Solution Manual for Finite Mathematics and Its Applications (13th Edition) – Larry J. Goldstein – Full Solutions (Chapters 1–12)

SOLUTION MANUAL m




Finite Mathematics & Its Applications
m m m m




13th Edition by Larry J. Goldstein,
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Chapters 1 - 12, Complete
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, Contents
Chapter 1: Linear Equations and Straight Lines
m m m m m 1–1
Chapter 2: Matrices
m 2–1

Chapter 3: Linear Programming, A Geometric Approach
m m m m m 3–1

Chapter 4: The Simplex Method
m m m 4–1

Chapter 5: Sets and Counting
m m m 5–1

Chapter 6: Probability
m 6–1

Chapter 7: Probability and Statistics
m m m 7–1

Chapter 8: Markov Processes
m m 8–1

Chapter 9: The Theory of Games
m m m m 9–1

Chapter 10: The Mathematics of Finance
m m m m 10–1

Chapter 11: Logic
m 11–1

Chapter 12: Difference Equations and Mathematical Models
m m m m m 12–1

, Chapter 1
m




Exercises 1.1 5
m

6. Left 1, down
m m m m




2
1. Right 2, up 3
m m m
y
y


(2, 3)
m



x
x
( –1, – 52 m m )
m




7. Left 20, up 40
m m m m


2. Left 1, up 4
m m m
y
y

(–20, 40) m

(–1, 4) m




x
x




8. m Right 25, up 30 m m m


3. Down 2
m m
y
y


(25, 30) m




x
x
(0, –2) m




9. Point Q is 2 units to the left and 2 units up or
m m m m m m m m m m m m


4. Right 2 m



y (—2, 2). m




10. Point P is 3 units to the right and 2 units down or
m m m m m m m m m m m m




(3,—2).
x
(2, 0)
m
1 m



11. —2(1) + (3) = —2 +1 = —1so yes the point is
m m m m m m m m m m m




3
on the line. m m




5. Left 2, up 1 1 m




12. —2(2) + (6) = —1 is false, so no the point is not
m m m
m m m m m m m m m m m m

y
3
on the line m m




(–2, 1) m

x



Copyright © 2023 Pearson Education, Inc.
m m m m m 1-1

, Chapter 1: Linear Equations and Straight Lines
m m m m m m ISM: Finite Math
m m




1 m
24. 0 = 5
m m m




13 —2x + y = —1 Substitute the x and y
m m m m m m m m m
no solution m


3
. x-intercept: none m


coordinates of the point into the equation: m m m m m m



f 1 hı f h When x = 0, y = 5
' ,3 →—2 ' 1 ı +1(3)=—1→—1+1=—1 is
m m m m m m m
m
m m


y-intercept: (0, 5)
y' ı 'y ıJ
m m m m m m m m m m
m m m


m

2 J 2 3
mm m m




a false statement. So no the point is not on
m m m m m m m m m 25. When y = 0, x = 7x-
m m m m m m m m




mtheline. m intercept: (7, 0) 0 m m m




f 1h f1h =7 m m




14 —2 ' ı + ' ı (—1) =—1 is true so yes the point is no solution
.
m m m m m m m m m m




'y3 ıJ 'y3 ıJ y-intercept: none m

m mm




on the line. m m
26. 0 = –8x
m m m




15. m = 5, b = 8
m m m m m m
x=0 m m




x-intercept: (0, 0) m m




16. m = –2 and b = –6
m m m m m m m
y = –8(0)m m




y=0 m m




17. m y = 0x + 3; m = 0, b = 3
m m m m m m m m m m
y-intercept: (0, 0) m m




2 2 1 m




y = x +0; m = , b = 0
m m

27 0 = x –1m m m m


18 m m m m m m m m m m


3
3 3 .
. x=3 m m




19. 14x +7 y = 21
m m m m m m
x-intercept: (3, 0) m m




1 m



7 y = —14x +21
m m m m m
y = (0) – 1
m m m m




3
y = —2x +3
y = –1
m m m m

m m




y-intercept: (0, –1) m m


20 x— y =3
m m m m
y
. —y =—x +3 m m m m




y = x —3m m m m




(3, 0)
x
m


21. 3x = 5
mm m m m




5 (0, –1) m


x= m m




3
1 2
28. When x = 0, y = 0.
– x+ y = 10
m m m m m m



22 2
m


3
m m


When x = 1, y = 2.
. m m m m m m




2 m 1 m
y
y= x +10 m m m




3 2
3 m


y = x +15 m m m
(1, 2) m


4 x
(0, 0) m




23. 0 = —4x +8
m m m m




4x = 8 m m




x =2 m m




x-intercept: (2, 0) m m




y = –4(0) + 8
m m m m




y=8 m m




y-intercept: (0, 8) m m




1-2 Copyright © 2023 Pearson Education, Inc. m m m m m