CSLB Concrete C8 License Practice Test #1
questions with answers
What is the volume of a cylinder if the diameter equals 3 feet and the length
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equals to 12 feet? - CORRECT ANSWERS ✔✔84.78 cubic feet
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Explanation:
There are two ways to solve the problem. However, regardless of which
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method is used, you need to first determine the area of the circle then
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multiply it by the length. Traditional Method Use the following formula:Area
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of the circle = π x r x rWhere π = 3.14 and radius (r) = 1.5 feet (half of the
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diameter length)Area = 3.14 x 1.5 x 1.5Area = 7.065 sq. ft.Multiply area by
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the length to find the volume.7.065 x 12 = 84.78Shortcut Method Area of the
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circle is 78.5% of the square. Treat the circle as a square and solve for the
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area.Find the area of the square instead of the circle.3' x 3' = 9 sq. ft.Since
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circle is 78.5% of the square, multiply area of the square by 78.5% (or .785 if
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there is no percentage sign on the calculator).9 sq. ft. x .785 = 7.065 square
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feetMultiply area by the length to find the volume.7.065 x 12 = 84.78 cubic
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feet
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Where are spiral rebar ties used? - CORRECT ANSWERS ✔✔In round columns
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Control joints in sidewalks should be spaced at what intervals? - CORRECT
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ANSWERS ✔✔Equal to the width of the slab
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Explanation:
,Generally the control joints in sidewalks should be spaced equal to the width
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of the slab, but not more than 6 feet apart.
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One cubic foot of cement weighs approximately: - CORRECT ANSWERS ✔✔95
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lbs
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How many cubic yard of concrete is required for a 4" slab with the diameter
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of 15 feet? - CORRECT ANSWERS ✔✔2 ½ cubic yards
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Explanation:
Traditional MethodUse the following formula:Area of the circle = π x r x
|| || || || || || || || || || || ||
rWhere π = 3.14 and radius (r) = 7.5 feet (half of the diameter length)Area
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= 3.14 x 7.5 x 7.5Area = 176.625 sq. ft.Multiply area by the depth of the slab
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(in feet) to find the volume in cubic feet.176.625 x .333 = 58.82 cubic
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feetConvert cubic feet into cubic yards.58.82 ÷ 27 = 2.18 cubic yardsSince
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2.18 is not a given option, round up the number to 2.5 cubic yardsShortcut
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MethodThis problem can be solved using a much simpler method. First is to
|| || || || || || || || || || || || ||
find the area of the square, then convert it into the area of the circle by
|| || || || || || || || || || || || || || || ||
multiplying it by 78.5%.Area of the square = 15' x 15' = 225 square feetArea
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of the circle = 225 x .785 = 176.625 square feetDivide the volume by 81 to
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solve for the cubic yards for a 4" slab.176.625 ÷ 81 = 2.18 cubic yardsSince
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2.18 is not a given option, round up the number to 2.5 cubic yards
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The normal tolerance for the location of bends and ends of reinforcing bar is:
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- CORRECT ANSWERS ✔✔+/- 2 inches
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How many cubic yards of backfill are required for a 3' x 5' trench, 1500 ft
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long, with a 1 foot diameter pipe? - CORRECT ANSWERS ✔✔789.72
|| || || || || || || || || || ||
, Explanation:
Step 1. Find the net face area of the trench deducting for pipe.Face area
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including pipe: 3 x 5 = 15 square feetArea of the pipe: 𝐴=𝜋𝑟2A = 3.14 x .5 x
|| || || || || || || || || || || || || || || || || ||
.5A = 0.785Find the face area of the trench minus area of the pipe, which will
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give you the net area for the backfill.15 - 0.785 = 14.215Step 2. Find the total
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volume of the backfill.14.215 x 1500 = 21322.5 cubic feetConvert the volume
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into cubic yards.21322.5 ÷ 27 = 789.72 cubic yards
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When can the live load be calculated by multiplying the height, width and
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length of a pour and dividing by the deadload? - CORRECT ANSWERS
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✔✔Never
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Tensile strength in concrete is achieved by: - CORRECT ANSWERS ✔✔The use
|| || || || || || || || || || ||
of steel reinforcement.
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Refer to the house plan. What is the total cost for the foundation slab if the
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contractor charges $3.54 per square foot? - CORRECT ANSWERS
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✔✔$6524.90
||
Explanation:
The easiest way to solve for the area of the slab is to image a full rectangle of
|| || || || || || || || || || || || || || || || ||
the slab and subtract void areas from the area of the slab.
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Rectangle area: 28.167' x 71.5'= 2013.94 sq ftLeft void area: 6.667' x 1.83' =
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12.2 sq ftCenter void area: 11.5' x 1.83' = 21.045 sq ftRight void area: 9.167'
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x 15' = 137.505Net area of the foundation slab: 2013.94 - 12.2 - 21.045 -
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questions with answers
What is the volume of a cylinder if the diameter equals 3 feet and the length
|| || || || || || || || || || || || || || ||
equals to 12 feet? - CORRECT ANSWERS ✔✔84.78 cubic feet
|| || || || || || || || || ||
Explanation:
There are two ways to solve the problem. However, regardless of which
|| || || || || || || || || || ||
method is used, you need to first determine the area of the circle then
|| || || || || || || || || || || || || ||
multiply it by the length. Traditional Method Use the following formula:Area
|| || || || || || || || || || ||
of the circle = π x r x rWhere π = 3.14 and radius (r) = 1.5 feet (half of the
|| || || || || || || || || || || || || || || || || || || || ||
diameter length)Area = 3.14 x 1.5 x 1.5Area = 7.065 sq. ft.Multiply area by
|| || || || || || || || || || || || || ||
the length to find the volume.7.065 x 12 = 84.78Shortcut Method Area of the
|| || || || || || || || || || || || || ||
circle is 78.5% of the square. Treat the circle as a square and solve for the
|| || || || || || || || || || || || || || || ||
area.Find the area of the square instead of the circle.3' x 3' = 9 sq. ft.Since
|| || || || || || || || || || || || || || || ||
circle is 78.5% of the square, multiply area of the square by 78.5% (or .785 if
|| || || || || || || || || || || || || || || ||
there is no percentage sign on the calculator).9 sq. ft. x .785 = 7.065 square
|| || || || || || || || || || || || || || ||
feetMultiply area by the length to find the volume.7.065 x 12 = 84.78 cubic
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feet
||
Where are spiral rebar ties used? - CORRECT ANSWERS ✔✔In round columns
|| || || || || || || || || || ||
Control joints in sidewalks should be spaced at what intervals? - CORRECT
|| || || || || || || || || || ||
ANSWERS ✔✔Equal to the width of the slab
|| || || || || || || ||
Explanation:
,Generally the control joints in sidewalks should be spaced equal to the width
|| || || || || || || || || || || ||
of the slab, but not more than 6 feet apart.
|| || || || || || || || || ||
One cubic foot of cement weighs approximately: - CORRECT ANSWERS ✔✔95
|| || || || || || || || || ||
lbs
||
How many cubic yard of concrete is required for a 4" slab with the diameter
|| || || || || || || || || || || || || ||
of 15 feet? - CORRECT ANSWERS ✔✔2 ½ cubic yards
|| || || || || || || || || ||
Explanation:
Traditional MethodUse the following formula:Area of the circle = π x r x
|| || || || || || || || || || || ||
rWhere π = 3.14 and radius (r) = 7.5 feet (half of the diameter length)Area
|| || || || || || || || || || || || || || ||
= 3.14 x 7.5 x 7.5Area = 176.625 sq. ft.Multiply area by the depth of the slab
|| || || || || || || || || || || || || || || || ||
(in feet) to find the volume in cubic feet.176.625 x .333 = 58.82 cubic
|| || || || || || || || || || || || || ||
feetConvert cubic feet into cubic yards.58.82 ÷ 27 = 2.18 cubic yardsSince
|| || || || || || || || || || || ||
2.18 is not a given option, round up the number to 2.5 cubic yardsShortcut
|| || || || || || || || || || || || || ||
MethodThis problem can be solved using a much simpler method. First is to
|| || || || || || || || || || || || ||
find the area of the square, then convert it into the area of the circle by
|| || || || || || || || || || || || || || || ||
multiplying it by 78.5%.Area of the square = 15' x 15' = 225 square feetArea
|| || || || || || || || || || || || || || ||
of the circle = 225 x .785 = 176.625 square feetDivide the volume by 81 to
|| || || || || || || || || || || || || || || ||
solve for the cubic yards for a 4" slab.176.625 ÷ 81 = 2.18 cubic yardsSince
|| || || || || || || || || || || || || || ||
2.18 is not a given option, round up the number to 2.5 cubic yards
|| || || || || || || || || || || || || ||
The normal tolerance for the location of bends and ends of reinforcing bar is:
|| || || || || || || || || || || || ||
- CORRECT ANSWERS ✔✔+/- 2 inches
|| || || || || ||
How many cubic yards of backfill are required for a 3' x 5' trench, 1500 ft
|| || || || || || || || || || || || || || ||
long, with a 1 foot diameter pipe? - CORRECT ANSWERS ✔✔789.72
|| || || || || || || || || || ||
, Explanation:
Step 1. Find the net face area of the trench deducting for pipe.Face area
|| || || || || || || || || || || || ||
including pipe: 3 x 5 = 15 square feetArea of the pipe: 𝐴=𝜋𝑟2A = 3.14 x .5 x
|| || || || || || || || || || || || || || || || || ||
.5A = 0.785Find the face area of the trench minus area of the pipe, which will
|| || || || || || || || || || || || || || || ||
give you the net area for the backfill.15 - 0.785 = 14.215Step 2. Find the total
|| || || || || || || || || || || || || || || ||
volume of the backfill.14.215 x 1500 = 21322.5 cubic feetConvert the volume
|| || || || || || || || || || || ||
into cubic yards.21322.5 ÷ 27 = 789.72 cubic yards
|| || || || || || || || ||
When can the live load be calculated by multiplying the height, width and
|| || || || || || || || || || || ||
length of a pour and dividing by the deadload? - CORRECT ANSWERS
|| || || || || || || || || || || ||
✔✔Never
||
Tensile strength in concrete is achieved by: - CORRECT ANSWERS ✔✔The use
|| || || || || || || || || || ||
of steel reinforcement.
|| || ||
Refer to the house plan. What is the total cost for the foundation slab if the
|| || || || || || || || || || || || || || ||
contractor charges $3.54 per square foot? - CORRECT ANSWERS
|| || || || || || || || ||
✔✔$6524.90
||
Explanation:
The easiest way to solve for the area of the slab is to image a full rectangle of
|| || || || || || || || || || || || || || || || ||
the slab and subtract void areas from the area of the slab.
|| || || || || || || || || || || ||
Rectangle area: 28.167' x 71.5'= 2013.94 sq ftLeft void area: 6.667' x 1.83' =
|| || || || || || || || || || || || ||
12.2 sq ftCenter void area: 11.5' x 1.83' = 21.045 sq ftRight void area: 9.167'
|| || || || || || || || || || || || || || ||
x 15' = 137.505Net area of the foundation slab: 2013.94 - 12.2 - 21.045 -
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