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Solution Manual for Finite Mathematics and Its Applications (13th Edition) – Larry J. Goldstein – Full Solutions (Chapters 1–12)

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Solution Manual for Finite Mathematics and Its Applications (13th Edition) – Larry J. Goldstein – Full Solutions (Chapters 1–12) Solution Manual for Finite Mathematics and Its Applications (13th Edition) – Larry J. Goldstein – Full Solutions (Chapters 1–12) Solution Manual for Finite Mathematics and Its Applications (13th Edition) – Larry J. Goldstein – Full Solutions (Chapters 1–12) Solution Manual for Finite Mathematics and Its Applications (13th Edition) – Larry J. Goldstein – Full Solutions (Chapters 1–12)

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Solution Manual For Finite Mathematics And Its App
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Solution manual for finite mathematics and its app











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Institution
Solution manual for finite mathematics and its app
Course
Solution manual for finite mathematics and its app

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Uploaded on
May 10, 2025
Number of pages
557
Written in
2024/2025
Type
Exam (elaborations)
Contains
Questions & answers

Content preview

SOLUTION MANUAL r




Finite Mathematics & Its Applications
r r r r




13th Edition by Larry J. Goldstein,
r r r r r




Chapters 1 - 12, Complete
r r r r

, Contents
Chapter 1: Linear Equations and Straight Lines
r r r r r 1–1

Chapter 2: Matrices
r 2–1

Chapter 3: Linear Programming, A Geometric Approach
r r r r r 3–1

Chapter 4: The Simplex Method
r r r 4–1

Chapter 5: Sets and Counting
r r r 5–1

Chapter 6: Probability
r 6–1

Chapter 7: Probability and Statistics
r r r 7–1

Chapter 8: Markov Processes
r r 8–1

Chapter 9: The Theory of Games
r r r r 9–1

Chapter10: The Mathematics of Finance
r r r r 10–1

Chapter 11: Logic
r 11–1

Chapter 12: Difference Equations and MathematicalModels
r r r r r 12–1

, Chapter 1
r




Exercises 1.1 5
r

6. Left 1, down
r r r r




2
1. Right 2, up 3
r r r
y
y



(2, 3)
r



x
x
( –1, –52 r r )
r




7. Left 20, up 40
r r r r


2. Left 1, up 4
r r r
y
y

(–20, 40) r

(–1, 4) r




x
x




8. Right 25, up 30
r r r r


3. Down 2
r r
y
y


(25, 30) r




x
x
(0, –2) r




9. Point Q is 2 units to the left and 2 units up or
r r r r r r r r r r r r


4. Right 2 r



y (—2,2). r




10. Point P is 3 units to the right and 2 units down or
r r r r r r r r r r r r




(3,—2).
x
(2, 0)
r
1 r



11. —2(1)+ (3) =—2+1=—1so yes the point is r r r r r r r r r r r




3
on the line. r r




5. Left 2, up 1 1 r



12. —2(2)+ (6) =—1is false, so no the point is not
r r r
r r r r r r r r r r r r

y
3
on the line r r




(–2, 1) r

x



Copyright © 2023 Pearson Education, Inc.
r r r r r 1-1

, Chapter 1: Linear Equations and Straight Lines
r r r r r r ISM: Finite Math
r r




1 r
24. 0 = 5
r r r




13 —2x + y =—1 Substitute the x and y r r r r r r r r r
no solution r


3
. x-intercept: none r


coordinates of the point into the equation: r r r r r r



f 1 hı f h When x = 0, y = 5y-
' ,3 →—2 ' 1 ı +1(3)=—1→—1+1=—1 is
r r r r r r r r
r
r r


intercept: (0, 5)
y' ı 'y ıJ
r r r r r r r r r r
r r


r

2 J 2 3 rr r r




a false statement. So no the point is not on
r r r r r r r r r 25. When y = 0, x = 7 x-
r r r r r r r r




theline.
r r intercept: (7, 0) 0 r r r




f 1h f1 h =7 r r




14 —2 ' ı + ' ı (—1)=—1 is true so yes the point is no solution
.
r r r r r r r r r r




'y3 ıJ 'y3 ıJ y-intercept:none r


r rr




on the line. r r
26. 0 = –8x
r r r




15. m = 5, b = 8 r r r r r r
x=0 r r




x-intercept: (0, 0) r r




16. m = –2 and b = –6
r r r r r r r
y = –8(0) r r




y=0 r r




17. y = 0x + 3; m = 0, b = 3
r r r r r r r r r r r
y-intercept: (0, 0) r r




2 2 1 r




y = x+0; m = , b=0
r r

27 0 = x –1 r r r r


18 r r r r r r r r r r

3
3 3 .
. x =3 r r




19. 14x+7y =21 r r r r r r
x-intercept: (3, 0) r r




1 r



7y =—14x+21 r r r r r
y = (0) –1 r r r r



3
y =—2x +3
y = –1
r r r r

r r




y-intercept: (0, –1) r r


20 x— y =3 r r r r
y
. —y =—x+3 r r r r




y = x— 3 r r r r




(3, 0)
x
r


21. 3x =5
rr r r r




5 (0, –1) r


x= r r




3
1 2
28. When x = 0, y = 0.
– x+ y =1 0
r r r r r r



22 2
r


3
r r


When x = 1, y = 2.
. r r r r r r




2 r 1 r y
y = x+10 r r r




3 2
3 r


y = x +15 r r r
(1, 2) r


4 x
(0, 0) r




23. 0 =—4x +8 r r r r




4x = 8 r r




x =2 r r




x-intercept: (2, 0) r r




y = –4(0) + 8
r r r r




y=8 r r




y-intercept: (0, 8) r r




1-2 Copyright © 2023 Pearson Education, Inc. r r r r r
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