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Solution Manual for First Course in Machine Learning 2nd Edition Exercise Solutions by Simon Rogers and Nark Girolami

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Solution Manual for First Course in Machine Learning 2nd Edition Exercise Solutions by Simon Rogers and Nark GirolamiSolution Manual for First Course in Machine Learning 2nd Edition Exercise Solutions by Simon Rogers and Nark Girolami

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Institution
A FIRST COURSE IN MACHINE LEARNING
Course
A FIRST COURSE IN MACHINE LEARNING











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Written for

Institution
A FIRST COURSE IN MACHINE LEARNING
Course
A FIRST COURSE IN MACHINE LEARNING

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Uploaded on
April 23, 2025
Number of pages
69
Written in
2024/2025
Type
Exam (elaborations)
Contains
Questions & answers

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Solution Manual for First Course
in Machine Learning 2nd Edition
Exercise Solutions by Simon
Rogers and Nark Girolami

,SOLUTIONS MANUAL FOR
N N




A First Course In
N N N N




Machine Learning N N




(2Nd Edition) Exe
N N




rcise SolutionsN




by
Simon Rogers andMark
N N N N




Girolami




BocaNRatonN LondonN NewNYork

CRCNPressNisNanNimprintNofNthe
TaylorN&NFrancisNGroup,NanNinformaNbusiness

,CRCNPress
TaylorN&NFrancisNGroup
6000N BrokenN SoundN ParkwayN NW,N SuiteN 300N
BocaNRaton,NFLN33487-2742
©N2017NbyNTaylorN&NFrancisNGroup,NLLC
CRCNPressNisNanNimprintNofNTaylorN&NFrancisNGroup,NanNInformaNbu

sinessNNoNclaimNtoNoriginalNU.S.NGovernmentNworks

PrintedN onN acid-
freeN paperNVersionNDate:N
20160404

InternationalN StandardN BookN Number-13:N 978-1-4987-3859-0N (Ancillary)

ThisNbookNcontainsNinformationNobtainedNfromNauthenticNandNhighlyNregardedNsources.NReasonableNeffortsNhaveNbeenNmadeNtoNpublishNreliableN
dataNandNinformation,NbutNtheNauthorNandNpublisherNcannotNassumeNresponsibilityNforNtheNvalidityNofNallNmaterialsNorNtheNconsequencesNofNthei
rNuse.NTheNauthorsNandNpublishersN haveN attemptedN toN traceN theN copyrightN holdersN ofN allN materialN reproducedN inN thisN publicationN andN apologi
zeN toN copyrightN holdersN ifN permissionNtoNpublishNinNthisNformNhasNnotNbeenNobtained.NIfNanyNcopyrightNmaterialNhasNnotNbeenNacknowledgedNp
leaseNwriteNandNletNusNknowNsoNweNmayNrectifyNinNanyNfutureNreprint.

ExceptNasNpermittedNunderNU.S.NCopyrightNLaw,NnoNpartNofNthisNbookNmayNbeNreprinted,Nreproduced,Ntransmitted,NorNutilizedNinNanyNformNby
NanyNelectronic,Nmechanical,NorN otherNmeans,NnowNknownNor NhereafterNinvented,N includingNphotocopying,N microfilming,NandNrecording, N orNin Nan
yNinformationNstorageNorNretrieval Nsystem,NwithoutNwrittenNpermissionNfromNtheNpublishers.

ForN permissionN toN photocopyN orN useN materialN electronicallyN fromN thisN work,N pleaseN accessN www.copyright.comN (http://www.copyright.com/)N
orN contactNtheNCopyrightNClearanceNCenter,NInc.N(CCC),N222NRosewoodNDrive,NDanvers,NMAN01923,N978-750-8400.NCCCNisNaNnot-for-
profitNorganizationNthatNprovidesNlicensesNandNregistrationNforNaNvarietyNofNusers.NForNorganizationsNthatNhaveNbeenNgrantedNaNphotocopyNlicens
eNbyNtheNCCC,NaNseparateNsystemNofNpaymentNhasNbeenNarranged.

TrademarkN Notice:N ProductN orN corporateN namesN mayN beN trademarksN orN registeredN trademarks,N andN areN usedN onlyN forN identificationN andN e
xplanationNwithoutNintentNtoNinfringe.
VisitN theN TaylorN &N FrancisN WebN si
teN atNhttp://www.taylorandfrancis.c
om
andN theN CRCN PressN WebN sit
eN atNhttp://www.crcpress.co
m

, Chapter 1 N




EXN 1.1.N AN highN positiveN valueN ofN w0N andN aN smallN negativeN valueN forN w1.N TheseN reflec
tN theNhighN interceptN onN theN tN axisN (correspondingN toN theN theoreticalN timeN winnin
gN timeN atNxN=N0N andN theN smallN decreseN inN winningN timeN overN theN years.


EXN1.2.N TheN followingN wouldN doNtheNjob:

1 %NAttributesNareNstoredNinNNx1NvectorNx
2 %NTargetsNareNstoredNinNNx1NvectorNtNxbN
3 =Nmean(x);
4 tbN=Nmean(t);
5 x2bN=Nmean(x.*x);N
6 xtbN=Nmean(x.*t);
7 w1N =N (xtbN−Nxt*xb)/(x2b−xbˆ2);
8 w0N=Ntb−w1*xb;
9 %NPlotNtheNdataNplot(x,t,'b.','marke
10 rsize',25);
11 %NPlotNtheNmodelNh
12 oldNon;
13 plot(x,w0+w1*x,'r','linewidth',2);




EXN 1.3.N WeN needN toN findN wTXTXw.N We’llN startN withN XTX.N MultiplyingN XTN byN XNgives:

N
ΣN ΣN
T 2
x n1
n=1NN n=1 xn1xn2
XN XN= ΣN ΣN
n=1
xn2 xn1 x2n2
n=1NNN



MultiplyingN thisN byN wN gives:

Σ Σ
T w0 N N 2N +Nw N
1 xn1xn2
n=1 xn1
Σ N N n=1
w0 n=1 xn2 xn1 1+Nw Σ x
N 2
XN XwN= n=1NNN n2

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