A Level Maths AQA question with
answers
Straight line equation formula - -y-y1 = m(x-x1)
-Perpendicular straight lines - -m1 x m2 = -1
-Log(a)b=c - -a^c=b
-Log(10)x + Log(10)y = - -Log(10)xy
-Log(10)x - Log(10)y = - -Log(10)x/y
-kLog(10)x = - -Log(10)x^k
-Displacement dy/dx = - -Velocity
-Velocity dy/dx = - -Acceleration
-Cos^2A + Sin^2A= - -1
-1 + Tan^2A = - -Sec^2A
-1 + Cot^2A = - -Cosec^2A
-2SinAcosA = - -Sin2A
-Cos^2A - Sin^2A = - -Cos2A
-(2tanA)/(1-tan^2A) = - -Tan2A
-A^x A^y = - -A^xy
-A^x / A^y = - -A^x-y
-(A^x)^y - -a^xy
-Arc Length (radians) = - -rθ
-Sector Area (radians) = - -1/2 r^2 θ
-x^n dy/dx = - -nx^(n-1)
-Sinkx dy/dx = - -kCoskx
-Coskx dy/dx = - --kSinkx
answers
Straight line equation formula - -y-y1 = m(x-x1)
-Perpendicular straight lines - -m1 x m2 = -1
-Log(a)b=c - -a^c=b
-Log(10)x + Log(10)y = - -Log(10)xy
-Log(10)x - Log(10)y = - -Log(10)x/y
-kLog(10)x = - -Log(10)x^k
-Displacement dy/dx = - -Velocity
-Velocity dy/dx = - -Acceleration
-Cos^2A + Sin^2A= - -1
-1 + Tan^2A = - -Sec^2A
-1 + Cot^2A = - -Cosec^2A
-2SinAcosA = - -Sin2A
-Cos^2A - Sin^2A = - -Cos2A
-(2tanA)/(1-tan^2A) = - -Tan2A
-A^x A^y = - -A^xy
-A^x / A^y = - -A^x-y
-(A^x)^y - -a^xy
-Arc Length (radians) = - -rθ
-Sector Area (radians) = - -1/2 r^2 θ
-x^n dy/dx = - -nx^(n-1)
-Sinkx dy/dx = - -kCoskx
-Coskx dy/dx = - --kSinkx
