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GNRS 613 (GNRS613) : Graduate Statistics Midterm Exam_ Answered Fall 2025/2026.

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GNRS 613 (GNRS613) : Graduate Statistics Midterm Exam_ Answered Fall 2025/2026. Azusa Pacific University.










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May 16, 2025
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GNRS 613: Graduate Statistics

Midterm Exam

Hint: Please review z scores.....note that a score needs to be +/- 2 sd from the mean (or

+/- a z score of 2) to be considered significant. There are a few questions on the exam

related to this. I would like for you to work out the answers first.




Please answer each of the following questions.

1. For the data below, tell me the mean, median, mode, and standard deviation.

The Data:

102.5, 104.5, 100.4, 95.9, 87, 95, 88.6, 89.2, 78.9, 84.6, 81.7, 72.2, 65.1, 68.1, 67.3, 52.5

The number of observations is 16

i. Mean = (102.5 + 104.5 + 100.4 + 95.9 + 87 + 95 + 88.6 + 89.2 + 78.9 + 84.6

+ 81.7 + 72.2 + 65.1+ 68.1 + 67.3 + 52.5)/16 = 83.34375

ii. Median = (84.6+87)/2 = 85.8

iii. Mode = There is no mode amongst the given numbers

iv. Standard deviation

The formulae for calculating variance =




Substituting the values:

Variance = 212.2774609

, Name:

Standard deviation = √ variance

= √ 212.2774609

= 14.5697

2. For the data below, tell me the mean, median, mode, and standard deviation.

25, 24, 26, 31, 35, 38, 26, 24, 27, 26, 34, 36, 33, 31, 30

In this second question, we can use excel to solve it:

i. Mean = 29.73333

ii. Mode = 26

iii. Median = 30

iv. Standard deviation = 4.667007

For the three questions below…..think z scores and the area under the curve.

3. A nursing professor was curious as to whether the students in a very large

class she was teaching who turned in their tests first scored differently from

the overall mean on the test. The overall mean score on the test was 75 with

a standard deviation of 10; the scores were approximately normally

distributed. The mean score for the first 20 tests was 78. Did the students

turning in their tests first score significantly different from the mean?

Explain.

Overall mean = 75

The standard deviation = 10

The mean score for the first 20 tests was 78

We are testing the mean of the first 20 tests, whether it is significantly different from the

overall mean of the tests.

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