 1 ½ in. pipe:
y ft. x 0.317 psi/ft = 67.2 psi
y = 67.2 ÷ 0.317
y = 212 ft.
A basic contract: (choose all that apply) - Answer: Contains the names of the parties involved,
References the contract documents, Discusses the work that is to be done, and Discusses start and
completion dates.
Define both the constant, y, and the exponent ,z, for q in the Hazen-Williams friction loss formula shown
Below:
