Solutions for Engineering Mechanics Statics 15th Edition by Hibbeler | All 11 Chapters Covered

ALL 11 CHAPTERS COVERED




SOLUTION MANUAL

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1–1.

What is the weight in newtons of an object that has a mass
of (a) 8 kg, (b) 0.04 kg, and (c) 760 Mg?




SOLUTION
(a) W = 9.81(8) = 78.5 N Ans.
(b) W = 9.81(0.04) ( 10 - 3 ) = 3.92 ( 10 - 4 ) N = 0.392 mN Ans.
(c) W = 9.81(760) ( 10 ) = 7.46 ( 10 ) N = 7.46 MN
3 6
Ans.




Ans:
W = 78.5 N
W = 0.392 mN
W = 7.46 MN

1

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exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.



1–2.

Represent each of the following combinations of units in
the correct SI form: (a) >KN>ms, (b) Mg>mN, and
(c) MN>(kg # ms).




SOLUTION
(a) kN>ms = 103N> ( 10 - 6 ) s = GN>s Ans.
(b) Mg>mN = 106g>10 - 3 N = Gg>N Ans.
6 -3
(c) MN>(kg # ms) = 10 N>kg(10 s) = GN>(kg # s) Ans.




Ans:
GN>s
Gg>N
GN>(kg # s)

2

,© 2016 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently
exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.



1–3.

Represent each of the following combinations of unit in the
correct SI form: (a) Mg>ms, (b) N>mm, (c) mN>(kg # ms).




SOLUTION

Mg 103 kg
(a) = = 106 kg>s = Gg>s Ans.
ms 10-3 s
N 1N
(b) = = 103 N>m = kN>m Ans.
mm 10-3 m
mN 10-3 N
(c) = = kN>(kg # s) Ans.
(kg # ms) 10-6 kg # s




Ans:
Gg>s
kN>m
kN>(kg # s)

3

,© 2016 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently
exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.



*1–4.

Convert: (a) 200 lb # ft to N # m, (b) 350 lb>ft3 to kN>m3,
(c) 8 ft>h to mm>s. Express the result to three significant
figures. Use an appropriate prefix.




SOLUTION

a) (200 lb # ft) ¢ ≤¢ ≤ = 271 N # m
4.4482 N 0.3048 m
Ans.
1 lb 1 ft


b) ¢ ≤ ¢ ≤ ¢ ≤ = 55.0 kN>m3
3
350 lb 1 ft 4.4482 N
Ans.
1 ft3 0.3048 m 1 lb


c) ¢ ≤¢ ≤¢ ≤ = 0.677 mm>s
8 ft 1h 0.3048 m
Ans.
1h 3600 s 1 ft




Ans:
271 N # m
55.0 kN>m3
0.677 mm>s

4

,© 2016 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently
exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.



1–5.

Represent each of the following as a number between 0.1
and 1000 using an appropriate prefix: (a) 45 320 kN,
(b) 568(105) mm, and (c) 0.00563 mg.




SOLUTION

(a) 45 320 kN = 45.3 MN Ans.
(b) 568 ( 105 ) mm = 56.8 km Ans.
(c) 0.00563 mg = 5.63 mg Ans.




Ans:
45.3 MN
56.8 km
5.63 mg

5

,© 2016 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently
exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.



1–6.

Round off the following numbers to three significant
figures: (a) 58 342 m, (b) 68.534 s, (c) 2553 N, and
(d) 7555 kg.




SOLUTION
a) 58.3 km b) 68.5 s c) 2.55 kN d) 7.56 Mg Ans.




Ans:
58.3 km
68.5 s
2.55 kN
7.56 Mg

6

,© 2016 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently
exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.



1–7.

Represent each of the following quantities in the correct
SI form using an appropriate prefix: (a) 0.000 431 kg,
(b) 35.3(103) N, and (c) 0.005 32 km.




SOLUTION
a) 0.000 431 kg = 0.000 431 A 103 B g = 0.431 g Ans.

b) 35.3 A 103 B N = 35.3 kN Ans.

c) 0.005 32 km = 0.005 32 A 103 B m = 5.32 m Ans.




Ans:
0.431 g
35.3 kN
5.32 m

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